ststern45
Well-known Member
- Joined
- Sep 17, 2005
- Messages
- 974
- Office Version
- 365
- 2010
- Platform
- Windows
Master Set of 3 numbers between 0 through 9
Cell A1 = 4
Cell B1 = 9
Cell C1 = 0
Next 3 sets of number between 0 through 9
Cell A2 = 2
Cell B2 = 2
Cell C2 = 9
Cell A3 = 4
Cell B3 = 7
Cell C3 = 3
Cell A4 = 6
Cell B4 = 9
Cell C4 = 6
The remainder of the cells below are as follows that stay the same values:
A5 = 0, B5 = 0, C5 = 0
A6 = 1, B6 = 1, C6 = 1
A7 = 2, B7 = 2, C7 = 2
A8 = 3, B8 = 3, C8 = 3
A9 = 4, B9 = 4, C9 = 4
A10 = 5, B10 = 5, C10 = 5
A11 = 6, B11 = 6, C11 = 6
A12 = 7, B12 = 7, C12 = 7
A13 = 8, B13 = 8, C13 = 8
A14 = 9, B14 = 9, C14 = 9
If I align the values as follows
C1-C2-C3
Row 01 - 4 - 9 - 0
Row 02- 2 - 2 - 9
Row 03 - 4 - 7 - 2
Row 04 - 6 - 9 - 6
Row 05 - 0 - 0 - 0
Row 06 - 1 - 1 - 1
Row 07 - 2 - 2 - 2
Row 08 - 3 - 3 - 3
Row 09 - 4 - 4 - 4
Row 10 - 5 - 5 - 5
Row 11 - 6 - 6 - 6
Row 12 - 7 - 7 - 7
Row 13 - 8 - 8 - 8
Row 14 - 9 - 9 - 9
4-9-0 is the main set
Below I calculate how far back until all 3 values 4-9-0 appear which is 4
The formula I am trying to figure out is the following
The 4 from the 4-9-0 appears in the 1st column in the 3rd row under the 2-2-9
The 9 from the 4-9-0 appears in the 3rd column in the 2nd row under the 4-9-0
The 0 from the 4-9-0 appears in both the 1st, 2nd, and 3rd columns on the 5th row under the 6-9-6
This is the outcome I'm trying to achieve:
Since the digits 4-9-0 appear in the 4 rows below the 4-9-0 (see below)
C1 C2 C3
4 - 9 - 0
x - x - 9
4 - x - x
x - x - x
x - 0 - x
The final result I am looking for is the following:
The 9 = C3 (Column 3) since it was the 1st digit to appear below the 4 - 9 - 0
The 4 = C1 (Column 1) since it was the 2nd digit to appear below the 4 - 9 - 0
The 0 = C2 (Column 2) since it was the 3rd and final digit to appear below the 4 - 9 - 0
So my final outcome would be C3, C1, C2 or 3 - 1 - 2
Some digit will repeat on the top line so for example, instead of 4 - 9 - 0 it cold be 4 - 4 -4 , 4 - 4 - 0, 4 - 9 -9 etc.
Any help would be greatly appreciated.
Thank you in advance!!
Cell A1 = 4
Cell B1 = 9
Cell C1 = 0
Next 3 sets of number between 0 through 9
Cell A2 = 2
Cell B2 = 2
Cell C2 = 9
Cell A3 = 4
Cell B3 = 7
Cell C3 = 3
Cell A4 = 6
Cell B4 = 9
Cell C4 = 6
The remainder of the cells below are as follows that stay the same values:
A5 = 0, B5 = 0, C5 = 0
A6 = 1, B6 = 1, C6 = 1
A7 = 2, B7 = 2, C7 = 2
A8 = 3, B8 = 3, C8 = 3
A9 = 4, B9 = 4, C9 = 4
A10 = 5, B10 = 5, C10 = 5
A11 = 6, B11 = 6, C11 = 6
A12 = 7, B12 = 7, C12 = 7
A13 = 8, B13 = 8, C13 = 8
A14 = 9, B14 = 9, C14 = 9
If I align the values as follows
C1-C2-C3
Row 01 - 4 - 9 - 0
Row 02- 2 - 2 - 9
Row 03 - 4 - 7 - 2
Row 04 - 6 - 9 - 6
Row 05 - 0 - 0 - 0
Row 06 - 1 - 1 - 1
Row 07 - 2 - 2 - 2
Row 08 - 3 - 3 - 3
Row 09 - 4 - 4 - 4
Row 10 - 5 - 5 - 5
Row 11 - 6 - 6 - 6
Row 12 - 7 - 7 - 7
Row 13 - 8 - 8 - 8
Row 14 - 9 - 9 - 9
4-9-0 is the main set
Below I calculate how far back until all 3 values 4-9-0 appear which is 4
The formula I am trying to figure out is the following
The 4 from the 4-9-0 appears in the 1st column in the 3rd row under the 2-2-9
The 9 from the 4-9-0 appears in the 3rd column in the 2nd row under the 4-9-0
The 0 from the 4-9-0 appears in both the 1st, 2nd, and 3rd columns on the 5th row under the 6-9-6
This is the outcome I'm trying to achieve:
Since the digits 4-9-0 appear in the 4 rows below the 4-9-0 (see below)
C1 C2 C3
4 - 9 - 0
x - x - 9
4 - x - x
x - x - x
x - 0 - x
The final result I am looking for is the following:
The 9 = C3 (Column 3) since it was the 1st digit to appear below the 4 - 9 - 0
The 4 = C1 (Column 1) since it was the 2nd digit to appear below the 4 - 9 - 0
The 0 = C2 (Column 2) since it was the 3rd and final digit to appear below the 4 - 9 - 0
So my final outcome would be C3, C1, C2 or 3 - 1 - 2
Some digit will repeat on the top line so for example, instead of 4 - 9 - 0 it cold be 4 - 4 -4 , 4 - 4 - 0, 4 - 9 -9 etc.
Any help would be greatly appreciated.
Thank you in advance!!