How to delete entire.column between a Range.

Trev0j

New Member
Joined
May 27, 2018
Messages
28
Hello,

what I want to do is:

i have a ranged name" Adjusted" and ranged name " Start" which is located in A1. i want to delete entire columns between range "Start" and "Adjusted". wherever the range " Adjusted" is located.
btw, before this code, need to find the range "Adjusted" and delete all the columns in between A1

I am thankfull for every help!
 
Last edited:

Excel Facts

Whats the difference between CONCAT and CONCATENATE?
The newer CONCAT function can reference a range of cells. =CONCATENATE(A1,A2,A3,A4,A5) becomes =CONCAT(A1:A5)
Based on your responses, I am guessing Rick hit the nail on the head here:
Is "Start" and "Adjusted" actual Excel Defined Names or are they just range variables set within your code?
Maybe explain to us exactly how/where you created these "named" ranges.
If in VBA code, please post your code.
 
Upvote 0
Based on your responses, I am guessing Rick hit the nail on the head here:

Maybe explain to us exactly how/where you created these "named" ranges.
If in VBA code, please post your code.

Sorry if i named it wrong,also sorry for my english :) but these are the headings of the columns.

i have just recorded a macro selecting the entire rows
Code:
Rows("1:1").Select
Selection.Find(What:="Adjusted", After:=ActiveCell, LookIn:=xlFormulas, _        LookAt:=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlNext, _
        MatchCase:=False, SearchFormat:=False).Activate...
and to delete the columns without specific count in between "Start" and "Adjusted"
 
Upvote 0
Yes, that makes a huge difference. A cell populated with that value and a named range are two entirely different things.
I think this will do what you want:
Code:
Sub MyDelete()

    Dim startCol As Long
    Dim adjCol As Long
    
'   Find Start column
    startCol = Rows("1:1").Find(What:="Start", After:=Range("A1"), LookIn:=xlFormulas, _
        LookAt:=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlNext, _
        MatchCase:=False, SearchFormat:=False).Column
        
'   Find Adjusted column
    adjCol = Rows("1:1").Find(What:="Adjusted", After:=Range("A1"), LookIn:=xlFormulas, _
        LookAt:=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlNext, _
        MatchCase:=False, SearchFormat:=False).Column

'   Delete columns in between
    If adjCol - startCol > 1 Then
        Range(Cells(1, startCol + 1), Cells(1, adjCol - 1)).EntireColumn.Delete
    End If
    
End Sub
 
Upvote 0
Yes, that makes a huge difference. A cell populated with that value and a named range are two entirely different things.
I think this will do what you want:
Code:
Sub MyDelete()

    Dim startCol As Long
    Dim adjCol As Long
    
'   Find Start column
    startCol = Rows("1:1").Find(What:="Start", After:=Range("A1"), LookIn:=xlFormulas, _
        LookAt:=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlNext, _
        MatchCase:=False, SearchFormat:=False).Column
        
'   Find Adjusted column
    adjCol = Rows("1:1").Find(What:="Adjusted", After:=Range("A1"), LookIn:=xlFormulas, _
        LookAt:=xlPart, SearchOrder:=xlByRows, SearchDirection:=xlNext, _
        MatchCase:=False, SearchFormat:=False).Column

'   Delete columns in between
    If adjCol - startCol > 1 Then
        Range(Cells(1, startCol + 1), Cells(1, adjCol - 1)).EntireColumn.Delete
    End If
    
End Sub
Thank you..it is working..
Thanks everyone!!!
 
Upvote 0
You are welcome.
Give Rick enough time, and he will probably come up with code that is much more concise than mine!;)
 
Last edited:
Upvote 0
Give Rick enough time, and he will probably come up with code that is much more concise than mine!;)
Not sure this would be considered more concise (is has more lines of code), but here is another macro that you can try...
Code:
Sub DeleteBetweenStartAndAdjusted()
  Dim A As Long, S As Long, C As Long, Row1 As Variant
  Row1 = Range("A1", Cells(1, Columns.Count).End(xlToLeft))
  For C = 1 To UBound(Row1, 2)
    If Row1(1, C) = "Start" Then S = C + 1
    If Row1(1, C) = "Adjusted" Then A = C - 1
  Next
  Range(Columns(S), Columns(A)).Delete
End Sub
 
Last edited:
Upvote 0

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