Formula development help

mech contractor

New Member
Joined
Sep 24, 2008
Messages
10
[TABLE="width: 500"]
<TBODY>[TR]
[TD]Total Lin Ft[/TD]
[TD]Wk-1[/TD]
[TD]Wk-2[/TD]
[TD]Wk-3[/TD]
[TD]Wk-4[/TD]
[TD]Wk-5[/TD]
[TD]Wk-6[/TD]
[TD]Production LF Over Under[/TD]
[/TR]
[TR]
[TD]300[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]400[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]200[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]1120[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD][/TD]
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[/TR]
[TR]
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[TD][/TD]
[/TR]
[TR]
[TD]I just can’t seem to develop a formula for this; any help would be much appreciated.
<o:p> </o:p>
I am trying to develop a production / installation tracking sheet given a total linear footage of material to be installed in 6 weeks.
<o:p> </o:p>
The formula will need to be based on installation footages, wk-1, then Wk-2 up to 6 weeks. Based on the average linear feet installed each week I need the productivity column to indicate given the averages each week what is the linear footage that will be either ahead or behind at 6 weeks
<o:p> </o:p>
Thanks much all
[/TD]
[TD][/TD]
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[TD][/TD]
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[TD][/TD]
[/TR]
</TBODY>[/TABLE]
 

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When they said...
When they said you are going to "Excel at life", they meant you "will be doing Excel your whole life".
No worries, glad it helped. By the way use this formula if your using mine.

Small fix:

=SUM($F5:OFFSET($F5,,COUNT($F5:$K5)-1))/COUNT($F5:$K5)*6-$D5
 
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