Modify a cell value if two other cells contain certain value

zack8576

Active Member
Joined
Dec 27, 2021
Messages
271
Office Version
  1. 365
Platform
  1. Windows
I need to modify some excel files, if column K contains "AO", "COVER", and column N contains "Tampa"
then any "Riser", "Cone", 'Top slab" (column K) with the same item label (column B) gets the letter J at the end of the value in column D
so in the screenshot below, rows 2 and 3 will be: F14632J and F14824J

I have a partially working code that does exactly this if N contains Tampa, how do I modify my code to have it look for AO COVER in column K ?


1672955363151.png


VBA Code:
Sub CityOfTampa()
    Dim c As Variant
    For Each c In Range("N2:N" & Cells(Rows.Count, 1).End(3).Row)
        If c Like "*Tampa*" Or _
           c Like "*Tampa*" Then Tampa = c.Offset(, -9)
        For Each d In Range("K2:K" & Cells(Rows.Count, 1).End(3).Row)
            If d Like "*4'*" And d Like "*Riser*" Or _
               d Like "*4'*" And d Like "*Top Slab*" Or _
               d Like "*4'*" And d Like "*Cone*" Or _
               d Like "*5'*" And d Like "*Cone*" Then
                If d.Offset(, 3) Like "*Tampa*" Then
                    If Right(d.Offset(, -7), 1) <> "J" Then
                        d.Offset(, -7) = d.Offset(, -7) & "J"
                    End If
                End If
            End If
        Next d
    Next c
End Sub
 

Attachments

  • 1672954906257.png
    1672954906257.png
    197.5 KB · Views: 15
No.
Dictionary's only add value if there is an exact match and your example is all based on if statements using partial matches (wildcards).
In the original problem we were finding a description with AO COVER. The dictionary did not help with finding AO COVER.
What it helped with was the next stage. The row with AO COVER had a Type in Column B. We wanted to capture that type in the dictionary so that we could then loop through the rows a second time and further process any row that had that same type by checking the type for each row to see if we held it in the dictionary.
Okay, thank you. The long block of code is working just fine right. I just wanted to see if there is a way to code it shorter. I will leave it the way it is for now . :)
 
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