Extract string of numbers

carlmov

New Member
Joined
Jun 23, 2017
Messages
16
Hello all,
I want to extract numbers using ONLY formula not text to column as follows:
[TABLE="width: 500, align: left"]
<tbody>[TR]
[TD]1,2,12,14,15[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]3,5,6,10,18,22[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
[TR]
[TD]8,17,32,45[/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[TD][/TD]
[/TR]
</tbody>[/TABLE]





I have either 1 or 2 digit numbers not more. I tried Left, mid, and right with find and substitute using columns as the variable (+1 and -) for increments, but didn't get it right altogether.

Kindly, can you give a robust formula.
Thank you and all the best for 2018,
carlo
 

Excel Facts

Which lookup functions find a value equal or greater than the lookup value?
MATCH uses -1 to find larger value (lookup table must be sorted ZA). XLOOKUP uses 1 to find values greater and does not need to be sorted.
Hello,

Lets assume your string of numbers lives in column A, starting in cells A1. Paste this formula in B1 and copy it to the range B1:J3:
=IFERROR(IFERROR(IF(FIND(" ",SUBSTITUTE($A1,","," ",COLUMN(B:B)-1))=2,LEFT($A1,1),SUBSTITUTE(MID($A1,FIND(" ",SUBSTITUTE($A1,","," ",COLUMN(B:B)-1))-2,2),",","")),MID($A1,FIND(" ",SUBSTITUTE($A1,","," ",COLUMN(B:B)-2))+1,2)),"")

For this string "1,2,12,14,15" in A1 your result will be as follows:
B1= 1
C1= 2
D1= 12
E1= 14
F1=15

Let me know if this works and if you have any questions.
 
Upvote 0
Maybe:

ABCDEFGH

<tbody>
[TD="align: center"]1[/TD]
[TD="align: right"]1,2,12,14,15[/TD]
[TD="align: right"]1[/TD]
[TD="align: right"]2[/TD]
[TD="align: right"]12[/TD]
[TD="align: right"]14[/TD]
[TD="align: right"]15[/TD]

[TD="align: center"]2[/TD]
[TD="align: right"]3,5,6,10,18,22[/TD]
[TD="align: right"]3[/TD]
[TD="align: right"]5[/TD]
[TD="align: right"]6[/TD]
[TD="align: right"]10[/TD]
[TD="align: right"]18[/TD]
[TD="align: right"]22[/TD]

[TD="align: center"]3[/TD]
[TD="align: right"]8,17,32,45[/TD]
[TD="align: right"]8[/TD]
[TD="align: right"]17[/TD]
[TD="align: right"]32[/TD]
[TD="align: right"]45[/TD]

</tbody>
Sheet7

[TABLE="width: 85%"]
<tbody>[TR]
[TD]Worksheet Formulas[TABLE="width: 100%"]
<tbody>[TR]
[TH]Cell[/TH]
[TH="align: left"]Formula[/TH]
[/TR]
[TR]
[TH]B1[/TH]
[TD="align: left"]=IFERROR(TRIM(LEFT(SUBSTITUTE(MID(","&$A1&",",FIND("|",SUBSTITUTE(","&$A1&",",",","|",COLUMN(B1)-1))+1,LEN($A1)),",",REPT(" ",LEN($A1))),LEN($A1)))+0,"")[/TD]
[/TR]
</tbody>[/TABLE]
[/TD]
[/TR]
</tbody>[/TABLE]


One more way, shorter, but not fully tested. It does work on the sample above though:

B1: =IFERROR(MID(SUBSTITUTE(","&$A1,",",REPT(" ",99)),(COLUMN(B1)-1)*99,99)+0,"")
 
Last edited:
Upvote 0
Another way :

=TRIM(MID(SUBSTITUTE(","&REPLACE($A1,LOOKUP(1,-MID($A1,ROW($A$1:$A$200),1),ROW($A$1:$A$200))+1,,","),",",REPT(" ",200)),200*COLUMNS($A:A),200))
 
Upvote 0

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