OK, so the value in U3 can be more than 5, but not the value in T3, correct? I thought the sum was to be capped at 5, not just the value in T3 (same logic applies for capping at 3).
No. The condition of at least 5 from S3 is not met (the value is currently 1). The value in t3 is currently 4. U3 in this situation should be 1 and this above formula provides a value back of 5.
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