Deactivate connectors from shapes

Doflamingo

Board Regular
Joined
Apr 16, 2019
Messages
238
Hi all :)

Does anyone know a VBA code that would allow me to deactivate connectors from shapes.

Here see an example

https://www.dropbox.com/s/e7m5qdre9m1riwp/Untitled.png?dl=0

Because what I would like is to turn the shapes at 180 degrees without moving the connectors. That's why I'm looking for how to deactivate connectors from the shapes, rotate the shapes and then reconnect the connectors to the shapes

Thanks for your help :)

Any ideas is welcomed
 

Excel Facts

Format cells as time
Select range and press Ctrl+Shift+2 to format cells as time. (Shift 2 is the @ sign).
I haven't looked at your file, but you can use the BeginDisconnect and EndDisconnect methods...

Code:
    conn.ConnectorFormat.BeginDisconnect
    conn.ConnectorFormat.EndDisconnect

...where conn is a variable that represents a connector shape.

Hope this helps!
 
Upvote 0
Hi Domenic, thanks for your prompt reply

Here is the code to create shapes linked with connectors

Code:
Sub créeShape(parent, niv, Attribut, coul) ' procédure récursive
  hauteurshape = 48
  largeurshape = 92
  colonne = colonne + 1
  'Forme des éléments
  forga.Shapes.AddShape(msoShapeRectangle, 10, 10, largeurshape, hauteurshape).Name = parent
  forga.Shapes(parent).Line.ForeColor.SchemeColor = 0
  txt = parent & vbLf & Attribut
  With forga.Shapes(parent)
    .TextFrame.Characters.Text = txt
    'taille de la police
    .TextFrame.Characters(Start:=1, Length:=1000).Font.Size = 10
    .TextFrame.Characters(Start:=1, Length:=1000).Font.ColorIndex = 0
    .TextFrame.Characters(Start:=1, Length:=Len(parent)).Font.Bold = True
    'couleur de la police
    .TextFrame.Characters(Start:=1, Length:=Len(parent)).Font.ColorIndex = 1
    'couleur intérieur des formes
    .Fill.ForeColor.RGB = coul
    '.Fill.ForeColor.RGB = RGB(255, 0, 0)
  End With
  forga.Shapes(parent).Left = débutOrg.Left + inth * colonne
  forga.Shapes(parent).Top = débutOrg.Top + intv * (niv - 1)
  For i = 1 To n
    If Tbl(i, 1) = parent And niv > 1 Then
      shapePère = Tbl(i, 2)
      'forga.Shapes.AddConnector(msoConnectorElbow, 100, 100, 100, 100).Name = parent & "c"
      forga.Shapes.AddConnector(msoConnectorElbow, 0, 0, 100, 100).Name = parent & "c"
      forga.Shapes(parent & "c").Line.ForeColor.SchemeColor = 0
      forga.Shapes(parent & "c").ConnectorFormat.BeginConnect forga.Shapes(shapePère), 3
      forga.Shapes(parent & "c").ConnectorFormat.EndConnect forga.Shapes(parent), 1
   End If
   If Tbl(i, 2) = parent Then créeShape Tbl(i, 1), niv + 1, Tbl(i, 3), f.Cells(i + 1, 1).Interior.Color
  Next i
End Sub

And here is the macro to run the previous code


Code:
Dim colonne, débutOrg, f, forga, inth, intv, Tbl(), n
Sub DessineOrga()
   Set forga = Sheets("Structure Chart")
   Set f = Sheets("Data")
   Tbl = f.Range("A2:C" & f.[A65000].End(xlUp).Row).Value
   n = UBound(Tbl)
   For Each S In forga.Shapes
    If S.Type = 17 Or S.Type = 1 Then S.Delete
   Next
   inth = 70
   intv = 60
   colonne = 0
   Set débutOrg = forga.Range("o4")
   'décide de la couleur de l'entité mother dans feuille data
   créeShape Tbl(1, 1), 1, Tbl(1, 3), f.Cells(2, 1).Interior.Color
End Sub

As you can see, that code can create as many connectors than there are shapes and the connectors used are ''msoconnectorelbow"

I'm going to see if I can adapt the line you gave me to the variables of that code

thanks again @Domenic
 
Upvote 0

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