Ranking multiple columns

mrcsbenson

New Member
Joined
May 8, 2024
Messages
9
Office Version
  1. 365
  2. 2021
Platform
  1. Windows
I am trying to come up with a ranking system that would take into account two separate values (from 2 different columns) and come up with a combined score (or rank).

In an ideal world, the formula would look at column(s) 'B' & 'C' and return a score that would rank these accounts from 1- whatever

Even better would be a way to rank column B holding 75% and column C weighting at 25% to make a total of 100% total ranking score.
 

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I just made a change with the price from the picture above, before I made this change Airline 1 was #2 and Airline 2 was #1 because it had the lowest cost and the highest score but now when I changed the price for Airline 1 and Airline 2 the ranking didn’t change which is odd if the formula is taking into account the price (75%) and score (25%) and the price is way more than Airline 3 and 4 even with the score still being high.

Hopefully that makes sense in what I am saying
 
Upvote 0
1 Can you post that in this thread, explaining what you would expect?
1715286828728.png


I just made a change with the price from the picture above, before I made this change Airline 1 was #2 and Airline 2 was #1 because it had the lowest cost and the highest score but now when I changed the price for Airline 1 and Airline 2 the ranking didn’t change which is odd if the formula is taking into account the price (75%) and score (25%) and the price is way more than Airline 3 and 4 even with the score still being high.

Hopefully that makes sense in what I am saying
 
Upvote 0
See if this works for you.
Book1
ABCDE
1PriceKPICombined ScoreRank
2Air128.50.4513
3Air2312.50.2504
4Air30.665.50.7821
5Air40.5530.7502
Sheet1
Cell Formulas
RangeFormula
D2:D5D2=LET( norm_price,1-(B2:B5-MIN($B$2:$B$5))/(MAX($B$2:$B$5)-MIN($B$2:$B$5)), norm_KPI,(C2:C5-MIN($C$2:$C$5))/(MAX($C$2:$C$5)-MIN($C$2:$C$5)), 0.75*norm_price+0.25*norm_KPI)
E2:E5E2=RANK.EQ(D2,$D$2#)
Dynamic array formulas.
 
Upvote 0

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