Trying to extract a string between two string using MID and Search

initialize

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Dec 7, 2015
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So I have a column in excel that contain strings similar to "Policy Number: 123456, random random random string"
I m trying to create a new column with only the number after "Policy Number:"

=MID(F2,SEARCH("Policy Number:",F2)+14,SEARCH(",",F2)-SEARCH("Policy Number:",F2)-14). This doesnt work if after the policy number there is no comma. I also want it to show Null if there is no find.

Can someone give me some help?
 

Excel Facts

Whats the difference between CONCAT and CONCATENATE?
The newer CONCAT function can reference a range of cells. =CONCATENATE(A1,A2,A3,A4,A5) becomes =CONCAT(A1:A5)
Hi,

How about this:


Excel 2010
FGH
2Policy Number: 123456, random random random string123456
3Policy Number: 234567 random random random string234567
Sheet17
Cell Formulas
RangeFormula
H2=SUBSTITUTE(MID(F2,FIND(":",F2)+2,FIND(",",SUBSTITUTE(F2," ",",",3))-FIND(":",F2)-1),",","")+0


This also converts the result to a real Number.
 
Last edited:
Upvote 0
is the police number always a number with no spaces in between and always of numeric characters?


Excel 2013/2016
ABC
1Policy Number: 123456 random random random string123456
Sheet1
Cell Formulas
RangeFormula
C1{=LEFT(MID(A1,LEN("Policy Number: ")+1,255),MATCH(TRUE,ISERROR(MID(MID(A1,LEN("Policy Number: ")+1,255),ROW(INDIRECT("1:"&LEN(MID(A1,LEN("Policy Number: ")+1,255)))),1)+0),0)-1)}
Press CTRL+SHIFT+ENTER to enter array formulas.
 
Upvote 0
Since it is a policy number, can we assume the format of that policy number is always the same (that is, all policy numbers are 6 digits long)? If so...

=MID(F2,SEARCH("Policy Number:",F2)+15,6)
 
Upvote 0

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