VBA: delete all rows where value (time) is less than 1 minute

JofFrey

New Member
Joined
Apr 3, 2023
Messages
11
Office Version
  1. 365
Platform
  1. Windows
Hello, I have to analyse a file where almost every 10 seconds a record is generated which is almost impossible to do. Therefore I would like to keep records where the date & time (Column C Start date) difference does not exceed 1 minute. I also want to keep the records where the speed (Column D) = "0 km/h".
So in the example underneath I would like to keep the records where I have added " good". I have no idea how to do this so basically I am doing it manually. However if one of you Excel wizards could create a a function in VBA that deletes those records or marks them in any way that I could filter them out it would mean a real help. I am talking about 2500-6000 each day so you know what I have to go through and how many coffees that would take.
BTW if I do C8-C2= 0,000694444 (so 1 minute equals 0,000694444).

Start dateSpeed
16/03/2024 07:51:36 good37 km/h
16/03/2024 07:51:4614 km/h
16/03/2024 07:51:5640 km/h
16/03/2024 07:52:0646 km/h
16/03/2024 07:52:1672 km/h
16/03/2024 07:52:2664 km/h
16/03/2024 07:52:36 good37 km/h
16/03/2024 07:52:4672 km/h
16/03/2024 07:52:5664 km/h
16/03/2024 07:53:0759 km/h
16/03/2024 07:53:1644 km/h
16/03/2024 07:53:2714 km/h
16/03/2024 07:53:37 good26 km/h
16/03/2024 07:53:4761 km/h
16/03/2024 07:53:5772 km/h
16/03/2024 07:54:0657 km/h
16/03/2024 07:54:1663 km/h
16/03/2024 07:54:2661 km/h
16/03/2024 07:54:3650 km/h
16/03/2024 07:54:46 good57 km/h
16/03/2024 07:54:5652 km/h
16/03/2024 07:55:0638 km/h
16/03/2024 07:55:1650 km/h
16/03/2024 07:55:2640 km/h
16/03/2024 07:55:3646 km/h
16/03/2024 07:55:46 good50 km/h
16/03/2024 07:55:5661 km/h
16/03/2024 07:56:0670 km/h
16/03/2024 07:56:1661 km/h
16/03/2024 07:56:2753 km/h
16/03/2024 07:56:3631 km/h
16/03/2024 07:56:46 good42 km/h
16/03/2024 07:56:5664 km/h
16/03/2024 07:57:0661 km/h
16/03/2024 07:57:1653 km/h
16/03/2024 07:57:2646 km/h
16/03/2024 07:57:36 good0 km/h
16/03/2024 07:57:46 good0 km/h
16/03/2024 07:57:57 good0 km/h
 
MrExcel_deleteTimDif.xls
ABCD
1Start dateSpeed
216/03/2024 07:51:3637 km/h
316/03/2024 07:51:4614 km/h
416/03/2024 07:51:5640 km/h
516/03/2024 07:52:0646 km/h
616/03/2024 07:52:1672 km/h
716/03/2024 07:52:2664 km/h
816/03/2024 07:52:3637 km/h
916/03/2024 07:52:4672 km/h
1016/03/2024 07:52:5664 km/h
1116/03/2024 07:53:0759 km/h
1216/03/2024 07:53:1644 km/h
1316/03/2024 07:53:2714 km/h
1416/03/2024 07:53:3726 km/h
1516/03/2024 07:53:4761 km/h
1616/03/2024 07:53:5772 km/h
1716/03/2024 07:54:0657 km/h
1816/03/2024 07:54:1663 km/h
1916/03/2024 07:54:2661 km/h
test
 
Upvote 0

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when I use the above, it still pastes in as Custom. For my previous code just posted, I forced all to be "Text" in General formatting.

So that latest code should work for you.

Rob
 
Upvote 0
If its plain text in your file, maybe this can work :

VBA Code:
Sub keep_good()

Dim lr, x As Long

lr = Cells(Rows.Count, 3).End(xlUp).Row
good_val = TimeValue(Right(Range("c2"), 8))

For x = 3 To lr 'start from row3 as we first value is always "good".
  
    If Range("C" & x) = "" Then Exit For 'check for blank rows to quit macro
   
       new_val = TimeValue(Right(Range("C" & x), 8))
    If new_val - good_val > 0.000694444 Or Left(Range("D" & x).Value, 1) = 0 Then
        good_val = TimeValue(Right(Range("c" & x).Value, 8))
    Else
        Range("C" & x).EntireRow.Delete
        x = x - 1
    End If

Next x

End Sub
Hi Rob, thank you very much, that worked as a charm, just had to declare "good_val" and "new_val" as a variable and perfect!
If you're ever in Belgium feel free to pass by for a cup of coffee, you saved me from drinking liters.
Thanks again!
 
Upvote 0
Great, glad it worked finally - thanks for the feedback.

Yes I plan to be there next year ! so won't forget.. ;-)

Rob
 
Upvote 0

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