Excel Color Picker

[Formula11]

Calling up a font colour picker with VBA doesn't seem to work (using "Application.Dialogs(xlDialogColorPalette).Show").
A good method is given here: Excel Color Picker - Collection of VBA Code Snippets and Useful Excel Knowledge.
I don't know how to call the procedure, given that arguments are required. I tried a couple of ways as follows but neither worked. Where am I going wrong?

Sub Test1()
Color2RGB 256, 256, 256, 256
End Sub

Sub Test2()
Call Color2RGB (256, 256, 256, 256)
End Sub

 

[thisoldman]

The first argument to Application.Dialogs(xlDialogEditColor).Show() must be an integer between 1 and 56.

The next three arguments must be integers between 0 and 255. These are the three RGB values.

Perhaps this tutorial will help: http://wellsr.com/vba/2016/excel/Show-Color-Palette-Dialog-Box-with-VBA-xlDialogEditColor/

It explains the color palette better than I could.

 

[Formula11]

Thank-you thisoldman.
The instructions for "Application.Dialogs(xlDialogColorPalette).Show" in the above link still do not work. I don't think it can be done.
It looks like the link in my original post is for interior cell colour as well.
I actually needed something for the font, ie "Application.Dialogs(xlDialogColorPalette).Show".
Never mind.

 

[thisoldman]

I looked into this a bit more. This code brings up the custom color dialog and changes the font color to the user selection. If the user cancels, font color is unchanged. The procedure works but I did not thoroughly test it.

Sub UserChangeFontColor()
' Allow user to change the font color of the selected range.
    Dim userColor As Long
    Dim res As Integer
    
    res = Application.Dialogs(xlDialogEditColor).Show(12, 127, 127, 127)
    
    ' The arg of .Colors() must be the same as first arg of .Show(), above.
    userColor = ThisWorkbook.Colors(12)
    Selection.Font.Color = userColor
End Sub

 

[Formula11]

Breakthrough finally.
Cheers.