VBA code is not working

Jagat Pavasia

Active Member
Joined
Mar 9, 2015
Messages
406
Office Version
  1. 2021
Platform
  1. Windows
1.JPG


VBA Code:
Private Sub Worksheet_Change(ByVal Target As Range)
If Target.CountLarge > 1 Then Exit Sub
Application.EnableEvents = False
Me.Unprotect
If Not Intersect(Target, [B:B,L:L]) Is Nothing Then
    If Target.Value = "**" Then
        Target.Value = Date
        Target.NumberFormat = "DD/MM/YYYY"
    End If
ElseIf Not Intersect(Target, [E1]) Is Nothing Then
    If Target.Value = "" Then
        Me.Range("A3:U3").AutoFilter Field:=Target.Column
    Else
        Me.Range("A3:U3").AutoFilter Field:=Target.Column, _
            Operator:=xlFilterValues, _
            Criteria1:="*" & CStr(Target.Value) & "*"
    End If
ElseIf Not Intersect(Target, [A1:V1]) Is Nothing Then
    If Target.Value = "" Then
        Me.Range("A3:U3").AutoFilter Field:=Target.Column
    Else
        Me.Range("A3:U3").AutoFilter Field:=Target.Column, _
            Operator:=xlFilterValues, _
            Criteria1:=CStr(Target.Value)
    End If
ElseIf Not Intersect([G:G], Target) Is Nothing Then
    If Target = "**" Then Target = WorksheetFunction.Max([G:G]) + 1
End If
Me.Protect DrawingObjects:=False, Contents:=True, _
           Scenarios:=False, AllowFormattingCells:=True, _
           AllowFiltering:=True
Application.EnableEvents = True
End Sub


I have this VBA code in My sheet , but when I input date in L3 than it is not working,
I have tried by change Formatting by Text, Date, Custom etc. but not working.
I am new in VBA code, so please edit my VBA and than give me
 

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this is working for me...excellent...thank you all replier.
The marked solution has been changed accordingly since the final code only has been changed slightly based on the special requirements that was not provided in the posts. In your future questions, please mark the post as the solution that actually answered your question, instead of your feedback message as it will help future readers. No further action is required for this thread.
 
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