Formulas to count including Unique Numbers

[Graham C1600]

Hi,

I've tried this before but ended up going around in circles because i was not asking the right questions. Hopefully the below will clear all this up.

[TABLE="width: 507"]
<colgroup><col><col><col><col span="3"></colgroup><tbody>[TR]
[TD]User ID[/TD]
[TD]Name[/TD]
[TD]Last Logon[/TD]
[TD]UTC[/TD]
[TD]Model[/TD]
[TD]Type[/TD]
[/TR]
[TR]
[TD]1[/TD]
[TD]Gary[/TD]
[TD]01/01/2019[/TD]
[TD]No[/TD]
[TD]AD[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]1[/TD]
[TD]Stephen[/TD]
[TD]02/01/2019[/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]1[/TD]
[TD]Brian[/TD]
[TD][/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]2[/TD]
[TD]Graham[/TD]
[TD]05/03/2019[/TD]
[TD]Yes[/TD]
[TD]REL[/TD]
[TD]SIM[/TD]
[/TR]
[TR]
[TD]3[/TD]
[TD]Steve[/TD]
[TD][/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]4[/TD]
[TD]Clare[/TD]
[TD]06/05/2019[/TD]
[TD]Yes[/TD]
[TD]REL[/TD]
[TD]SIM[/TD]
[/TR]
[TR]
[TD]4[/TD]
[TD]Trev[/TD]
[TD][/TD]
[TD]Yes[/TD]
[TD]AD[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]5[/TD]
[TD]Simon[/TD]
[TD]03/03/2018[/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]6[/TD]
[TD]Rich[/TD]
[TD][/TD]
[TD]No[/TD]
[TD]AD[/TD]
[TD]SIM[/TD]
[/TR]
[TR]
[TD]7[/TD]
[TD]Darren[/TD]
[TD]05/06/2019[/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]COL[/TD]
[/TR]
[TR]
[TD]8[/TD]
[TD]John[/TD]
[TD]01/04/2018[/TD]
[TD]No[/TD]
[TD]AD[/TD]
[TD]SIM[/TD]
[/TR]
[TR]
[TD]8[/TD]
[TD]Andrew[/TD]
[TD][/TD]
[TD]No[/TD]
[TD]REL[/TD]
[TD]SIM[/TD]
[/TR]
[TR]
[TD]9[/TD]
[TD]Oliver[/TD]
[TD][/TD]
[TD]Yes[/TD]
[TD]REL[/TD]
[TD]SIM
[/TD]
[/TR]
</tbody>[/TABLE]

So work on the assumption that the User ID's is Column A and so on. So the formulas I need will be going into Column G and beyond.

1^st query. How many unique User ID’s are there with the following criteria – There is text in the Last Logon field and also the UTC is=”No”. So in this example the answer would be 3. This is User ID 1,5 & 8.
2^nd query. As above but I now need to see how many unique User ID’s there are with the following criteria – The Last Logon field is blank and the UTC is =”No”. The important part with this one is that all of the same User ID’s must meet this requirement. So for instance User ID 1, Brian has not logged on and his UTC is “No”. But Gary and Stephen have logged on so this User id is not to be counted. So using this method the answer would be 2. This would be Rich and Steve.
3^rd query. I need to count the total amount of User ID’s where at least 1 person has data in the Last logged on field and the UTC = “No”. This is not unique and I need a total. In this case it would be 5 (Gary, Stephen, John, Darren, Simon)
4^th query. I need to count the total amount of User ID’s where at least 1 person has data in their Last Logon box and the UTC =”No”. This count needs to be User ID’s that are the same for instance John has met this criteria but we also need to include Andrew in the count because he has the same User ID. So in this scenario the count would be 7 (Gary, Stephen, Brian, Simon, Darren, John, Andrew)
4^th query. I need to count the total amount of User ID’s where there is no data in the Last Logon Field and the UTC=”No”. This count needs to be similar to the 2^nd query in that if there is a User ID that meets this requirement and another person with the same User ID does not meet the requirement then we need to disregard these users. So in this query the answer would be 2.
5^th query. I need to count the how many Unique User ID’s there are that meet the following criteria – UTC=”No” –Model =”AD” Type=”SIM”. In this case the answer is 2 (Rich & John)
6^th query. I need to count the total of User ID’s that meet the following criteria – UTC=”No” Model=”REL” Type=”COL”. In this case the answer is 5 (Stephen, Steve, Brian,Simon,Darren)
7^th query. I need to count the total of User ID’s that meet this criteria – UTC=”No” Model=”REL” Type=”COL” and also where there is data in the Last Logon field. So in this scenario the count would be 3 (Stephen, Simon , Darren)

Thanks in advance.

 

[DanteAmor]

@Marcelo Branco and I answered your last request and we had doubts, because your rules were not clear.


If you created another thread, you could at least notify and thank the commitment shown towards your solution.

 

[Marcelo Branco]

Still confusing - as in the previous thread ...

1st query
Shouldn't the result be 4? Users 1, 5, 7 and 8

M.

 

[Graham C1600]

Hi Dante,

Apologies, will go and do that now.

I appreciate all the help that was given.

Thanks

 

[Graham C1600]

Hi Marcelo,

As for Dante, thanks for support so far.

Thanks for pointing out that the answer should be 4 and not 3. I looked at the wrong table when i worked out the answer.

Thanks

 

[Marcelo Branco]

Let's do it by steps

1st query
Array formula
=SUM(IF(FREQUENCY(IF(C2:C14<>"",IF(D2:D14="No",MATCH(A2:A14,A2:A14,0))),ROW(A2:A14)-ROW(A2)+1),1))
confirmed with Ctrl+Shift+Enter, not just Enter

Does it work for you?

M.

 

[Graham C1600]

Thanks M. Works a treat.

 

[Marcelo Branco]

2nd query

Array formula
=SUM(IF(FREQUENCY(IF(ISNA(MATCH(A2:A14,IF((C2:C14<>"")+(D2:D14="Yes"),A2:A14),0)),MATCH(A2:A14,A2:A14,0)),ROW(A2:A14)-ROW(A2)+1),1))
Ctrl+Shift+Enter

Does it work for you?

M.

 

[Graham C1600]

Thanks again M, works fine.

 

[Marcelo Branco]

3rd query
Shouldn't the result be 6? Gary, Stephen, Brian, Simon, Darren and John
Brian has not logon date, but Gary and Stephen (same ID) have. Shouldn't Brian be counted too?

M.