Sum Frequency IF formulas with multiple criteria

NewbieExcel123

New Member
Joined
Jul 30, 2024
Messages
10
Office Version
  1. 365
Platform
  1. Windows
Hi all,

I have a formula I found on here (thanks for the help), but I need to add another criteria for it to search for.
It searches for how many times the word 'Pass' appears more than 5 times in a row until a 'Fail' is found, and then it tells me the total times that occurs.

Column NColumn O
AOPass
AOPass
AOPass
EOPass
EOFail
EOPass
EOPass
EOPass
AOPass
AOPass

Currently the formula is:
=SUM(--(FREQUENCY(IF(O5:O99="Pass",ROW(O5:O99)),IF(O5:O99="Fail",ROW(O5:O99)))>=5))

But I want to add the option for have one formula also search for EO and another formula search for AO.

Essentially I need to add into the above formula:

$N$5:$N$100,"=AO", $O$5:$O$100,"=Pass
or
$N$5:$N$100,"=EO", $O$5:$O$100,"=Pass

I am unable to upload files unfortunately.

Thank you
 

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Try:

Book5
KLMNO
1Code# of 5-in-a-rowCodePass/Fail
2AO2AOPass
3EO1AOPass
4AOPass
5EOPass
6EOFail
7EOPass
8EOPass
9EOPass
10AOPass
11AOPass
12AOPass
13AOPass
14AOFail
15AOPass
16AOPass
17AOPass
18AOPass
19AOPass
20EOpass
21EOpass
22EOpass
23AOfail
24
Sheet4
Cell Formulas
RangeFormula
L2:L3L2=LET(f,FILTER($O$2:$O$100,$N$2:$N$100=K2),s,SEQUENCE(ROWS(f)),fr,FREQUENCY(IF(f="pass",s),IF(f="fail",s)),SUM(--(fr>=5)))
 
Upvote 0
Solution
Welcome to the MrExcel forum.

Try:

Thank you very much, that worked great, I have a question to make it work with what I need, can I use a wild card search on the 'Pass' bit? I also have another criteria which is "Pass (Advisory)" which I need to include in the total of cells matching EO and AO? I did have a go adding in *Pass or ?*** but it broke the formula.

Thank you
 
Upvote 0
Or if a wild card can't be used, how would I add a second criteria to search "Pass" and "Pass (Advisory)" under AO and EO?
Thank you
 
Upvote 0
I'd suggest using the ISNUMBER(SEARCH("pass",string)) construct. SEARCH will return the offset into string where "pass" starts, or an error if it's not found. Then you can see if you get a number back by using ISNUMBER, telling you that it's in there somewhere. So the formula becomes:

Book5
KLMNO
1Code# of 5-in-a-rowCodePass/Fail
2AO2AOPass
3EO1AOPass
4AOPass
5EOPass
6EOFail
7EOPass
8EOPass
9EOPass
10AOPass (Advisory)
11AOPass
12AOPass
13AOPass
14AOFail
15AOPass
16AOPass
17AOPass
18AOPass
19AOPass
20EOpass
21EOpass
22EOpass
23AOfail
Sheet4
Cell Formulas
RangeFormula
L2:L3L2=LET(f,FILTER($O$2:$O$100,$N$2:$N$100=K2),s,SEQUENCE(ROWS(f)),fr,FREQUENCY(IF(ISNUMBER(SEARCH("pass",f)),s),IF(f="fail",s)),SUM(--(fr>=5)))
 
Upvote 0
Thank you again! After googling I'm glad you came back with that as it kinda of was in the direction I was heading
However I've popped that in but I'm getting a #calc! Errors on ones where there are no AO or EO for it to search, so I assume it needs something to tell to return zero where no AO or EO is present?

This is a great learning journey and you're helping loads, thank you for helping me.
 
Upvote 0
I think this is easiest:

=LET(f,FILTER($O$2:$O$100,$N$2:$N$100=K2,"Fail"),s,SEQUENCE(ROWS(f)),fr,FREQUENCY(IF(ISNUMBER(SEARCH("pass",f)),s),IF(f="fail",s)),SUM(--(fr>=5)))

If the filter doesn't find AO or EO, then it just returns a default value of "Fail", and when that is given to the rest of the formula, it returns 0.

Happy to help!
 
Upvote 0
It searches for how many times the word 'Pass' appears more than 5 times in a row until a 'Fail' is found, and then it tells me the total times that occurs.
Eric's formula is counting 5 or more, but your OP asked for more than 5 times. If it's more than 5 times then you can change my formula to 6 towards the end of the formula.
One more option:
Book3
KLMNO
1Code# of 5-in-a-rowCodePass/Fail
2AO2AOPass
3EO1AOPass
4XD0AOPass
5EOPass
6EOFail
7EOPass
8EOPass
9EOPass
10AOPass (Advisory)
11AOPass
12AOPass
13AOPass
14AOFail
15AOPass
16AOPass
17AOPass
18AOPass
19AOPass
20EOpass
21EOpass
22EOpass
23AOfail
Sheet1
Cell Formulas
RangeFormula
L2:L4L2=SUM(--(SCAN(0,FILTER($O$2:$O$23,$N$2:$N$23=K2,0),LAMBDA(a,b,IF(ISNUMBER(SEARCH("Pass",b)),a+1,0)))=5))
 
Last edited:
Upvote 0
Eric's formula is counting 5 or more, but your OP asked for more than 5 times. If it's more than 5 times then you can change my formula to 6 towards the end of the formula.
One more option:

Sorry I did mean how many times does Pass or Pass (advisory) appear 5 times in a row, so how many blocks of 5 are there, so if a Fail appears say 3 Passes in, the count starts again after that fail to look for another 5 in a row.
 
Upvote 0
So I've come across a problem, it all seemed to be working fine, turned the result into a percentage so that 1 block of 5 "Pass" including "Pass (Advisory)" would equal 50% and two blocks of 5 would equal 100%.
But for some reason it's not done it in this one, is it because there's no breaks between the two blocks of 5? just 10 "Pass" in a row?
AO Passes = 1050%
EO Passes = 0None Completed
AOFail
AOPass
AOPass
AOPass
AOPass
AOPass
AOPass
AOPass
AOPass
AOPass


=IFERROR(LET(f,FILTER($I$5:$I$103,$H$5:$H$103="AO"),s,SEQUENCE(ROWS(f)),fr,FREQUENCY(IF(ISNUMBER(SEARCH("Pass",f)),s),IF(f="fail",s)),SUM(--(fr>=5)))*0.5,"None completed")

Thank you
 
Upvote 0

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