Yongle
Well-known Member
- Joined
- Mar 11, 2015
- Messages
- 6,977
- Office Version
- 365
- Platform
- Windows
Due to a rather woolly first post on this thread ....
my "solution" array formula assumes that there was only one 5229 to be found in the range (C3:I8)
=INDEX(Sheet1!A3:A8,MATCH(1,(Sheet1!C3:C8=5229)*1+(Sheet1!D3:D8=5229)*1+(Sheet1!E3:E8=5229)*1+(Sheet1!F3:F8=5229)*1+(Sheet1!G3:G8=5229)*1+(Sheet1!H3:H8=5229)*1+(Sheet1!I3:I8=5229)*1,0))
Unfortunately that is not what the OP meant and I cannot modify my formula successfully
OP wants
- to find multiple instances of 5229 within range C3:I8 on sheet1
- get the value from column A in same same row
- put the values in column B of sheet4 starting at B2
Hopefully somone can help the OP
thanks
my "solution" array formula assumes that there was only one 5229 to be found in the range (C3:I8)
=INDEX(Sheet1!A3:A8,MATCH(1,(Sheet1!C3:C8=5229)*1+(Sheet1!D3:D8=5229)*1+(Sheet1!E3:E8=5229)*1+(Sheet1!F3:F8=5229)*1+(Sheet1!G3:G8=5229)*1+(Sheet1!H3:H8=5229)*1+(Sheet1!I3:I8=5229)*1,0))
Unfortunately that is not what the OP meant and I cannot modify my formula successfully
OP wants
- to find multiple instances of 5229 within range C3:I8 on sheet1
- get the value from column A in same same row
- put the values in column B of sheet4 starting at B2
Hopefully somone can help the OP
thanks
Last edited: