Count "0" and "1" in a single cell separated by vertical bar

K

Kishan

Well-known Member
Joined
Mar 15, 2011
Messages
1,648
Office Version
  1. 2010
Platform
  1. Windows
Using Excel 2000</SPAN></SPAN>
Hi,</SPAN></SPAN>

Data in columns C:P, need to count "0" and "1" in a single cell separated by vertical bar in the column R </SPAN></SPAN>

Example data</SPAN></SPAN>


Book1
ABCDEFGHIJKLMNOPQRST
1
2
3
4
5P1P2P3P4P5P6P7P8P9P10P11P12P13P14EMCount 0 And 1
60000000000000014
7000100110100113 | 1 | 2 | 2 | 1 | 1 | 2 | 2
801110101001101u
9011001011001111 | 2 | 2 | 1 | 1 | 2 | 2 | 3
10101011011000111 | 1 | 1 | 2 | 1 | 2 | 3 | 2
11000000110111106 | 2 | 1 | 4 | 1
12011011101101011 | 2 | 1 | 3 | 1 | 2 | 1 | 1 | 1 | 1
13100010111011011 | 3 | 1 | 1 | 3 | 1 | 2 | 1 | 1
14111000010010003 | 4 | 1 | 2 | 1 | 3
15100111110110011 | 2 | 5 | 1 | 2 | 2
16010010000111001 | 1 | 2 | 1 | 4 | 3 | 2
17110101011101012 | 1 | 1 | 1 | 1 | 1 | 3 | 1 | 1 | 1 | 1
18111110111000115 | 1 | 3 | 3 | 2
19011001111011001 | 2 | 2 | 4 | 1 | 2 | 2
20111101001001004 | 1 | 1 | 2 | 1 | 2 | 1 | 2
21111001101011013 | 2 | 2 | 1 | 1 | 1 | 2 | 1 | 1
22010110111011101 | 1 | 1 | 2 | 1 | 3 | 1 | 3 | 1
23111110110100015 | 1 | 2 | 1 | 1 | 3 | 1
24011011011011101 | 2 | 1 | 2 | 1 | 2 | 1 | 3 | 1
25111101111111114 | 1 | 9
26011110110011011 | 4 | 1 | 2 | 2 | 2 | 1 | 1
27100000101110111 | 5 | 1 | 1 | 3 | 1 | 2
28111010000010103 | 1 | 1 | 5 | 1 | 1 | 1 | 1
29111001010101003 | 2 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 2
30111011101101103 | 1 | 3 | 1 | 2 | 1 | 2 | 1
31111011111111113 | 1 | 10
32101101100010011 | 1 | 2 | 1 | 2 | 3 | 1 | 2 | 1
33001101001001012 | 2 | 1 | 1 | 2 | 1 | 2 | 1 | 1 | 1
34101011111101011 | 1 | 1 | 1 | 6 | 1 | 1 | 1
35011100100110011 | 3 | 2 | 1 | 2 | 2 | 2 | 1
36100011001101001 | 3 | 2 | 2 | 2 | 1 | 1 | 2
37011111111000001 | 8 | 5
38001100111001112 | 2 | 2 | 3 | 2 | 3
39010101000001101 | 1 | 1 | 1 | 1 | 1 | 5 | 2 | 1
40111001001010013 | 2 | 1 | 2 | 1 | 1 | 1 | 2 | 1
41000110111100113 | 2 | 1 | 4 | 2 | 2
42000101011010013 | 1 | 1 | 1 | 1 | 2 | 1 | 1 | 2 | 1
43001001011111012 | 1 | 2 | 1 | 1 | 5 | 1 | 1
44001011110101102 | 1 | 1 | 4 | 1 | 1 | 1 | 2 | 1
45110110111110112 | 1 | 2 | 1 | 5 | 1 | 2
46111100011111014 | 3 | 5 | 1 | 1
47001111101111012 | 5 | 1 | 4 | 1 | 1
48101001011111111 | 1 | 1 | 2 | 1 | 1 | 7
49010101010000011 | 1 | 1 | 1 | 1 | 1 | 1 | 1 | 5 | 1
50011110111111101 | 4 | 1 | 7 | 1
51010110001000111 | 1 | 1 | 2 | 3 | 1 | 3 | 2
52011100111111001 | 3 | 2 | 6 | 2
53011000111110001 | 2 | 3 | 5 | 3
54010010001001001 | 1 | 2 | 1 | 3 | 1 | 2 | 1 | 2
55000101101101013 | 1 | 1 | 2 | 1 | 2 | 1 | 1 | 1 | 1
561111111111111114
57
58
Sheet1


Thank you in advance</SPAN></SPAN>

Regards,</SPAN>
Kishan</SPAN></SPAN>
 
Last edited:

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Create a module in VBA and put in the following code:

Code: 
Function CountGroups(Rng As Range)

Dim Cel As Range
Dim output As String
Dim CheckValue As String
Dim Counter As Integer
Counter = 0
output = ""
CheckValue = Rng(1).Value
For Each Cel In Rng
    If CheckValue = Cel.Value Then
        Counter = Counter + 1
    Else
        CheckValue = Cel.Value
        If Len(output) > 0 Then
            output = output & "|" & Counter
        Else
            output = Counter
        End If
        Counter = 1
    End If
Next
        If Len(output) > 0 Then
        output = output & "|" & Counter
        Else
           output = Counter
        End If
CountGroups = output
End Function

And then in the cell you want you can use this formula:

Code: 
=Countgroups(C1:P1)

This will work for any values and any range.
 
Upvote 0
Puertorekinsam said:
Create a module in VBA and put in the following code:

Code: 
Function CountGroups(Rng As Range)

End Function

And then in the cell you want you can use this formula:

Code: 
=Countgroups(C1:P1)

This will work for any values and any range.
Click to expand...
Hi, Puertorekinsam thank you for the Function it is giving a result as request and as you said it works perfect for any values and any range too.</SPAN></SPAN>

I do appreciate your kind help. Just a question could it be made a macro, why? Because the functions are always active and do not live the values.</SPAN></SPAN>

Thank you

Kind Regards,</SPAN></SPAN>
Kishan</SPAN></SPAN>
 
Upvote 0
Try this for all results in column "R":-
Code: 
[COLOR="Navy"]Sub[/COLOR] MG23Oct05
[COLOR="Navy"]Dim[/COLOR] Rng [COLOR="Navy"]As[/COLOR] Range, Dn [COLOR="Navy"]As[/COLOR] Range, Ac [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]Long,[/COLOR] c [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]Long,[/COLOR] nStr [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]String[/COLOR]
[COLOR="Navy"]Dim[/COLOR] Temp [COLOR="Navy"]As[/COLOR] [COLOR="Navy"]String[/COLOR]
[COLOR="Navy"]Set[/COLOR] Rng = Range("C6", Range("C" & Rows.Count).End(xlUp))
[COLOR="Navy"]For[/COLOR] [COLOR="Navy"]Each[/COLOR] Dn [COLOR="Navy"]In[/COLOR] Rng

[COLOR="Navy"]For[/COLOR] Ac = 1 To 14
    [COLOR="Navy"]If[/COLOR] Not Dn(, Ac) = Temp [COLOR="Navy"]Then[/COLOR]
        [COLOR="Navy"]If[/COLOR] c > 0 [COLOR="Navy"]Then[/COLOR]
            nStr = nStr & IIf(nStr = "", c, "|" & c)
            c = 0
        [COLOR="Navy"]End[/COLOR] If
    [COLOR="Navy"]End[/COLOR] If
    c = c + 1: Temp = Dn(, Ac)
[COLOR="Navy"]Next[/COLOR] Ac


[COLOR="Navy"]If[/COLOR] Not Dn(, Ac) = Temp [COLOR="Navy"]Then[/COLOR]
    [COLOR="Navy"]If[/COLOR] c > 0 [COLOR="Navy"]Then[/COLOR]
        nStr = nStr & IIf(nStr = "", c, "|" & c)
        c = 0
    [COLOR="Navy"]End[/COLOR] If
[COLOR="Navy"]End[/COLOR] If

Dn.Offset(, 15).Value = nStr

nStr = "": c = 0
[COLOR="Navy"]Next[/COLOR] Dn
[COLOR="Navy"]End[/COLOR] [COLOR="Navy"]Sub[/COLOR]
Regards Mick
 
Upvote 0
I would keep the function as it is, and call it as a separate sub routine

Code: 
Sub RunTheCode()

Dim i As Integer

i = 1

Do Until Cells(i, 3) = ""
    Cells(i, 18) = CountGroups(Range(Cells(i, 3), Cells(i, 16)))

    i = i + 1
Loop
End Sub
 
Upvote 0
MickG said:
Try this for all results in column "R":-
Code: 
[COLOR=navy]Sub[/COLOR] MG23Oct05
[COLOR=navy]Dim[/COLOR] Rng [COLOR=navy]As[/COLOR] Range, Dn [COLOR=navy]As[/COLOR] Range, Ac [COLOR=navy]As[/COLOR] [COLOR=navy]Long,[/COLOR] c [COLOR=navy]As[/COLOR] [COLOR=navy]Long,[/COLOR] nStr [COLOR=navy]As[/COLOR] [COLOR=navy]String[/COLOR]
[COLOR=navy]Dim[/COLOR] Temp [COLOR=navy]As[/COLOR] [COLOR=navy]String[/COLOR]
[COLOR=navy]Set[/COLOR] Rng = Range("C6", Range("C" & Rows.Count).End(xlUp))
[COLOR=navy]For[/COLOR] [COLOR=navy]Each[/COLOR] Dn [COLOR=navy]In[/COLOR] Rng

[COLOR=navy]For[/COLOR] Ac = 1 To 14
    [COLOR=navy]If[/COLOR] Not Dn(, Ac) = Temp [COLOR=navy]Then[/COLOR]
        [COLOR=navy]If[/COLOR] c > 0 [COLOR=navy]Then[/COLOR]
            nStr = nStr & IIf(nStr = "", c, "|" & c)
            c = 0
        [COLOR=navy]End[/COLOR] If
    [COLOR=navy]End[/COLOR] If
    c = c + 1: Temp = Dn(, Ac)
[COLOR=navy]Next[/COLOR] Ac


[COLOR=navy]If[/COLOR] Not Dn(, Ac) = Temp [COLOR=navy]Then[/COLOR]
    [COLOR=navy]If[/COLOR] c > 0 [COLOR=navy]Then[/COLOR]
        nStr = nStr & IIf(nStr = "", c, "|" & c)
        c = 0
    [COLOR=navy]End[/COLOR] If
[COLOR=navy]End[/COLOR] If

Dn.Offset(, 15).Value = nStr

nStr = "": c = 0
[COLOR=navy]Next[/COLOR] Dn
[COLOR=navy]End[/COLOR] [COLOR=navy]Sub[/COLOR]
Regards Mick
Click to expand...
MickG, I liked the macro solution and it worked Prefect!! </SPAN></SPAN>

Thank you for your time and kind help</SPAN></SPAN>

Kind Regards,</SPAN></SPAN>
Kishan :)</SPAN></SPAN>
 
Upvote 0
Puertorekinsam said:
I would keep the function as it is, and call it as a separate sub routine

Code: 
Sub RunTheCode()

Dim i As Integer

i = 1

Do Until Cells(i, 3) = ""
    Cells(i, 18) = CountGroups(Range(Cells(i, 3), Cells(i, 16)))

    i = i + 1
Loop
End Sub
Click to expand...
Hi, Puertorekinsam I tried putting the "Sub RunTheCode" in the same "Function" module, when I run it do not get any result, and then tried in another module but no results. Don't know what I am doing wrong</SPAN></SPAN>

Please could you check?</SPAN></SPAN>

Thank you</SPAN></SPAN>
Kishan </SPAN></SPAN>

 
Last edited:
Upvote 0
Put the sub in the code for the individual sheet.

Or add "Sheets("NAME OF SHEET")." infront of the word Cells and Range in the sub.
 
Upvote 0
Kishan said:
MickG, I liked the macro solution and it worked Prefect!! </SPAN></SPAN>

Thank you for your time and kind help</SPAN></SPAN>

Kind Regards,</SPAN></SPAN>
Kishan :)</SPAN></SPAN>
Click to expand...
MickG, would you please do a favour I find my mistake row 6 and row 56 the result are 14, but row 6 starting with 0 & the row 56 starting with 1, to make them distinction I want please can you alter a code (just adding a 1st "1" or "0" striating of the each row as shown below</SPAN></SPAN>


Book1
ABCDEFGHIJKLMNOPQRST
1
2
3
4
5P1P2P3P4P5P6P7P8P9P10P11P12P13P14EMCount 0 And 1
6000000000000000 - 14
7000100110100110 - 3|1|2|2|1|1|2|2
8011101010011010 - 1|3|1|1|1|1|2|2|1|1
9011001011001110 - 1|2|2|1|1|2|2|3
10101011011000111 - 1|1|1|1|2|1|2|3|2
11000000110111100 - 6|2|1|4|1
12011011101101010 - 1|2|1|3|1|2|1|1|1|1
13100010111011011 - 1|3|1|1|3|1|2|1|1
14111000010010001 - 3|4|1|2|1|3
15100111110110011 - 1|2|5|1|2|2|1
16010010000111000 - 1|1|2|1|4|3|2
17110101011101011 - 2|1|1|1|1|1|3|1|1|1|1
18111110111000111 - 5|1|3|3|2
19011001111011000 - 1|2|2|4|1|2|2
20111101001001001 - 4|1|1|2|1|2|1|2
21111001101011011 - 3|2|2|1|1|1|2|1|1
22010110111011100 - 1|1|1|2|1|3|1|3|1
23111110110100011 - 5|1|2|1|1|3|1
24011011011011100 - 1|2|1|2|1|2|1|3|1
25111101111111111 - 4|1|9
26011110110011010 - 1|4|1|2|2|2|1|1
27100000101110111 - 1|5|1|1|3|1|2
28111010000010101 - 3|1|1|5|1|1|1|1
29111001010101001 - 3|2|1|1|1|1|1|1|1|2
30111011101101101 - 3|1|3|1|2|1|2|1
31111011111111111 - 3|1|10
32101101100010011 - 1|1|2|1|2|3|1|2|1
33001101001001010 - 2|2|1|1|2|1|2|1|1|1
34101011111101011 - 1|1|1|1|6|1|1|1|1
35011100100110010 - 1|3|2|1|2|2|2|1
36100011001101001 - 1|3|2|2|2|1|1|2
37011111111000000 - 1|8|5
38001100111001110 - 2|2|2|3|2|3
39010101000001100 - 1|1|1|1|1|1|5|2|1
40111001001010011 - 3|2|1|2|1|1|1|2|1
41000110111100110 - 3|2|1|4|2|2
42000101011010010 - 3|1|1|1|1|2|1|1|2|1
43001001011111010 - 2|1|2|1|1|5|1|1
44001011110101100 - 2|1|1|4|1|1|1|2|1
45110110111110111 - 2|1|2|1|5|1|2
46111100011111011 - 4|3|5|1|1
47001111101111010 - 2|5|1|4|1|1
48101001011111111 - 1|1|1|2|1|1|7
49010101010000010 - 1|1|1|1|1|1|1|1|5|1
50011110111111100 - 1|4|1|7|1
51010110001000110 - 1|1|1|2|3|1|3|2
52011100111111000 - 1|3|2|6|2
53011000111110000 - 1|2|3|5|3
54010010001001000 - 1|1|2|1|3|1|2|1|2
55000101101101010 - 3|1|1|2|1|2|1|1|1|1
56111111111111111 - 14
57
58
Sheet2


Thank you</SPAN></SPAN>

Kind Regards,</SPAN></SPAN>
Kishan</SPAN></SPAN>
 
Last edited:
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