this code become slow for 18000 rows despite of using dictionary and array

leap out

Active Member
Joined
Dec 4, 2020
Messages
288
Office Version
  1. 2016
  2. 2010
Hi experts
I got help from mr.Peter_Ss with some modification .
the code becomes more slowly when test for big data, despite of using dictionary & array
so the big data can be 18000 rows for each sheet . the code will calculation items based on column B and if there is duplicates items should merge for each sheet . the formula will be (stock-sales+pur-return) in sheet summary for last column ,also if there is new item in one of sheets but is not in another , then should also show and calculation . the code create whole data with format & borders and collect the data across sheet into sheet summary
VBA Code:
Sub CollateData_v4()
  Dim d As Object
  Dim ShList As Variant, a As Variant, vals As Variant
  Dim i As Long, j As Long
  Dim s As String
 
  Set d = CreateObject("Scripting.Dictionary")
  ShList = Split("stock|sales|pur|returns", "|")
  For j = 0 To UBound(ShList)
    With Sheets(ShList(j))
      a = .UsedRange.Value2
      For i = 2 To UBound(a)
        s = .Cells(i, 2)
        If Len(s) > 2 Then
         
        If Not d.exists(s) Then d(s) = Join(Application.Index(a, i, Array(3, 4, 5)), ";") & ";;;;"
          vals = Split(d(s), ";")
          If IsNumeric(vals(j + 3)) Then
           vals(j + 3) = vals(j + 3) + a(i, 6)
           Else
           vals(j + 3) = a(i, 6)
          End If
         
            d(s) = Join(vals, ";")
         
        End If
      Next i
    End With
  Next j
  Application.ScreenUpdating = False
  With Sheets("summary")
    .UsedRange.EntireRow.Delete
    With .Range("B2:C2").Resize(d.Count)
      .Value = Application.Transpose(Array(d.Keys, d.Items))
      With .Columns(2)
        .TextToColumns DataType:=xlDelimited, ConsecutiveDelimiter:=False, Semicolon:=True, Comma:=False, Space:=False, Other:=False
        With .Offset(, 7) ' ### was .Offset(, 5)
          .FormulaR1C1 = "=RC[-4]-RC[-3]+RC[-2]+RC[-1]"
          .Value = .Value
        End With
        '.Resize(, 3).EntireColumn.Insert '### not needed
      End With
      .Columns(1).TextToColumns DataType:=xlDelimited, ConsecutiveDelimiter:=False, Semicolon:=True, Comma:=False, Space:=False, Other:=False
      With .Columns(0)
        .Cells(1).Value = 1
        .DataSeries Rowcol:=xlColumns, Type:=xlLinear, Step:=1
      End With
    End With
    With .Range("A1:J1")
      .Value = Array("item", "CODE", "BRAND", "TYPE", "MANUFACTURE", "STOCK", "SALES", "PUR", "RETURNS", "BALANCE")
       .Font.Bold = True
  .Interior.Color = RGB(166, 166, 166)
      .EntireColumn.AutoFit
    End With
    With .UsedRange
      .BorderAround xlContinuous
      .Borders(xlInsideVertical).LineStyle = xlContinuous
      .Borders(xlInsideHorizontal).LineStyle = xlContinuous
    End With
  End With
  Application.ScreenUpdating = True
End Sub
for more detailes
INVEN with single search v0 c.xlsm
ABCDEF
1itemCODEBRANDTYPEMANUFACTUREQTY
21AA-110W40 208LQ8EU2222
32AA-215W40 208LCASSU400
43AA-35W30 208LQ8EU800
54AA-45W30 12x1LQ8EU600
65AA-510W40 208LENIIT300
76AA-65W30 4x4LQ8EU200
87AA-710W40 12x1LQ8EU120
98AA-815W40 12x1LCASSU450
109AA-910W40 12x1LENIIT890
1110AA-1010W40 4x4LQ8EU345
1211AA-1110W40 4x4LCASSU78
1312AA-1210W40 4x4LENIIT123
1413AA-135W40 4x4LQ8EU456
1514AA-145W40 4x4LCASSU678
1615AA-155W40 4x4LENIIT1234
1716AA-1620W50 4x4LQ8EU456
stock



INVEN with single search v0 c.xlsm
ABCDEF
1DATECODEBRANDTYPEMANUFACTURESALES
21/1/2021AA-110W40 208LQ8EU100
31/2/2021AA-215W40 208LCASSU50
41/3/2021AA-35W30 208LQ8EU280
51/4/2021AA-45W30 12x1LQ8EU300
61/5/2021AA-510W40 208LENIIT80
71/6/2021AA-65W30 4x4LQ8EU20
81/7/2021AA-710W40 12x1LQ8EU20
91/8/2021AA-815W40 12x1LCASSU20
101/9/2021AA-910W40 12x1LENIIT876
111/10/2021AA-1010W40 4x4LQ8EU345
121/11/2021AA-1110W40 4x4LCASSU123
131/12/2021AA-1210W40 4x4LENIIT78
141/13/2021AA-135W40 4x4LQ8EU300
151/14/2021AA-145W40 4x4LCASSU34
161/15/2021AA-155W40 4x4LENIIT23
171/16/2021AA-1620W50 4x4LQ8EU56
181/17/2021AA-110W40 208LQ8EU100
sales



INVEN with single search v0 c.xlsm
ABCDEF
1DATECODEBRANDTYPEMANUFACTUREPURCHASE
22/4/2021AA-110W40 208LQ8EU55
32/5/2021AA-215W40 208LCASSU20
42/6/2021AA-35W30 208LQ8EU10
52/7/2021AA-45W30 12x1LQ8EU10
62/8/2021AA-510W40 208LENIIT3
72/9/2021AA-65W30 4x4LQ8EU4
82/10/2021AA-710W40 12x1LQ8EU45
92/11/2021AA-815W40 12x1LCASSU8
102/12/2021AA-910W40 12x1LENIIT1
112/13/2021AA-1010W40 4x4LQ8EU100
122/14/2021AA-1110W40 4x4LCASSU20
132/15/2021AA-1210W40 4x4LENIIT100
142/16/2021AA-135W40 4x4LQ8EU44
152/17/2021AA-145W40 4x4LCASSU20
162/18/2021AA-155W40 4x4LENIIT50
172/19/2021AA-1620W50 4x4LQ8EU12
182/20/2021AA-1720W50 4x4LCASSU9
192/21/2021AA-1820W50 4x4LENIIT4
202/22/2021AA-110W40 208LQ8EU55
pur


INVEN with single search v0 c.xlsm
ABCDEF
1itemCODEBRANDTYPEMANUFACTUREreturns
24/5/2021AA-910W40 12x1LENIIT20
34/6/2021AA-1010W40 4x4LQ8EU30
44/7/2021AA-1110W40 4x4LCASSU40
54/8/2021AA-45W30 12x1LQ8EU10
64/9/2021AA-45W30 12x1LQ8EU11
returns



result
INVEN with single search v0 c.xlsm
ABCDEFGHIJ
1itemCODEBRANDTYPEMANUFACTURESTOCKSALESPURRETURNSBALANCE
21AA-110W40 208LQ8EU22222001102132
32AA-215W40 208LCASSU4005020370
43AA-35W30 208LQ8EU80028010530
54AA-45W30 12x1LQ8EU6003001021331
65AA-510W40 208LENIIT300803223
76AA-65W30 4x4LQ8EU200204184
87AA-710W40 12x1LQ8EU1202045145
98AA-815W40 12x1LCASSU450208438
109AA-910W40 12x1LENIIT89087612035
1110AA-1010W40 4x4LQ8EU34534510030130
1211AA-1110W40 4x4LCASSU78123204015
1312AA-1210W40 4x4LENIIT12378100145
1413AA-135W40 4x4LQ8EU45630044200
1514AA-145W40 4x4LCASSU6783420664
1615AA-155W40 4x4LENIIT123423501261
1716AA-1620W50 4x4LQ8EU4565612412
1817AA-1720W50 4x4LCASSU99
1918AA-1820W50 4x4LENIIT44
summary

can anybody make it fast,please?
 
thanks but the showing of data are incorrect
Sorry about that I misunderstood your code, however I think the idea of trying to avoid joining and splitting up the dictionary item might be worth trying. I needed to do a similar thing with some code I wrote a little while ago, instead of joining and splitting I passed an array to the dictionary. I think this method would be very suitable for you and possibly a lot faster. This is my code:
VBA Code:
Sub dictionaryandarray()
Dim dict As Object
Set dict = CreateObject("scripting.dictionary")
Dim temparr() As Variant
Dim outarr()
With Worksheets("BOM")
LastRow = .Cells(Rows.Count, "B").End(xlUp).Row   ' find last row of data
inarr = .Range(.Cells(1, 1), .Cells(LastRow, 7))     ' load the whole sheet of data into variant array ( 7 columns)
' find maximum week no
cwmax = 0
 For i = 4 To LastRow
   If inarr(i, 7) > cwmax Then
    cwmax = inarr(i, 7)
   End If
 Next i
'ReDim temparr(1 To 7)  ' to pass values to dictionary

 For i = 4 To LastRow
   If dict.Exists(inarr(i, 2)) Then
     Erase temparr
     ReDim temparr(1 To cwmax)  ' to pass values to dictionary
     temparr = dict.Item(inarr(i, 2)) ' load dictionary item into temp array
     temparr((inarr(i, 7))) = temparr(inarr(i, 7)) + inarr(i, 5)  ' add cost to total using week no as index
     dict.Item(inarr(i, 2)) = temparr  ' write tempory array back to dictionary
   Else
     Erase temparr
     ReDim temparr(1 To cwmax)  ' to pass values to dictionary
     temparr(inarr(i, 7)) = inarr(i, 5)   ' add first cost into total using week no as index
     dict.Add inarr(i, 2), temparr()
    End If
 Next i
End With
' output dictinary vlaues
 ReDim outarr(1 To LastRow, 1 To 5 + cwmax) '' define output array as the maximu possible size
indi = 1
For Each Key In dict
     Erase temparr
     ReDim temparr(1 To cwmax)  ' to pass values to dictionary
      temparr = dict.Item(Key)
     For j = 1 To cwmax
       outarr(indi, 4 + j) = temparr(j)
     Next j
     outarr(indi, 1) = Key
     indi = indi + 1
Next Key
With Worksheets("Sheet3")
.Range(.Cells(4, 2), .Cells(4 + indi, 5 + cwmax)) = outarr
End With
End Sub
 
Upvote 0

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Ok, my time test results are in for the following code submissions:

1.56875 average seconds for jecV2 post #10 with the output sheet cleared & 18K rows

1.03046875 average seconds for bebo021999 post #7 with zeros hidden & 18K rows

0.58984375 average seconds for johnnyL post #8 with 18k rows
 
Upvote 0
Theoretically, that means the code from post #8 should be about 5 times faster than the code from the original post. :) Hopefully @leap out can confirm or deny with the real world testing, my testing results.
 
Upvote 0
@JEC great ! but your code doesn't show the minus or positive value correctly . if there is just value in column sales then should show minus value when calculate in column BALANCE also if there is just value in column RETURNS then should show minus value in column BALANCE .
thanks
 
Upvote 0
@johnnyL thanks but I can't test your code .it gives error as in picture .I thought script runtime doesn't select from reference ,but it seems another option should select, can you guide me to test it,please ? to select the most best solution;)

1.PNG
 
Upvote 0
@johnnyL thanks but I can't test your code .it gives error as in picture .I thought script runtime doesn't select from reference ,but it seems another option should select, can you guide me to test it,please ? to select the most best solution;)

View attachment 70891

Did you follow the directions at the top of the script? Adding a class Module?
 
Upvote 0

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