Hi friends, to find the maturity amount of a fix deposit we use the following formula:
A = P x (1 + r/n) ^ n*t
“A” =maturity amount.
“P” = investment amount.
“r” = annual interest rates.
“n” = the number of times the interest is compounded. (For instance, n is equal to 4 for quarterly compounding, SBI using it)
“t” = the investment tenure.
If we put a fix deposit Rs. 1,00,000 (P) for 2 years (t), @7.00% (r), in SBI, FD interest is payable quarterly, so n = 12/3 = 4
So A = 100000(1+7%/4)^4*2 = 214,372
Now, my question is if we keep the same fix deposit for 400 days tenure, @ 7.1%, how we calculate the maturity amount
Please help me to find the formula for the same.
Thanks...
A = P x (1 + r/n) ^ n*t
“A” =maturity amount.
“P” = investment amount.
“r” = annual interest rates.
“n” = the number of times the interest is compounded. (For instance, n is equal to 4 for quarterly compounding, SBI using it)
“t” = the investment tenure.
If we put a fix deposit Rs. 1,00,000 (P) for 2 years (t), @7.00% (r), in SBI, FD interest is payable quarterly, so n = 12/3 = 4
So A = 100000(1+7%/4)^4*2 = 214,372
Now, my question is if we keep the same fix deposit for 400 days tenure, @ 7.1%, how we calculate the maturity amount
Please help me to find the formula for the same.
Thanks...
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