Counting unique records with multiple criteria

gigimarga

New Member
Joined
Oct 25, 2010
Messages
18
Office Version
  1. 2016
Hi All,

I have the following dataset and I want the final answer to be a number of unique counts of "Record#", based on criteria 1=Variable1,"AAAA" and criteria 2=Variable2,"123". The two criteria are set as lists in a separate worksheet, so when the user selects variable 1 and variable 2, the result (formula) returns a value in a separate summary table. In the example here - based on the stipulated criteria (criteria 1=Variable1,"AAAA" and criteria 2=Variable2,"123") the value would be 2. Thanks in advance.

Record#Variable1Variable2
1AAAA123
1AAAB123
1AAAA123
2AAAA234
2AAAC234
3AAAA123
4AAAA456
 
Using Peter's layout, try:

Book2
A
1Unique Count
22
Sheet3
Cell Formulas
RangeFormula
A2A2=SUM(SIGN(FREQUENCY(IF((Sheet1!B2:B8=Sheet2!A2)*(Sheet1!C2:C8=Sheet2!B2),MATCH(Sheet1!A2:A8,Sheet1!A2:A8,0)),ROW(Sheet1!A2:A8)-ROW(Sheet1!A2)+1)))
Press CTRL+SHIFT+ENTER to enter array formulas.
 
Upvote 0

Excel Facts

What did Pito Salas invent?
Pito Salas, working for Lotus, popularized what would become to be pivot tables. It was released as Lotus Improv in 1989.
Another option to consider.

gigimarga.xlsm
A
1Unique Count
22
Sheet3
Cell Formulas
RangeFormula
A2A2=COUNT(1/(MATCH(Sheet1!A2:A8&"|"&Sheet2!A2&"|"&Sheet2!B2,Sheet1!A2:A8&"|"&Sheet1!B2:B8&"|"&Sheet1!C2:C8,0)=ROW(Sheet1!A2:A8)-ROW(Sheet1!A2)+1))
Press CTRL+SHIFT+ENTER to enter array formulas.
 
Upvote 0

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