Identify "nth" unique entry in a list

ellison

Active Member
Joined
Aug 1, 2012
Messages
356
Office Version
  1. 365
Platform
  1. Windows
Hi, is it possible to identify the "nth" unique entry in a list?
In other words: Column A has 8 different unique entries, some duplicated.
So for rows 7 to 8 where the Info is "charlie":
Col B "nth unique entry": charlie is the 5th unique entry on the list (i.e. 1,2,alpha,beta, charlie)
Col C "nth with count": there are 2 duplicates of charlie, so the 1st one (row 8) will be 5.1. And the second row (row 9) 5.2
If it helps, the info in Column is sorted A-Z


Book3
ABC
1Info (a-z)"nth unique entry""nth with count"
2111.1
3222.1
4222.2
5alpha33.1
6beta44.1
7charlie55.1
8charlie55.2
9delta66.1
10echo77.1
11echo77.1
12echo77.1
13foxtrot88.1
14foxtrot88.2
Sheet1




Hope this helps
 
Another option...
Book1
ABCDEF
1Info (a-z)"nth unique entry""nth with count"nnth unique
2111.17echo
3222.1
4222.2
5alpha33.1
6beta44.1
7charlie55.1
8charlie55.2
9delta66.1
10echo77.1
11echo77.2
12echo77.3
13foxtrot88.1
14foxtrot88.2
Sheet1
Cell Formulas
RangeFormula
B2:B14B2=SUM(1/COUNTIF($A$2:A2,$A$2:A2))
C2C2=B2+0.1
C3:C14C3=IF(B3<>B2,B3+0.1,C2+0.1)
F2F2=INDEX(UNIQUE(A2:A14),$E$2)

Doug
 
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is there a way that the digits that the counts give to inclue the leading zero's....
How about
Excel Formula:
=LET(d,FILTER(A2:A100,A2:A100<>""),r,ROWS(d),u,UNIQUE(d),x,XMATCH(d,u),HSTACK(x,TEXT(x,"000")&"."&MMULT((SEQUENCE(r)>=SEQUENCE(,r))*(d=TOROW(d)),SEQUENCE(r,,,0))))
 
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Solution
How about
Excel Formula:
=LET(d,FILTER(A2:A100,A2:A100<>""),r,ROWS(d),u,UNIQUE(d),x,XMATCH(d,u),HSTACK(x,TEXT(x,"000")&"."&MMULT((SEQUENCE(r)>=SEQUENCE(,r))*(d=TOROW(d)),SEQUENCE(r,,,0))))
Brilliant!!!

The "simples" way that I found way to go to custom number format and type in 000.000. Then export the results to notepad, and copy and paste it back into Excel to make the changes take effect.

In short, your way is MUCH better! :ROFLMAO: :ROFLMAO:
 
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