VBA for Scanning Items Out/Into a registry

bobsburgers

Board Regular
Joined
Jun 25, 2017
Messages
60
Hi, all!

I'm working on a program that would track iPads used by our employees.

Ideally, the system would allow me to press a button to activate a search VBA, scan a bar code on the iPad and once the scanstring is located (in column A), allow me to scan an employee's ID card to populate the adjacent cell (column B) with the employee's ID number. This would then loop back to scan an iPad until the message box is manually closed.

So far, I have been able to come up with some code that allows me to find the correct iPad ID through QR codes, however, I can't seem to find a way to have the macro prompt a second message box asking for the Employee ID Number.

Would it be possible to help me find a way to have this macro contain both the "find the iPad" function, as well as automatically prompting a new message box asking for the Employee ID Number?

Here is the code I have so far:

Code:
Sub iPad_Out()

    Dim scanstring As String
    Dim foundscan As Range
    Dim ws As Worksheet
    Dim foundscan_address As String
    
Set ws = ActiveSheet

scanstring = InputBox("Please enter a value to search for", "Enter value")
If scanstring = "" Then Exit Sub

With ws.Columns("D")
    
    Set foundscan = .Find(What:=scanstring, LookIn:=xlValues, LookAt:=xlWhole, _
                          SearchOrder:=xlByRows, SearchDirection:=xlNext, _
                          MatchCase:=False, SearchFormat:=False)
                      
    If Not foundscan Is Nothing Then
foundscan_address = foundscan.Address

Do
        foundscan.Offset(0, 4).Value = scanstring
        ws.Activate
        foundscan.Activate
        ActiveWindow.ScrollRow = foundscan.Row

        Set foundscan = .FindNext(foundscan)

Loop While Not foundscan Is Nothing And foundscan.Address <> foundscan_address

    Else
        MsgBox scanstring & "  was not found"
    End If
    
End With

    Call iPad_Out

End Sub

Please let me know if you can provide any insight - thanks!

best,
bob
 

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