How use RC formulas when fill three columns

Abdo

Board Regular
Joined
May 16, 2022
Messages
229
Office Version
  1. 2019
  2. 2010
Platform
  1. Windows
Hello
I have this code.
VBA Code:
Private Sub Worksheet_Change(ByVal Target As Range)

    Dim lr As Long
    If Target.Address = Range("G2").Address Or Target.Column = 5 Or Target.Column = 6 Then
        Application.EnableEvents = False
        lr = Cells(Rows.Count, "B").End(xlUp).Row

        Range("G2").FormulaR1C1 = "=RC[-2]-RC[-1]"
        Range("G3:G" & lr).FormulaR1C1 = "=R[-1]C+RC[-2]-RC[-1]"
        Range("G3:G" & lr).Value = Range("G3:G" & lr).Value
        Application.EnableEvents = True
    End If

End Sub
I try when fill column E or F then will fill two formula
in G2=E2-F2
G3=G2+E3-F3
G4=G3+E4-F4
and so on .
the code will show error in G2,G3 =#VALUE
any help guys,please?
 

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It is because your 2nd formula is looking at the header row which is text due to your 2nd formula overwriting the first formula, as your last row is 2 at the time i.e. it is putting =G1+E2-F2 in cell G2 as the code is saying
VBA Code:
Range("G3:G2").FormulaR1C1 = "=R[-1]C+RC[-2]-RC[-1]"
When there isn't an inv number in row 3 of column B

Rich (BB code):
Private Sub Worksheet_Change(ByVal Target As Range)

    Dim lr As Long
    If Target.Address = Range("G2").Address Or Target.Column = 5 Or Target.Column = 6 Then
        Application.EnableEvents = False
        lr = Cells(Rows.Count, "B").End(xlUp).Row

        Range("G2").FormulaR1C1 = "=RC[-2]-RC[-1]"
      
        If lr < 3 Then lr = 3
      
        Range("G3:G" & lr).FormulaR1C1 = "=R[-1]C+RC[-2]-RC[-1]"
        Range("G3:G" & lr).Value = Range("G3:G" & lr).Value
        Application.EnableEvents = True
    End If

End Sub
 
Last edited:
Upvote 0
VBA Code:
"=R[-1]C+RC[-2]-RC[-1]"
this is what I got when use recorded macro then I set for this formula in G3 , I don't understand what the header is relating !
should start from row2,3
so what I suppose to fix it?
 
Upvote 0
should start from row2,3
From my last post
Rich (BB code):
is putting =G1+E2-F2 in cell G2 as the code is saying
VBA Code:
Range("G3:G2").FormulaR1C1 = "=R[-1]C+RC[-2]-RC[-1]"
 
Upvote 0
it works.:)
VBA Code:
        Range("G2").FormulaR1C1 = "=RC[-2]-RC[-1]"<br>
I suppose when write in e2 or f2 so in g2=e2-d2 , but will show error
after that when write in e3 or f3 should look to g2 , not g1 . I don't select cells in the headers to start from headers!
so I don't used to state condition as you did it.in some similar cases no need use IF condition and works ,but in here I'm confused!
 
Upvote 0
It isn't
Excel Formula:
Range("G2").FormulaR1C1 = "=RC[-2]-RC[-1]"
that caused the issue, that was writing in the cell correctly.

It is the 2nd formula, when lr is 2 the cells referenced with
VBA Code:
Range("G3:G" & lr)
are
VBA Code:
 Range("G3:G" & 2)
or
VBA Code:
Range("G3:G2")
which is exactly the same range as
VBA Code:
Range("G2:G3")
and so it was overwriting the formula in G2 with
Excel Formula:
=G1+E2-F2

You could also probably do

Rich (BB code):
Private Sub Worksheet_Change(ByVal Target As Range)

    Dim lr As Long
    If Target.Address = Range("G2").Address Or Target.Column = 5 Or Target.Column = 6 Then
        Application.EnableEvents = False
        lr = Cells(Rows.Count, "B").End(xlUp).Row

'        Range("G2").FormulaR1C1 = "=RC[-2]-RC[-1]"
'
'        If lr = 2 Then lr = 3
        
        Range("G2:G" & lr).FormulaR1C1 = "=SUM(R[-1]C,RC[-2])-RC[-1]"
        Range("G3:G" & lr).Value = Range("G3:G" & lr).Value
        Application.EnableEvents = True
    End If

End Sub


it works.:)
Happy it helped
 
Last edited:
Upvote 0
Solution
VBA Code:
        Range("G3:G" &amp; lr).Value = Range("G3:G" &amp; lr).Value<br>
to avoid show formulas I suppose this
Rich (BB code):
        Range("G2:G" &amp; lr).Value = Range("G2:G" &amp; lr).Value
I prefer the last answering .:)
thanks for your time and help.;)
 
Upvote 0
I prefer the last answering .:)
thanks for your time and help.;)
You're welcome (and yes to your last code if you want G2 included, left it as that was how you had it in post 1)
 
Upvote 0

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