What did I do wrong in this probability sheet?

JenniferMurphy

Well-known Member
Joined
Jul 23, 2011
Messages
2,687
Office Version
  1. 365
Platform
  1. Windows
While playing solitaire, I was curious about the odds of 1 or more aces among the 7 initial face-up cards. I created the little table in the mini-sheet below. I then had the solitaire game deal 100 hands and tallied the number of aces in the initial face up cards. That tally is in row 6. Row 7 has what I thought were the expected odds, but there must be an error. They do not add up to 100 (I7 highlighted in yellow). Row 8 has the actual percentages and row 9 has the percentage error.

Can someone tell me where I went wrong? Thanks

Cell Formulas
RangeFormula
H6:H9H6=SUM(D6:G6)
I6:I8I6=SUM(C6:G6)
C7C7=COMBIN(7,7) * ((4/52)^0) * ((48/52)^7)
D7D7=COMBIN(7,1) * ((4/52)^1) * ((48/52)^6)
E7E7=COMBIN(7,2) * ((4/52)^2) * ((48/52)^5)
F7F7=COMBIN(7,3) * ((4/52)^3) * ((48/52)^4)
G7G7=COMBIN(7,4) * ((4/52)^4) * ((48/52)^3)
C8C8=C6/I6
D8D8=D6/I6
E8E8=E6/I6
F8F8=F6/I6
G8G8=G6/I6
C9:G9C9=C8/C7 - 1
C10C10="7,7 = " & COMBIN(7,7)
D10D10="7,1 = " & COMBIN(7,1)
E10E10="7,2 = " & COMBIN(7,2)
F10F10="7,3 = " & COMBIN(7,3)
G10G10="7,4 = " & COMBIN(7,4)
 

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Hello,

Delete C7:G7 and write into C7:
Excel Formula:
=COMBIN(4,SEQUENCE(1,5,0,1))*COMBIN(48,7-SEQUENCE(1,5,0,1))/COMBIN(52,7)
Regards,
Bernd
 
Upvote 0
Solution
Hello,

Delete C7:G7 and write into C7:
Excel Formula:
=COMBIN(4,SEQUENCE(1,5,0,1))*COMBIN(48,7-SEQUENCE(1,5,0,1))/COMBIN(52,7)
Regards,
Bernd
Wow! I get the correct formula and a more compact expression! Very nice. 👏👏👏👍🥰 Thank you.

I think I see why your formula works. It divides the product of the number of aces times the number of non-aces by the possible deals. Correct?

But I don't see why mine fails. The expression I had for 1 ace, =COMBIN(7,1) * ((4/52)^1) * ((48/52)^6), multiplies the odds of 1 ace times the odds of 6 non-aces ties the number of combinations. Any help there?

Thanks
 
Upvote 0
Hello,

Yes, you correctly understand my formula, I think.
Your formulas calculate the probabilities with replacement as you can simulate with this VBA:
VBA Code:
Sub monte()
Const runs = 100000
Dim i As Long, j As Long, n As Long, r(1 To 5) As Long
With Application.WorksheetFunction
Randomize
For i = 1 To runs
    n = 0
    For j = 1 To 7
        If .RandBetween(1, 52) < 5 Then
            n = n + 1
            If n = 4 Then Exit For
        End If
    Next j
    r(1 + n) = r(1 + n) + 1
Next i
Cells(11, 2).Formula = r(1) / runs
Cells(11, 3).Formula = r(2) / runs
Cells(11, 4).Formula = r(3) / runs
Cells(11, 5).Formula = r(4) / runs
Cells(11, 6).Formula = r(5) / runs
End With
End Sub

The correct probabilities without replacement you get if you change the .RandBetween row to
VBA Code:
If .RandBetween(1, 53 - j) < 5 - n Then

Note: Start above simulation with a smaller number of runs (1000 or 10000) if your computer is a bit slow. But then the simulation will be less accurate.

Regards,
Bernd
 
Upvote 0
Hello,

Yes, you correctly understand my formula, I think.
Your formulas calculate the probabilities with replacement . . .
Aha! And that's why they are slightly higher. Thank you. That will give me something to ponder. . .

I should have had you for my probabality and statistics class, but that was quite a few years ago...so maybe it wouldn't have made any difference.

This has been very helpful. Thank you.
 
Upvote 0

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