Removing Part of Cell/Text

RJB78

Board Regular
Joined
Aug 8, 2016
Messages
69
Office Version
  1. 365
Hello - Trying to come up with formula that will give me the number from a different cell, but the cell I am trying to reference also had letters,

Example: The cell referenced, lets call it A1, contains: '4 yrs'. I would like cell A2 to calculate 4. I tried doing a =LEFT(A1,1), but the issue I ran into was double digit numbers ie 10 yrs., would only return the first digit, 1.

Thank you in advance!
 

Excel Facts

Quick Sum
Select a range of cells. The total appears in bottom right of Excel screen. Right-click total to add Max, Min, Count, Average.
Is this what you are looking for...
Excel Formula:
=LOOKUP(9.9E+307,--LEFT(MID(A1,MIN(FIND({0,1,2,3,4,5,6,7,8,9},A1&"0123456789")),99),ROW($1:$99)))
This is not very robust though. In the examples below ..
  • The first example fails if a couple of rows are inserted above
  • The second one fails outright
The first issue is easy enough to resolve, but the second is not so simple to solve with worksheet formulas. For one thing, whether decimal numbers might be included or not could change the approach.

21 09 18.xlsm
AB
1a 5 b 35
2xx 1 decade44531
Sample
Cell Formulas
RangeFormula
B1:B2B1=LOOKUP(9.9E+307,--LEFT(MID(A1,MIN(FIND({0,1,2,3,4,5,6,7,8,9},A1&"0123456789")),99),ROW($1:$101)))
 
Upvote 0
With regex. Catches decimal numbers as well.
Did not manage to put it in one pattern, which is probably possible.

VBA Code:
Function jec(cell As String) As Double
 On Error Resume Next
  With CreateObject("VBscript.RegExp")
    .Global = True
    .Pattern = "\d+\.(\d+)"
     a = .Execute(cell)(0)
    .Pattern = "\d+"
     If IsEmpty(a) Then
        jec = .Execute(cell)(0)
     Else
        jec = a
     End If
  End With
End Function
 
Upvote 0
Did not manage to put it in one pattern, which is probably possible.
It certainly is, also catches negative numbers & handles if no numbers at all

VBA Code:
Function GetNum(s As String) As Variant
  Dim RX As Object
  
  GetNum = ""
  Set RX = CreateObject("VBScript.RegExp")
  RX.Pattern = "\-?\d+(\.\d*)?"
  If RX.Test(s) Then GetNum = Val(RX.Execute(s)(0))
End Function

21 09 18.xlsm
AB
1a 5 b 35
2xx 1 decade1
3 
4a 1.23561.2356
5avv -67.1434 abc-67.1434
6xxx 
Sample
Cell Formulas
RangeFormula
B1:B6B1=GetNum(A1)
 
Upvote 0

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