2d array redim problem

ToExcelOrNotToExcel

New Member
Joined
Jan 7, 2023
Messages
13
Office Version
  1. 2019
Platform
  1. Windows
Hello everyone I hav somee code which shold work but it is returning an error code 9 and I have no idea why. It's supposed to loop through a range of cells with strings that look like this: "AM17, 12: ;HM2; AM40; AM45, 13". I'm sure the code works but I don't understand how to solve this error.

Code:
Option Explicit
Sub FillPlayerRating()

    Dim rng As Range, cell As Range
    Dim ArrayCount As Integer
    Dim i As Long
    Set rng = Range("CE3:CE24")
    Dim size_1d As Integer
    
        For Each cell In rng
        Dim arr_1d() As String
        arr_1d = Split(cell.Value, ";")
        size_1d = UBound(arr_1d) - LBound(arr_1d)
        
        Dim arr_2d() As String
        ReDim arr_2d(size_1d, 1) As String
            
            For i = 0 To size_1d
            Dim temp() As String
            temp = Split(arr_1d(i), ",")
            Dim size_temp As Integer
            size_temp = UBound(temp) - LBound(temp) + 1
            If size_temp = 1 Then
                arr_2d(i, 0) = Trim(temp(0))
            ElseIf size_temp = 2 Then
                arr_2d(i, 0) = Trim(temp(0))
                arr_2d(i, 0) = Trim(temp(1))
            End If
            
            Next i
        
        ' Range("CS20").Value = arr()
        Next cell

End Sub
 
When the argument for Split is a zero-length string ( "" ), it returns an empty array with no elements and no data. In this case, UBound returns -1. So let's say the cell is empty, we get the following...

VBA Code:
size_1d = UBound(arr_1d) - LBound(arr_1d)

size_1d = ( -1 ) - ( 0 )

size_1d = -1

...which returns an error when ReDim'ing.
 
Upvote 0

Excel Facts

Last used cell?
Press Ctrl+End to move to what Excel thinks is the last used cell.
Not possible to test/diagnose without some sample data. Also, all variables should be declared.

johnnyL is asking the right question, I eagerly await the answer.
Hi I uploaded a mini-sheet with all the data from CE3: CE24

Betting forula 2022.xlsm
CE
3HM9;AM17;HM30;AM31;AM50;HM60;AM75;AM86;HM96;HM104;AM110;HM126
4AM31,10;AM50,31;HM60,10;AM75,31;AM86;HM96;HM104,87;AM110;HM126
5HA60,58;AA75;AA86;HA96;HA104,76;AA110
6HA9;AA17;HA30,86;AA31;AA50,87;HA60,80;AA75,59;AA86;HA96,18;HA104;AA110,81;HA126
7HA9,37;AA17;HA30,4;AA31,22;AA50,22;HA60,32;AA86,61;HA96,72;HA126
8HM9;AM17,17;HM30,86;AM31;AM50;HM60;AM75;AM86,83;HM104,3;AM110,80;HM126,79
9HD9;AD17,46;AD75,44;AD86;HD96;HD104;AD110;HD126
10HD9;AD17,40;HD30;AD31;AD50;HD80,80;AD75;AD86;HD96;HD104;AD110;HD126
11HD9;AD17;HD30,86;AD31;AD50;HD60;AD75;AD86;HD96;HD104;AD110;HD126
12HA9;AA17,60;HA30,71;AA31,68;AA50,68;HA60,67;AA75,70;HA96;HA104,87;AA110,52
13HM9,78;AM17,44;HM30;AM31;AM50;HM60;AM75,59;AM86,7;HM104,14;AM110,10;HM126,29
14AD17,44;HD30;AD31;AD50;HD60;AD75,46
15AD17,44;HD30;AD31;AD50;HD60;AD75,40;HD96;HD104;AD110,60
16AD75,50;AD86;AD110,30
17HD9;AD17;AD60,9;HD126
18HGK9;AGK17;HGK30;AGK31;AGK50;HGK60;AGK75;AGK86;HGK96;HGK104;AGK110;HGK126
19HA30,44;AA75,31;AA86,29
20HD30,4
21HM9,53;AM17,46;HM30,19;AM50,3;HM60,23;AM75,20;HM96;HM104;AM110,38;HM126,11
22AA17,30;HA30,46;AA31,80;AA50,59;HA104,3;AA110,9;HA126,61
23
24HM9,12;AM17,3;HM30,4
Football
 
Upvote 0
Did you check to see whether size_1d contains a negative value when the error occurs?

Does your range contain one or more empty cells? If so, you should test for it in your loop, for example...

VBA Code:
    For Each cell In Rng
        If Len(cell.Value) > 0 Then
            'your code here
            '
            '
        End If
    Next cell
 
Upvote 0
Solution
When the argument for Split is a zero-length string ( "" ), it returns an empty array with no elements and no data. In this case, UBound returns -1. So let's say the cell is empty, we get the following...

VBA Code:
size_1d = UBound(arr_1d) - LBound(arr_1d)

size_1d = ( -1 ) - ( 0 )

size_1d = -1

...which returns an error when ReDim'ing.
ok i get that but what should i do for my code to work correctly
 
Upvote 0
Did you check to see whether size_1d contains a negative value when the error occurs?

Does your range contain one or more empty cells? If so, you should test for it in your loop, for example...

VBA Code:
    For Each cell In Rng
        If Len(cell.Value) > 0 Then
            'your code here
            '
            '
        End If
    Next cell
I tried this an my code is not giving me the desired results, here is my new code

Code:
Option Explicit
Sub FillPlayerRating()

    Dim rng As Range, cell As Range
    Dim ArrayCount As Integer
    Dim i As Long
    Set rng = Range("CE3:CE24")
    Dim size_1d As Integer
    
        For Each cell In rng
        
            If Len(cell.Value) > 0 Then
                
                Dim arr_1d() As String
                arr_1d = Split(cell.Value, ";")
                size_1d = UBound(arr_1d) - LBound(arr_1d)
                
                Range("CS20") = size_1d
                
                Dim arr_2d() As String
                ReDim arr_2d(size_1d, 1) As String
        
                    For i = 0 To size_1d
                    Dim temp() As String
                    temp = Split(arr_1d(i), ",")
                    Dim size_temp As Integer
                    size_temp = UBound(temp) - LBound(temp) + 1
                    If size_temp = 1 Then
                        arr_2d(i, 0) = Trim(temp(0))
                    ElseIf size_temp = 2 Then
                        arr_2d(i, 0) = Trim(temp(0))
                        arr_2d(i, 0) = Trim(temp(1))
                    End If
        
                    Next i
                
              Range("CS20").Value = arr_2d(1, 0)
                
            End If
            
        Next cell

End Sub

[\code]
 
Upvote 0
I don't know what you mean when you say that it's not giving you the desired result. Did my suggestion address your original error? If so, and if you have a new question, please start a new thread and ask your question there.
 
Upvote 0
I don't know what you mean when you say that it's not giving you the desired result. Did my suggestion address your original error? If so, and if you have a new question, please start a new thread and ask your question there.
ok thank you
 
Upvote 0

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