XMatch Not Returning Expected Result

Jeffrey Mahoney

Well-known Member
Joined
May 31, 2015
Messages
3,212
Office Version
  1. 365
Platform
  1. Windows
I'm a little frustrated with this because I expected to finish an hour ago. So you get my rant.

I have some costs in line with some cells Containing TRUE so I can Use SumIFS to sum the values, but not the summary values for each year. As you can see cell U8 is not TRUE and is a summary column

Now I want to find the first cost in a row that is over zero. I'm using xmatch like this in cell I17:
=XMATCH(0.00001,$I$7:$ET$7*$I$8:$ET$8,1,1)
or
=XMATCH(1e-99,$I$7:$ET$7*$I$8:$ET$8,1,1)
But as you can tell, it returns 17 instead of 12. Cell T7 is definitely a value, not text. Cell T9 shows the same value; it is a formula: =T8*T7

Please take a look

Jeff

ProjectsRegister - Support_4.xlsm
IJKLMNOPQRSTUVWXYZAA
512345678910111213141516171819
6Jan-14Feb-14Mar-14Apr-14May-14Jun-14Jul-14Aug-14Sep-14Oct-14Nov-14Dec-142014Jan-15Feb-15Mar-15Apr-15May-15Jun-15
70.000.000.000.000.000.000.000.000.000.000.006,256,117.536,256,117.530.000.000.0094.000.0036,082.00
8TRUETRUETRUETRUETRUETRUETRUETRUETRUETRUETRUETRUE0TRUETRUETRUETRUETRUETRUE
9000000000006256117.53000094036082
10
1117
Last EAC
Cell Formulas
RangeFormula
I6:EU6I6=SAPHistoryTbl[[#Headers],[Jan-14]:[2024]]
I9:AA9I9=I8*I7
I11I11=XMATCH(0.00001,$I$7:$ET$7*$I$8:$ET$8,1,1)
Dynamic array formulas.
 

Excel Facts

Format cells as currency
Select range and press Ctrl+Shift+4 to format cells as currency. (Shift 4 is the $ sign).
It's returning 17 as that is the nearest value to .00001.
How about
Excel Formula:
=TAKE(FILTER(SEQUENCE(,142),$I$7:$ET$7*$I$8:$ET$8>0),,1)
 
Upvote 0
Solution
MrExcelPlayground13.xlsx
IJKLMNOPQRSTUVWXYZAA
512345678910111213141516171819
6
7000000000006256118625611800094036082
8TRUETRUETRUETRUETRUETRUETRUETRUETRUETRUETRUETRUE0TRUETRUETRUETRUETRUETRUE
9000000000006256118000094036082
10
1117
1212
Sheet25
Cell Formulas
RangeFormula
I9:AA9I9=I8*I7
I11I11=XMATCH(0.00001,$I$7:$ET$7*(--($I$8:$ET$8)),1)
I12I12=MIN(FILTER(SEQUENCE(1,COLUMNS(I7:AA8))*(I7:AA7*I8:AA8>0),SEQUENCE(1,COLUMNS(I7:AA8))*(I7:AA7*I8:AA8>0)>0))
 
Upvote 0
It's returning 17 as that is the nearest value to .00001.
How about
Excel Formula:
=TAKE(FILTER(SEQUENCE(,142),$I$7:$ET$7*$I$8:$ET$8>0),,1)
I haven't worked with TAKE yet, but now it's worth a look. I seen what you did with the sequence to return the series. I removed that and just used the date range above to return the correct date, which was what I wanted the final result to be anyway
=TAKE(FILTER(I6:ET6,$I$7:$ET$7*$I$8:$ET$8>0),,1)

Thank you
 
Upvote 0
Glad we could help & thanks for the feedback.
 
Upvote 0

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