VBA - Delete entire row if column contains certain text from a specific range of data

spencerp237

New Member
Joined
Feb 24, 2017
Messages
26
Code:
Dim lastRow As Integer


lastRow = Sheets("CustomReport").Cells(Rows.count, 1).End(xlUp).Row


For i = 1 To lastRow


If WorksheetFunction.IsErr(WorksheetFunction.Find(Sheets("CustomReport").Cells(i, 15), Sheets("Sheet8").Range("A2:A" & Sheets("Sheet8").Cells(Rows.count, 1).End(xlUp).Row))) = False Then
    Sheets("CustomReport").Cells(i, 15).EntireRow.Delete
End If


Next i

I am trying to have this macro loop through a data export. It looks in column "O" (15) on the "CustomReport" sheet and checks if it is in the specified range on "Sheet8".

When I run this, I get a "Run-time error'13': Type mismatch" error message.
 

Excel Facts

Spell Check in Excel
Press F7 to start spell check in Excel. Be careful, by default, Excel does not check Capitalized Werds (whoops)
The find formula of worksheet searches a specified letter in a cell.
The find statement searches a spesified letter/number in a range.
You want to know if the text is in a range or not. You can use countif formula, because find statement troublesome if it does not find it.
And when deleting a row, it is usual rule to loop from the bottom.
Hope this helps.

Code:
Sub test1()
Dim i, ws As Worksheet
Dim lastRow As Integer
Dim rng As Range
Set ws = Sheets("Sheet8")
Set rng = ws.Range(ws.Range("A2"), ws.cells(Rows.count, 1).End(xlUp))
With Sheets("CustomReport")
    lastRow = .cells(Rows.count, [COLOR=#ff0000][B]15[/B][/COLOR]).End(xlUp).Row
    For i = lastRow To 1 Step -1
        If WorksheetFunction.CountIf(rng, .cells(i, 15).Value) > 0 Then
            .Rows(i).Delete
        End If
    Next
End With
End Sub
 
Last edited:
Upvote 0
Hi spencerp237,

Try this (though initially on a copy of your data as the results cannot be undone if they're not as expected):

Code:
Option Explicit
Sub Macro2()

    Const lngStartRow As Long = 2 'Starting data row number. Change to suit.
    
    Dim lngMyCol As Long, _
        lngMyRow As Long
    Dim xlnCalcMethod As XlCalculation
            
    With Application
        xlnCalcMethod = .Calculation
        .Calculation = xlCalculationManual
        .ScreenUpdating = False
    End With

    With Sheets("CustomReport")
        lngMyCol = .Cells.Find("*", SearchOrder:=xlByColumns, SearchDirection:=xlPrevious).Column + 1
        lngMyRow = .Cells.Find("*", SearchOrder:=xlByRows, SearchDirection:=xlPrevious).Row
    End With
    
    With Sheets("CustomReport").Columns(lngMyCol)
        With Range(Cells(lngStartRow, lngMyCol), Cells(lngMyRow, lngMyCol))
            .Formula = "=VLOOKUP(CustomReport!O" & lngStartRow & ",Sheet8!A:A,1,FALSE)"
            ActiveSheet.Calculate
            .Value = .Value
        End With
        On Error Resume Next 'Turn error reporting off - OK to ignore 'No cells found' message
            .SpecialCells(xlCellTypeConstants, xlErrors).EntireRow.Delete
        On Error GoTo 0 'Turn error reporting back on
        .Delete
    End With
    
    With Application
        .Calculation = xlnCalcMethod
        .ScreenUpdating = True
    End With

    MsgBox "All rows from Col. O on the ""CustomReport"" tab that were not in the Col. A of ""Sheet8"" have now been deleted.", vbInformation

End Sub

Note as it doesn't loop it's very fast.

Regards,

Robert
 
Last edited:
Upvote 0
Thanks Robert,

Just tried it out and it runs very quickly. However it is deleting a lot more rows than I want it too and I'm not sure why.

Do I need to change the * in the .Find("*") to something?
 
Upvote 0
Takae,

Thank you as well. Yours works great! Knowing that I should loop from the bottom and better understanding of the find formula will definitely help me with other things as well!
 
Upvote 0

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