Formulas to count including Unique Numbers

[Graham C1600]

Hi,

I've tried this before but ended up going around in circles because i was not asking the right questions. Hopefully the below will clear all this up.

[TABLE="width: 507"]
<colgroup><col><col><col><col span="3"></colgroup><tbody>[TR]
[TD]User ID[/TD]
[TD]Name[/TD]
[TD]Last Logon[/TD]
[TD]UTC[/TD]
[TD]Model[/TD]
[TD]Type[/TD]
[/TR]
[TR]
[TD]1[/TD]
[TD]Gary[/TD]
[TD]01/01/2019[/TD]
[TD]No[/TD]
[TD]AD[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]1[/TD]
[TD]Stephen[/TD]
[TD]02/01/2019[/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]1[/TD]
[TD]Brian[/TD]
[TD][/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]2[/TD]
[TD]Graham[/TD]
[TD]05/03/2019[/TD]
[TD]Yes[/TD]
[TD]REL[/TD]
[TD]SIM[/TD]
[/TR]
[TR]
[TD]3[/TD]
[TD]Steve[/TD]
[TD][/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]4[/TD]
[TD]Clare[/TD]
[TD]06/05/2019[/TD]
[TD]Yes[/TD]
[TD]REL[/TD]
[TD]SIM[/TD]
[/TR]
[TR]
[TD]4[/TD]
[TD]Trev[/TD]
[TD][/TD]
[TD]Yes[/TD]
[TD]AD[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]5[/TD]
[TD]Simon[/TD]
[TD]03/03/2018[/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]6[/TD]
[TD]Rich[/TD]
[TD][/TD]
[TD]No[/TD]
[TD]AD[/TD]
[TD]SIM[/TD]
[/TR]
[TR]
[TD]7[/TD]
[TD]Darren[/TD]
[TD]05/06/2019[/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]8[/TD]
[TD]John[/TD]
[TD]01/04/2018[/TD]
[TD]No[/TD]
[TD]AD[/TD]
[TD]SIM[/TD]
[/TR]
[TR]
[TD]8[/TD]
[TD]Andrew[/TD]
[TD][/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]SIM[/TD]
[/TR]
[TR]
[TD]9[/TD]
[TD]Oliver[/TD]
[TD][/TD]
[TD]Yes[/TD]
[TD]REL[/TD]
[TD]SIM
[/TD]
[/TR]
</tbody>[/TABLE]

So work on the assumption that the User ID's is Column A and so on. So the formulas I need will be going into Column G and beyond.

1^st query. How many unique User ID’s are there with the following criteria – There is text in the Last Logon field and also the UTC is=”No”. So in this example the answer would be 3. This is User ID 1,5 & 8.
2^nd query. As above but I now need to see how many unique User ID’s there are with the following criteria – The Last Logon field is blank and the UTC is =”No”. The important part with this one is that all of the same User ID’s must meet this requirement. So for instance User ID 1, Brian has not logged on and his UTC is “No”. But Gary and Stephen have logged on so this User id is not to be counted. So using this method the answer would be 2. This would be Rich and Steve.
3^rd query. I need to count the total amount of User ID’s where at least 1 person has data in the Last logged on field and the UTC = “No”. This is not unique and I need a total. In this case it would be 5 (Gary, Stephen, John, Darren, Simon)
4^th query. I need to count the total amount of User ID’s where at least 1 person has data in their Last Logon box and the UTC =”No”. This count needs to be User ID’s that are the same for instance John has met this criteria but we also need to include Andrew in the count because he has the same User ID. So in this scenario the count would be 7 (Gary, Stephen, Brian, Simon, Darren, John, Andrew)
4^th query. I need to count the total amount of User ID’s where there is no data in the Last Logon Field and the UTC=”No”. This count needs to be similar to the 2^nd query in that if there is a User ID that meets this requirement and another person with the same User ID does not meet the requirement then we need to disregard these users. So in this query the answer would be 2.
5^th query. I need to count the how many Unique User ID’s there are that meet the following criteria – UTC=”No” –Model =”AD” Type=”SIM”. In this case the answer is 2 (Rich & John)
6^th query. I need to count the total of User ID’s that meet the following criteria – UTC=”No” Model=”REL” Type=”COL”. In this case the answer is 5 (Stephen, Steve, Brian,Simon,Darren)
7^th query. I need to count the total of User ID’s that meet this criteria – UTC=”No” Model=”REL” Type=”COL” and also where there is data in the Last Logon field. So in this scenario the count would be 3 (Stephen, Simon , Darren)

Thanks in advance.

 

[Marcelo Branco]

What's the difference from the 2nd query? They look identical ...

M.

 

[Graham C1600]

Hi M,

Probably a bad example but he slight difference here is query 2 gave me a number of unique User ID's base on the criteria. This time i need to count all the user ID's that meet the criteria.

So query 2 result is 2 and they are Steve & Rich.

This time the answer is also 2 and again it's Steve & Rich.

However if I added another user under User id 3 with no logon data and UTC = "No" then this answer would be 3 but query 2 would still be 2 as query 2 was unique User ID's.

Thanks

 

[Marcelo Branco]

Try

Array formula
=SUM(IF(A2:A14<>"",--ISNA(MATCH(A2:A14,IF((C2:C14<>"")+(D2:D14="Yes"),A2:A14),0))))
Ctrl+Shift+Enter

M.

 

[Graham C1600]

Hi M,

Works a treat.

 

[Graham C1600]

[TABLE="width: 64"]
<colgroup><col width="64" style="width:48pt"> </colgroup><tbody>[TR]
[TD="width: 64"][TABLE="width: 602"]
<tbody>[TR]
[TD]Next I would like to count the Unique User ID's based on the following criteria - Type="COL", Model=Rel",UTC="No". So in this case the number would be 4. User ID's 1,3,5,7.
[/TD]
[/TR]
[TR]
[TD]Then based on this information (

Type="COL", Model=Rel",UTC="No")​

I need to count the total number of users. This would be 5 (Stephen, Brian,Steve,Simon & Darren)
[/TD]
[/TR]
</tbody>[/TABLE]
<strike></strike>
[/TD]
[/TR]
[TR]
[TD][/TD]
[/TR]
</tbody>[/TABLE]

 

[Marcelo Branco]

First
Array formula
=SUM(IF(FREQUENCY(IF($D$2:$D$14="NO",IF(E2:E14="REL",IF(F2:F14="COL",MATCH(A2:A14,A2:A14,0)))),ROW(A2:A14)-ROW(A2)+1),1))
Ctr+Shift+Enter

Second
Regular formula
=COUNTIFS(D2:D14,"No",E2:E14,"REL",F2:F14,"COL")

M.

 

[Graham C1600]

Thanks M, all working great.

If i wanted to add another ask in the second regular formula to look down the Last Logon and then count all users, where would the additional C2:C15,<>"" go as i tried to add it but keep getting errors.

=COUNTIFS(D2:D14,"No",E2:E14,"REL",F2:F14,"COL")​

Thanks.

 

[Marcelo Branco]

=COUNTIFS(C2:C14,"<>",D2:D14,"No",E2:E14,"REL",F2:F14,"COL")

M.

 

[Graham C1600]

Thanks M these are working great. I've tried them on the full data set and get exactly what i need.

 

[Graham C1600]

2nd query

Array formula
=SUM(IF(FREQUENCY(IF(ISNA(MATCH(A2:A14,IF((C2:C14<>"")+(D2:D14="Yes"),A2:A14),0)),MATCH(A2:A14,A2:A14,0)),ROW(A2:A14)-ROW(A2)+1),1))
Ctrl+Shift+Enter

Does it work for you?

M.

M,

Is it possible to tweak the above formula to provide a list instead of just a number ? So say I put the formula in M1 it would list in M1, M2 etc,, the results of the query ?

Thanks