How to return only part of a string from a list?

FlashDota

New Member
Joined
Jun 11, 2023
Messages
33
Office Version
  1. 2021
Platform
  1. Windows
Let's say I have in sheet 1 cell A1: The best scenes from Jursassic Park

In sheet 2 I have a list like in the picture:
A1: Jursassic Park
A2: The Bourne Identity

I want a formula where if a part of the value in A1 is found in that list, return only that title. See pictures for example
 

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I don't know if it is possible with your data but I included an example in case more than 1 item from Sheet2 is found.

FlashDota.xlsm
A
1
2Jurassic Park
3The Bourne Identity
4Best Scenes
5
Sheet2


FlashDota.xlsm
AB
1
2The best scenes from Jurassic ParkJurassic Park, Best Scenes
Sheet1
Cell Formulas
RangeFormula
B2B2=LET(r,Sheet2!A$2:A$100,TEXTJOIN(", ",1,FILTER(r,ISNUMBER(SEARCH(r,A2))*(r<>""))))


BTW, I suggest that you investigate XL2BB for providing sample data to make it easier for helpers by not having to manually type out sample data to test with.
 
Upvote 0
Solution
The answer from Petter_SSs is excelent. But I would like add a few points.
Use tabels for both your lists, so it is easier to expand.

Second is add an IFERROR function, in case there NO matches.

My example without the LET-function, but with table ref instead.
Excel Formula:
=IFERROR(TEXTJOIN(", ",TRUE,FILTER(MyList[List],ISNUMBER(SEARCH(MyList[List];A2))*(MyList[List]<>""))),"Not in list")



1693482461777.png
1693482485617.png
 
Upvote 0
There is no reason to use Iferror, which will hid any error, just use the Ifempty argument of filter
Excel Formula:
=LET(r,Sheet2!A$2:A$100,TEXTJOIN(", ",1,FILTER(r,ISNUMBER(SEARCH(r,A2))*(r<>""),"Not in list")))
 
Upvote 0
I don't know if it is possible with your data but I included an example in case more than 1 item from Sheet2 is found.

FlashDota.xlsm
A
1
2Jurassic Park
3The Bourne Identity
4Best Scenes
5
Sheet2


FlashDota.xlsm
AB
1
2The best scenes from Jurassic ParkJurassic Park, Best Scenes
Sheet1
Cell Formulas
RangeFormula
B2B2=LET(r,Sheet2!A$2:A$100,TEXTJOIN(", ",1,FILTER(r,ISNUMBER(SEARCH(r,A2))*(r<>""))))


BTW, I suggest that you investigate XL2BB for providing sample data to make it easier for helpers by not having to manually type out sample data to test with.
Thank you very much, I think this is the solution
 
Upvote 0
You're welcome. Thanks for the follow-up. Might be set to include the "Not in list" per @Fluff's modification or return just "" as below if no matches are found.
Excel Formula:
=LET(r,Sheet2!A$2:A$100,TEXTJOIN(", ",1,FILTER(r,ISNUMBER(SEARCH(r,A2))*(r<>""),"")))
 
Upvote 0

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