Count how many names in each column for random output

youbitto

New Member
Joined
Jun 8, 2022
Messages
34
Office Version
  1. 2019
  2. 2016
  3. 2013
Platform
  1. Windows
I have two sheets


first is "Inscrp" where I put the names depending on categories in different columns Second is "Tirage" where I see random names appears from each category


HowMany = 5 in the code represent the number of names to be picked randomly The problem when I write less than 5 names the result would be empty.


I want the names to be picked randomly regardless of their number and prevent Hardcoding the "HowMany"


This is the code for it

VBA Code:
Sub PickNamesAtRandom()
 Dim shI As Worksheet, lastR As Long, shT As Worksheet, HowMany As Long
 Dim rndNumber As Integer, Names() As String, i As Long, CellsOut As Long

 HowMany = 5: CellsOut = 8
 Set shI = Worksheets("Inscrp")
 Set shT = Worksheets("Tirage")

 Dim col As Long, arrCol, filt As String, nrCol As Long
 nrCol = shT.Cells(4, 8) 'number of columns to be returned. It can be changed and also be calculated...

 For col = 1 To nrCol
 
  
    lastR = shI.Cells(shI.Rows.Count, col).End(xlUp).Row 'last row in column to be processed
    
    If lastR >= HowMany + 2 Then  '+ 2 because the range is build starting with the third row...
        arrCol = Application.Transpose(shI.Range(shI.Cells(3, col), shI.Cells(lastR, col)).Value2) 'place the range in a 1D array
       
        ReDim Names(1 To HowMany) 'Set the array size to how many names required
        For i = 1 To UBound(Names)
tryAgain:
            Randomize
            rndNumber = Int((UBound(arrCol) - LBound(arrCol) + 1) * Rnd + LBound(arrCol))
            If arrCol(rndNumber) = "" Then GoTo tryAgain
            Names(i) = arrCol(rndNumber)
            filt = arrCol(rndNumber) & "##$$@": arrCol(rndNumber) = filt
            arrCol = Filter(arrCol, filt, False)   'eliminate the already used name from the array
        Next i
        shT.Cells(CellsOut, col).Resize(UBound(Names), 1).Value2 = Application.Transpose(Names)
    End If
 Next col
 MsgBox "Ready..."
End Sub

Like this it returns only 5 names randomly from each filled column


Illustration :


In this case the column B in "Tirage" return empty because the HowMany I assigned is 5 names

------------------------------------Sheet1"Inscrp"-------------------------------------------------------------------------------------Sheet2"Tirage"

A​
B​
A​
B​
John​
Simon​
David​
"Nothing"​
David​
Gerard​
Steve​
Jacob​
Herald​
john​
Steve​
Paul​
Sara​
Sara​
Jacob​
This is how I want it :
------------------------------------Sheet1"Inscrp"-------------------------------------------------------------------------------------Sheet2"Tirage"
A​
B​
A​
B​
John​
Simon​
David​
Gerard​
David​
Gerard​
Steve​
Paul​
Jacob​
Herald​
john​
Simon​
Steve​
Paul​
Sara​
Herald​
Sara​
Jacob​
 

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So you don't want those empty cells?

Try this:

VBA Code:
Sub PickNamesAtRandom_2()
  Dim sh1 As Worksheet, sh2 As Worksheet
  Dim nrCol As Long, i As Long, j As Long, x As Long, lr As Long
  Dim arr As Variant, y As Variant

  Set sh1 = Worksheets("Inscrp")
  Set sh2 = Worksheets("Tirage")
 
  nrCol = sh2.Range("H4").Value
  Randomize
 
  For j = 1 To nrCol
    lr = sh1.Cells(Rows.Count, j).End(3).Row
    If lr > 3 Then
      arr = sh1.Range(sh1.Cells(3, j), sh1.Cells(lr, j)).SpecialCells(xlCellTypeConstants).Value
      For i = 1 To UBound(arr, 1)
        x = Int(UBound(arr) * Rnd + 1)
        y = arr(x, 1)
        arr(x, 1) = arr(i, 1)
        arr(i, 1) = y
      Next
      sh2.Cells(8, j).Resize(UBound(arr, 1)).Value = arr
    End If
  Next
End Sub
Thank you very much, that's awesome
 
Upvote 0

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