Working code copied BUT i get a RTE13 message now

ipbr21054

Well-known Member
Joined
Nov 16, 2010
Messages
5,752
Office Version
  1. 2007
Platform
  1. Windows
Hi,
I have copied some code & changed the values that will be populated into the list box & column to search etc.

On my userform i have 5 textboxes where each search a specific column.
I also have a listbox.
Example.
TextBoxName i enter a name, listbox is populated, i select a name in the listbox & i am taken to that customer on the worksheet.
The above works for all other textboxes.

My problem is this code ive just copied when i select a name in the listbox i get a RTE13
When i debug it the line of code below is in yellow
I dont understand why all the others work & this one fails as i shouldnt need to alter anything ?
The copied is also supplied.


Rich (BB code):
Private Sub ListBox1_Click()
     Dim rw As Long
     Dim ws As Worksheet
     Dim answer As Integer
     Set ws = ThisWorkbook.Sheets("Database")
    If ListBox1.ListIndex = -1 Then Exit Sub
     rw = ListBox1.List(ListBox1.ListIndex, 3)
     ws.Range("A" & rw).Select
     Unload Me
   answer = MsgBox("OPEN CUSTOMERS FILE IN MAIN DATABASE ?", vbYesNo + vbInformation, "OPEN DATABASE MESSAGE")
   If answer = vbYes Then
 
   Database.LoadData Sheets("DATABASE"), Selection.Row

    Else
    Unload DatabaseSearchForm
    End If
  End Sub

Rich (BB code):
Private Sub TextBoxKeyType_Change()
Me.Label1.Visible = False
Me.Label2.Visible = False
Me.Label3.Visible = False
Me.Label4.Visible = False
TextBoxKeyType = UCase(TextBoxKeyType)
  Dim r As Range, f As Range, cell As String, added As Boolean
  Dim sh As Worksheet
 
  Set sh = Sheets("DATABASE")
  sh.Select
  With ListBox1
    .Clear
    .ColumnCount = 4
    .ColumnWidths = "150;290;130;10"
If TextBoxKeyType.Value = "" Then Exit Sub
    Set r = Range("C6", Range("C" & Rows.Count).End(xlUp))
    Set f = r.Find(TextBoxKeyType.Value, LookIn:=xlValues, LookAt:=xlPart)
    If Not f Is Nothing Then
      cell = f.Address
      Do
        added = False
        For i = 0 To .ListCount - 1
          Select Case StrComp(.List(i), f.Value, vbTextCompare)
            Case 0, 1
          .AddItem f.Value, i
              .List(i, 1) = f.Offset(, -2).Value
              .List(i, 2) = f.Offset(, 13).Value
              .List(i, 3) = f.Offset(, -1).Value
              .List(i, 4) = f.Row
              added = True
              Exit For
          End Select
        Next
        If added = False Then
          .AddItem f.Value
          .List(.ListCount - 1, 1) = f.Offset(, -2).Value
          .List(.ListCount - 1, 2) = f.Offset(, 13).Value
          .List(.ListCount - 1, 3) = f.Offset(, -1).Value
          .List(.ListCount - 1, 4) = f.Row
        End If
        Set f = r.FindNext(f)
      Loop While Not f Is Nothing And f.Address <> cell
      TextBoxSearch = UCase(TextBoxSearch)
      .TopIndex = 0
      Else
      MsgBox "NO ITEM WAS FOUND USING THAT INFORMATION", vbCritical, "DATABASE SHEET ITEM SEARCH"
      TextBoxKeyType.Value = ""
      TextBoxKeyType.SetFocus
    End If
  End With
End Sub
 
Last edited by a moderator:

Excel Facts

What is =ROMAN(40) in Excel?
The Roman numeral for 40 is XL. Bill "MrExcel" Jelen's 40th book was called MrExcel XL.
I don't see a yellow line. Which is your actual code?
In general RTE 13 is Type mismatch, meaning you provide a value of the wrong type, which cannot be converted to the necessary one e.g. you provide a text value where a number is required.
 
Upvote 0

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