That works perfectly.
Let's throw in some more complexity. I have the logic, but think I am missing something in syntax.
I am adding a third column. This column is numbers. I want to take the highest number and give the "value" column a number (ie: "3"), but if there are duplicates in this new column, I want to find the value closest to zero (negative or positive) from the original first column.
Ie
| A | B | C |
------------------
| 10 | -1 | 3 |
| 9 | 2 | |
| 7 | 5 | |
| 10 | 1 | 3 |
| 8 | 8 | |
| 5 | 10 | |
Make sense?
I figured this would do it, but must be missing something:
=IF(A3>0,(IF(A3=LARGE(A3:A32, 1),(IF(B3=MIN(B$3:B$32),10,"0")),"0")),"0")