Expected End of Statement and Syntax for User Defined Function

SBF12345

Well-known Member
Joined
Jul 26, 2014
Messages
614
Greetings,

I am currently receiving a Expected End of Statement Error on the following line.

Code:
wkbk_LO.Worksheets(c).Range(Cells(g, "A")).value = "=INDEX(PERSONAL.XLS!LOGIT([LOGREG_INPUT.xls].worksheets(c).Range(cells(2,"B"),cells(g,"B")), [LOGREG_INPUTS.xls].worksheets(c).Range(cells(2,"D"),cells(h,"I")),0.8,TRUE,TRUE),ROW(A1),COLUMN(A1))"

The user defined function includes the following variables:

Code:
Function Logit(known_y As Range, known_x As Range, Cutoff As Double, Optional Constant As Boolean = True, Optional Stats = False)

and outputs an "output" array:

Code:
ReDim output(1 To 26, 1 To M + 1) As Variant

My question is how the user defined function should appear in a vba subroutine to produce output of the size shown above. I suspect that the INDEX statement will need to show a range of cells instead of ROW(A1), COLUMN(A1).

Thanks
 

Excel Facts

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Press Alt+Enter to move to a new row in a cell. Lets you control where the words wrap.
Without trying to decipher your function to see if there are any other problems, I do note that you need to double up your internal quote marks within the quote marks delimiting your text constant...
Code:
[table="width: 500"]
[tr]
	[td]wkbk_LO.Worksheets(c).Range(Cells(g, "A")).value = "=INDEX(PERSONAL.XLS!LOGIT([LOGREG_INPUT.xls].worksheets(c).Range(cells(2,"[B][COLOR="#FF0000"]"[/COLOR][/B]B[B][COLOR="#FF0000"]"[/COLOR][/B]"),cells(g,"[B][COLOR="#FF0000"]"[/COLOR][/B]B[B][COLOR="#FF0000"]"[/COLOR][/B]")), [LOGREG_INPUTS.xls].worksheets(c).Range(cells(2,"[B][COLOR="#FF0000"]"[/COLOR][/B]D[B][COLOR="#FF0000"]"[/COLOR][/B]"),cells(h,"[B][COLOR="#FF0000"]"[/COLOR][/B]I[B][COLOR="#FF0000"]"[/COLOR][/B]")),0.8,TRUE,TRUE),ROW(A1),COLUMN(A1))"[/td]
[/tr]
[/table]
 
Last edited:
Upvote 0
Thanks, I am unfamiliar with the rules surrounding the use of double quotation marks. I would not have guessed they were required in this case!

As for the function, it seems to be running smoothly.
 
Upvote 0
Thanks, I am unfamiliar with the rules surrounding the use of double quotation marks.
When you have a text constant (a bunch of characters with a quote mark on each end), you must double up each internal quote mark... this tell VB that the quote mark is a character in the text... if you only put a single internal quote mark, VB thinks that is the end of the text constant and then gets confused at all the characters that follow it.
 
Upvote 0
Thank you, I'll remember there are special rules surrounding text constants next time they find their way into a script.
 
Upvote 0

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