Count Consecutive Cells Above/Below a Value

chicubs

New Member
Joined
Aug 10, 2016
Messages
8
I am trying to count the consecutive weeks an item is below its average for a given period of time. Not sure how to do this. Item 123 should have an output of 3 and item 1234 should have an output of 1.

[TABLE="width: 500"]
<tbody>[TR]
[TD]Item[/TD]
[TD]10/20[/TD]
[TD]10/27[/TD]
[TD]11/3[/TD]
[TD]11/10[/TD]
[TD]Avg[/TD]
[TD]Consecutive WK Below Avg[/TD]
[/TR]
[TR]
[TD]123[/TD]
[TD]15[/TD]
[TD]8[/TD]
[TD]7[/TD]
[TD]6[/TD]
[TD]9[/TD]
[TD]???[/TD]
[/TR]
[TR]
[TD]1234[/TD]
[TD]15[/TD]
[TD]14[/TD]
[TD]15[/TD]
[TD]8[/TD]
[TD]13[/TD]
[TD]???[/TD]
[/TR]
</tbody>[/TABLE]
 

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That works for items where Column E is a value less than the average. However, it does not return a 0 for items where Column E is above the average. See the link below for the example.

I'm not sure what you mean. I took the example that you posted in post #4 and it seems to work fine. It results in the maximum number of consecutive weeks where the number is higher than the average. Is this not what you are looking for?


Excel 2010
ABCDEFGHIJK
19/17/20169/24/201610/1/201610/8/201610/15/201610/22/201610/29/201611/5/2016
2ItemSales UnitsSales UnitsSales UnitsSales UnitsSales UnitsSales UnitsSales UnitsSales UnitsAvg Sales UnitsConsecutive WK Below Avg
32033352882992342202391941881782486
42007981291281271421431471511501333
Sheet1
Cell Formulas
RangeFormula
K3{=MAX(FREQUENCY(IF(B3:I3B3:I3)),IF(B3:I3>=J3,COLUMN(B3:I3))))}
Press CTRL+SHIFT+ENTER to enter array formulas.
 
Last edited:
Upvote 0
This is what I'm looking for! What formula would I use if I wanted to count the consecutive weeks ABOVE the average?
 
Upvote 0
This is what I'm looking for! What formula would I use if I wanted to count the consecutive weeks ABOVE the average?

Just reverse the inequalities. < becomes > and >= becomes <=.

Formula would then become

=MAX(FREQUENCY(IF(B3:I3>J3,COLUMN(B3:I3)),IF(B3:I3<=J3,COLUMN(B3:I3)))) Ctrl Shift Enter
 
Last edited:
Upvote 0

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