Excelestial
Well-known Member
- Joined
- Jan 2, 2009
- Messages
- 828
OOoohhhh.,....30/(1/2)...multiply by 2 to cancel the fraction = 30*2 = 60 + 10 = 70. What kind of math did I do originally??? lol
Divide the nine balls into 3 sets of 3 balls each. Lets call them A, B & C.
Using the weighing scale compare the weights of A & B.
Two outcomes are possible:
1. The heavier ball is present in one of the sets and hence that set will tip. Once we have identified the set which contains the heavier ball, compare 2 balls from the set. Either one of the 2 is the heavier one... or the 3rd one is.
2. Both A & B have the same weight and hence the scales don't tip. So now we know that the heavier ball is in the 3rd set (C). Compare two balls from C like we did in point 1 and either one of the 2 is heavy or the remaining one is heavy.
Okay...#2 question was lame. Throw that one out.
I THINK this approach is only guaranteed to work if you know the odd ball is heavier. But the original question says it COULD be lighter.
You Are Correct!..Well there are many different answers for this one...Two spills make a sea/"C" of wet?
28 WET TO SPILL 40 WET...
I got nothin.