UK License Plate Searcher

Hgreen1601

New Member
Joined
Jun 15, 2021
Messages
18
Office Version
  1. 2016
Platform
  1. Windows
I have been trying to make a macro where I enter a license plate and it searches the gov.uk website (https://vehicleenquiry.service.gov.uk) and returns the cylinder capacity.

Relatively new to macro writing so any explanation would be appreciated, currently have numerous errors.

VBA Code:
Sub EngineSearch()

    Dim Tool      As Object
    Dim Var     As Variant
    Dim element As Variant
    Dim WrkBk   As Workbook
    Dim WrkSht  As Worksheet
   
    Set WrkBk = ThisWorkbook
    Set WrkSht = WrkBk.ActiveSheet

    For i = WrkSht.Range("E3").Value To WrkSht.Range("F3").Value
    'Have put the cells of my data range within these values
   
   
    Set Tool = CreateObject("InternetExplorer.Application")
    Tool.navigate "[URL]https://vehicleenquiry.service.gov.uk/[/URL]"

    Tool.Visible = False
   
    Application.Wait (Now + TimeValue("0:00:01"))

    Set frm = Tool.document.getelementbyid("wizard_vehicle_enquiry_capture_vrn_vrn")

    frm.Value = WrkSht.Cells(i, 2).Value
       
    Tool.document.getelementbyid("submit_vrn_button").Click
   
    Application.Wait (Now + TimeValue("0:00:01"))

    Tool.document.getelementbyid("yes-vehicle-confirm").Click
    Tool.document.getelementbyid("capture_confirm_button").Click
   
    Application.Wait (Now + TimeValue("0:00:01"))

    Set HtmlType = ie.document.getelementbyid("cylinder_capacity")
    WrkSht.Range("C" & i) = Right(HtmlType.innerText, 7)
  

    Tool.Quit


    Next i
   
Exit Sub
 

Excel Facts

Will the fill handle fill 1, 2, 3?
Yes! Type 1 in a cell. Hold down Ctrl while you drag the fill handle.

As you forgot to give an example of source data and expected result accordingly …​
As you can attach a sample worksheet with this forum tool XL2BB or link a sample workbook on a files host website like Dropbox for example …​
 
Upvote 0
Engine Size Finder.xlsm
ABCDEFGHIJKLMN
1
2License PlateEngine SizeStart RowEnd Row
3LD66TVE310
4
5
6
7
8
9
10
11
Sheet1





Is this all you need or can I upload it with the module?
 
Upvote 0
Columns G & H are useless but what is the expected result for the cell C3 plate ?​
 
Upvote 0
As columns G:H are useless so I won't use them !​
From your attachment, what is the exact expected result in cell D3 according to the plate in cell C3 ?​
 
Upvote 0
According to your attachment a VBA demonstration for starters :​
VBA Code:
Sub DemoIE1()
  Const C = "complete", Y = "yes-vehicle-confirm"
    Dim V, R&, D As Date, oElt As Object
        V = [C1].CurrentRegion.Value2:  If UBound(V) < 3 Then Beep: Exit Sub
        On Error GoTo Fin
    With CreateObject("InternetExplorer.Application")
        For R = 3 To UBound(V)
            If Not IsEmpty(V(R, 1)) And IsEmpty(V(R, 2)) Then
                   .Navigate "https://vehicleenquiry.service.gov.uk/"
                    D = Now + 0.0001
                    On Error Resume Next
                Do
                    DoEvents
                    Set oElt = .Document.forms(0)("wizard_vehicle_enquiry_capture_vrn_vrn")
                Loop While D > Now And oElt Is Nothing
                    On Error GoTo Fin
                If oElt Is Nothing Then
                    Cells(R, 4).Value2 = "¤ error"
                Else
                        oElt.Value = V(R, 1)
                        oElt.form("submit_vrn_button").Click
                        Set oElt = Nothing
                        While .Document.ReadyState <> C:  DoEvents:  Wend
                    If IsObject(.Document.all(Y)) Then
                       .Document.all(Y).Click
                       .Document.all.capture_confirm_button.Click
                        While .Document.ReadyState <> C:  DoEvents:  Wend
                        Cells(R, 4).Value2 = .Document.querySelector("#engine_capacity>dd").innerText
                    Else
                        Cells(R, 4).Value2 = "¤ not found"
                    End If
                End If
            End If
        Next
Fin:
        If Err.Number <> -2147023706 Then .Quit
    End With
        If Err.Number Then Beep: Debug.Print Err.Number; " : "; Err.Description
End Sub
 
Upvote 0
Solution
According to your attachment a VBA demonstration for starters :​
VBA Code:
Sub DemoIE1()
  Const C = "complete", Y = "yes-vehicle-confirm"
    Dim V, R&, D As Date, oElt As Object
        V = [C1].CurrentRegion.Value2:  If UBound(V) < 3 Then Beep: Exit Sub
        On Error GoTo Fin
    With CreateObject("InternetExplorer.Application")
        For R = 3 To UBound(V)
            If Not IsEmpty(V(R, 1)) And IsEmpty(V(R, 2)) Then
                   .Navigate "https://vehicleenquiry.service.gov.uk/"
                    D = Now + 0.0001
                    On Error Resume Next
                Do
                    DoEvents
                    Set oElt = .Document.forms(0)("wizard_vehicle_enquiry_capture_vrn_vrn")
                Loop While D > Now And oElt Is Nothing
                    On Error GoTo Fin
                If oElt Is Nothing Then
                    Cells(R, 4).Value2 = "¤ error"
                Else
                        oElt.Value = V(R, 1)
                        oElt.form("submit_vrn_button").Click
                        Set oElt = Nothing
                        While .Document.ReadyState <> C:  DoEvents:  Wend
                    If IsObject(.Document.all(Y)) Then
                       .Document.all(Y).Click
                       .Document.all.capture_confirm_button.Click
                        While .Document.ReadyState <> C:  DoEvents:  Wend
                        Cells(R, 4).Value2 = .Document.querySelector("#engine_capacity>dd").innerText
                    Else
                        Cells(R, 4).Value2 = "¤ not found"
                    End If
                End If
            End If
        Next
Fin:
        If Err.Number <> -2147023706 Then .Quit
    End With
        If Err.Number Then Beep: Debug.Print Err.Number; " : "; Err.Description
End Sub
Great thank you, really appreciate the help.

If I was too add another variable to search at the same time would this prove much more difficult?
 
Upvote 0
Nope as once you get an element like the cylinder capacity that means the difficulties are bypassed …​
 
Upvote 0

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