Find the all rows number of the each pattern

Kishan

Well-known Member
Joined
Mar 15, 2011
Messages
1,648
Office Version
  1. 2010
Platform
  1. Windows
Using Excel 2000</SPAN></SPAN>

Hi,</SPAN></SPAN>

I want to find the all rows number of the each pattern</SPAN></SPAN>

Below example shows the row numbers only for first 2 patterns, it is difficult to find manually.</SPAN></SPAN>

Please need VBA help?</SPAN></SPAN>

Result</SPAN></SPAN> data example</SPAN></SPAN></SPAN>


Book1
ABCDEFGHIJKLMNOPQRSTUVWXYZAAABACADAEAFAGAHAI
1Cycle1
2CycleX
3Cycle2
4Next Delay-->
5EM1|1|11|1|X1|1|21|X|11|X|X1|X|21|2|11|2|X1|2|2X|1|1X|1|XX|1|2X|X|1X|X|XX|X|2X|2|1X|2|XX|2|22|1|12|1|X2|1|22|X|12|X|X2|X|22|2|12|2|X2|2|2
6X|1|21626
71|X|22032
81|X|12257
91|X|12359
10X|1|X2468
11X|X|X4872
122|X|150
13X|1|X51
141|X|X52
15X|2|X55
161|1|161
171|2|163
181|X|X64
191|X|X71
201|1|1
21X|1|2
221|1|1
231|1|1
241|1|1
251|2|2
261|1|X
27X|X|X
28X|2|1
291|X|2
302|1|X
311|X|1
321|1|X
332|1|X
34X|1|1
351|2|1
36X|1|1
372|X|1
381|X|2
39X|1|X
401|X|X
411|X|1
421|2|1
43X|1|1
442|X|X
45X|2|1
461|X|X
47X|X|1
481|1|1
49X|X|1
501|1|1
511|1|1
521|1|1
532|X|1
541|X|X
551|1|1
56X|1|1
571|1|X
581|2|2
591|1|X
601|2|2
611|1|1
622|1|1
631|1|1
641|1|1
651|2|1
661|2|2
671|1|1
681|1|X
691|X|1
70X|1|1
711|1|1
721|1|X
731|X|X
74X|X|1
751|1|2
76
77
Sheet1


Thank you in advance</SPAN></SPAN>

Regards,</SPAN>
Kishan</SPAN>
 
Last edited:

Excel Facts

How to create a cell-sized chart?
Tiny charts, called Sparklines, were added to Excel 2010. Look for Sparklines on the Insert tab.
Try this:-

Code:
[COLOR="Navy"]Sub[/COLOR] MG01Sep27
[COLOR="Navy"]Dim[/COLOR] Rng [COLOR="Navy"]As[/COLOR] Range, Dn [COLOR="Navy"]As[/COLOR] Range, n [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]Long,[/COLOR] Sp [COLOR="Navy"]As[/COLOR] Variant
[COLOR="Navy"]Set[/COLOR] Rng = Range(Range("C6"), Range("C" & Rows.Count).End(xlUp))
[COLOR="Navy"]With[/COLOR] CreateObject("scripting.dictionary")
.CompareMode = vbTextCompare
[COLOR="Navy"]For[/COLOR] [COLOR="Navy"]Each[/COLOR] Dn [COLOR="Navy"]In[/COLOR] Rng
    [COLOR="Navy"]If[/COLOR] Not .exists(Dn.Value) [COLOR="Navy"]Then[/COLOR]
        .Add Dn.Value, Dn.Row
    [COLOR="Navy"]Else[/COLOR]
        .Item(Dn.Value) = .Item(Dn.Value) & ", " & Dn.Row
    [COLOR="Navy"]End[/COLOR] If
[COLOR="Navy"]Next[/COLOR]

[COLOR="Navy"]Set[/COLOR] Rng = Range("E5", Cells(5, Columns.Count).End(xlToLeft))
    [COLOR="Navy"]For[/COLOR] [COLOR="Navy"]Each[/COLOR] Dn [COLOR="Navy"]In[/COLOR] Rng
        [COLOR="Navy"]If[/COLOR] .exists(Dn.Value) [COLOR="Navy"]Then[/COLOR]
            Sp = Split(.Item(Dn.Value), ", ")
            Dn.Offset(1).Resize(UBound(Sp) + 1).Value = Application.Transpose(Sp)
        [COLOR="Navy"]End[/COLOR] If
    [COLOR="Navy"]Next[/COLOR] Dn
[COLOR="Navy"]End[/COLOR] [COLOR="Navy"]With[/COLOR]
[COLOR="Navy"]End[/COLOR] [COLOR="Navy"]Sub[/COLOR]
Regards Mick
 
Upvote 0
Try this:-

Code:
[COLOR=navy]Sub[/COLOR] MG01Sep27
[COLOR=navy]Dim[/COLOR] Rng [COLOR=navy]As[/COLOR] Range, Dn [COLOR=navy]As[/COLOR] Range, n [COLOR=navy]As[/COLOR] [COLOR=navy]Long,[/COLOR] Sp [COLOR=navy]As[/COLOR] Variant
[COLOR=navy]Set[/COLOR] Rng = Range(Range("C6"), Range("C" & Rows.Count).End(xlUp))
[COLOR=navy]With[/COLOR] CreateObject("scripting.dictionary")
.CompareMode = vbTextCompare
[COLOR=navy]For[/COLOR] [COLOR=navy]Each[/COLOR] Dn [COLOR=navy]In[/COLOR] Rng
    [COLOR=navy]If[/COLOR] Not .exists(Dn.Value) [COLOR=navy]Then[/COLOR]
        .Add Dn.Value, Dn.Row
    [COLOR=navy]Else[/COLOR]
        .Item(Dn.Value) = .Item(Dn.Value) & ", " & Dn.Row
    [COLOR=navy]End[/COLOR] If
[COLOR=navy]Next[/COLOR]

[COLOR=navy]Set[/COLOR] Rng = Range("E5", Cells(5, Columns.Count).End(xlToLeft))
    [COLOR=navy]For[/COLOR] [COLOR=navy]Each[/COLOR] Dn [COLOR=navy]In[/COLOR] Rng
        [COLOR=navy]If[/COLOR] .exists(Dn.Value) [COLOR=navy]Then[/COLOR]
            Sp = Split(.Item(Dn.Value), ", ")
            Dn.Offset(1).Resize(UBound(Sp) + 1).Value = Application.Transpose(Sp)
        [COLOR=navy]End[/COLOR] If
    [COLOR=navy]Next[/COLOR] Dn
[COLOR=navy]End[/COLOR] [COLOR=navy]With[/COLOR]
[COLOR=navy]End[/COLOR] [COLOR=navy]Sub[/COLOR]
Regards Mick
Hi Mick, it is just amazing, perfect results!!</SPAN></SPAN>

Thank you for quick response, solved totally
</SPAN></SPAN>

Have a great weekend
</SPAN></SPAN>

Kind Regards,
</SPAN></SPAN>
Kishan :)
</SPAN></SPAN>
 
Upvote 0

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