Extract Only Numbers From Text String

[mgirvin]

Dear Smartest Excelers Around,

Is there a one cell formula that could take this string in cell A1:

45t*&65/

and extract only the numbers and deliver this

4565

to a single cell?

The formula would have to be able to deal with all 255 ASCII characters and be copied down a column.

 

[Ron Coderre]

With
A1: 91.28ABC37.1D2F465
B1: 2

This variation of the array formula I posted returns embedded numbers
that can contain decimal values:

C1: =LOOKUP(10^99,--MID("|"&A1,SMALL(IF(((--ISNUMBER(--("0"&MID("|"&A1,
ROW($1:$25),1)))=0)*ISNUMBER(--(MID("|"&A1,ROW($2:$26),1)))),ROW($2:$26)),B1),
ROW($1:$25)))

In the above example, the formula returns the second embedded number:
37.1

 

[pto160]

This is going to work fantastic with embedded numbers, for example inventory parts. I will definitely use it for that.
The first array formula works with non-embedded numbers.
If the first number is 100.59, and you put in 1 for the position, it picks up 100.59, but if you put in 2, it picks up 59. The way around this is to go up by increments of two. But some numbers will be 464 and not 464.00, so the 3rd number will pick up the two digits after the decimal point.

Sheet3

<table style="background-color: rgb(255, 255, 255); padding-left: 2pt; padding-right: 2pt; font-family: Arial,Arial; font-size: 10pt;" border="1" cellpadding="0" cellspacing="0"> <colgroup> <col style="width: 30px; font-weight: bold;"> <col style="width: 235px;"> <col style="width: 254px;"> <col style="width: 88px;"></colgroup> <tbody> <tr style="text-align: center; background-color: rgb(202, 202, 202); font-size: 8pt; font-weight: bold;"> <td> </td> <td>A</td> <td>B</td> <td>C</td></tr> <tr style="height: 17px;"> <td style="text-align: center; background-color: rgb(202, 202, 202); font-size: 8pt;">3</td> <td> </td> <td>Formula</td> <td>Number of n</td></tr> <tr style="height: 17px;"> <td style="text-align: center; background-color: rgb(202, 202, 202); font-size: 8pt;">4</td> <td>464.59 DDFSDF 23.25 ccd 157.25</td> <td style="text-align: right;">464.59</td> <td style="text-align: right;">1</td></tr> <tr style="height: 17px;"> <td style="text-align: center; background-color: rgb(202, 202, 202); font-size: 8pt;">5</td> <td>464.68 DDFSDF 23.25 ccd 157.25</td> <td style="text-align: right;">68.00</td> <td style="text-align: right;">2</td></tr> <tr style="height: 17px;"> <td style="text-align: center; background-color: rgb(202, 202, 202); font-size: 8pt;">6</td> <td>464 DDFSDF 23.25 ccd 157.25</td> <td style="text-align: right;">23.25</td> <td style="text-align: right;">2</td></tr> <tr style="height: 17px;"> <td style="text-align: center; background-color: rgb(202, 202, 202); font-size: 8pt;">7</td> <td>464 DDFSDF 23.84 ccd 157.25</td> <td style="text-align: right;">84.00</td> <td style="text-align: right;">3</td></tr></tbody></table>
<table style="border-style: groove; border-color: rgb(0, 255, 0); background-color: rgb(255, 252, 249); font-family: Arial; color: rgb(0, 0, 0); font-size: 10pt;"><tbody><tr> <td>Spreadsheet Formulas</td></tr> <tr> <td> <table style="font-family: Arial; font-size: 9pt;" border="1" cellpadding="2" cellspacing="0"> <tbody> <tr style="background-color: rgb(202, 202, 202); font-size: 10pt;"> <td>Cell</td> <td>Formula</td></tr> <tr> <td>B4</td> <td>{=LOOKUP(10^99,--MID("|"&A4,SMALL(IF(((--ISNUMBER(--MID("|"&A4,
ROW($1:$1003),1))=0)*ISNUMBER(--MID("|"&A4,ROW($2:$1004),1))),ROW($2:$1004)),C4),
ROW($1:$1003)))}</td></tr></tbody></table></td></tr> <tr> <td>Formula Array:
Produce enclosing { } by entering
formula with CTRL+SHIFT+ENTER!</td></tr></tbody></table>
Maybe use another column to change numbers like 464 to 464.00 and then
use the formula on the revised column?


Excel tables to the web >> Excel Jeanie HTML 4

 

[Ron Coderre]

I think we finally have an all-purpose formula.

With A1:A7 containing

45t*&65/
9128A+BC37/E*465
91a28ABC3712DEF465
91.28ABC3712DEF465
91.28ABC37.1D2F465
464.59 DDFSDF 23.25 ccd 157.25
123asdf.asdf.asdf456
 
and
C1: 2

This array formula returns the specified number from the string,

B1: =LOOKUP(10^99,--MID("|"&A1,SMALL(IF(((--ISNUMBER(--("0"&MID(
SUBSTITUTE(" "&A1," ","|"),ROW($1:$25),1)))=0)*ISNUMBER(--(MID(
SUBSTITUTE(" "&A1," ","|"),ROW($2:$26),1)))),ROW($2:$26)),C1),ROW($1:$25)))

Copy B1 and paste into B2:B7

With the above examples, the formulas return these values:

45
37
28
91.28
2
23.25
456

Note: If you want to display two decimal places, change the number format.

Are we done, yet?

 

[Ron Coderre]

Yikes! I posted the wrong returned value list!

[B]45[/B] <-----Should be 65
37
28
[B]91.28[/B] <--Should be 3712
[B]2[/B] <------Should be 37.1
23.25 
456

so the list of second embedded numbers should be this:

65
37
28
3712
37.1
23.25

 

[pto160]

Yes, we are definitely done. This formula can pretty much work with any type of text format that is thrown at it. I thought regex was the only option for this, but I was proved wrong. Thanks so much for your help.

 

[jianniskouts]

i just did what you said and pressing F9 i get the correct result but when i press control+shift+enter i get something that looks like 3,0697E+11 INSTEAD Of 306970490622...please help!!

 

[VoG]

Just format the cell as Number and make the column wider.

 

[jianniskouts]

Just format the cell as Number and make the column wider.

thank you it worked, sorry for that but i am newbie....

 

[Tcurious]

Extract only numbers but need decimals

Schielrn,
The formula from Domenic at post 6:
Extracting Multiple Numbers from String
works great (I changed my string to cell A2):

=SUM(MID(0&A2,LARGE(ISNUMBER(--MID(A2,ROW(INDIRECT("1:"&LEN(A2))),1))*ROW(INDIRECT("1:"&LEN(A2))),ROW(INDIRECT("1:"&LEN(A2))))+1,1)*10^ROW(INDIRECT("1:"&LEN(A2)))/10)

Ron Coderre,
This formula is beautiful (I changed my string to cell A2):

=SUMPRODUCT(MID(0&A2,LARGE(INDEX(ISNUMBER(--MID(A2,ROW($1:$25),1))*
ROW($1:$25),0),ROW($1:$25))+1,1)*10^ROW($1:$25)/10)

Ron, I like your formula because of its compactness and non-array non-Ctrl-Shift-Enter.
I like Domenic’s because of the robustness of the ROW(INDIRECT("1:"&LEN(A2))).
Mashing your two formulas together (in Excel 2007 only – exceeds 7 nesting rule in Excel 2003) I got:

=SUMPRODUCT(MID(0&A2,LARGE(INDEX(ISNUMBER(--MID(A2,ROW(INDIRECT("1:"&LEN($A$2))),1))*
ROW(INDIRECT("1:"&LEN($A$2))),0),ROW(INDIRECT("1:"&LEN($A$2))))+1,1)*10^ROW(INDIRECT("1:"&LEN($A$2)))/10)

I learn a lot from both formulas. In essence, are these the concepts of how the formula is working:

1) Extract characters with MID
2) Convert extracted characters to numbers and errors with --
3) Ask array if elements are numbers with ISNUMBER
4) Multiply array of TRUE/FALSE by position -- *ROW(INDIRECT("1:"&LEN($A$2)))
5) Organize by position with LARGE (largest to smallest including zeroes)
6) Add 1 to avoid error with MID caused by zeros from LARGE
7) Concatenate a zero to beginning of string so the 1 added to the zeros will not cause error when MID extracts numbers
8) Multiply the extracted numbers by 10^ROW(INDIRECT("1:"&LEN($A$2))) to get the correct number of zeros for each extracted number
9) Divide by 10 to deal with the fact the we had a zero concatenated to the front of the string
10) Added

Am I getting the concepts, right?

I have found the above really useful and got it to work however have one big challenge I can't quite get my head around, what if the number is a decimal? Eg If the string is 2.28xbw I need it to extract 2.28 instead of 228 as these do, anyone any ideas?

 

[williamezell]

I played around with the formula some more...
This non-array formula seems to be working:

B1: =SUMPRODUCT(MID(0&A1,LARGE(INDEX(ISNUMBER(--MID(A1,ROW($1:$25),1))*
ROW($1:$25),0),ROW($1:$25))+1,1)*10^ROW($1:$25)/10)

That worked for me! Thanks!!!