VBA to find the day number of the year from today's date?

[danbates]

Hi,

Please can someone help me?

I would like a VBA code that can find the day number of the year based from the current date.

Example: today is the 05/10/2019 so I would like the code to return 278. So tomorrow would return 279 and so on.

I have the date in cell T3 if that helps any?

Any help would be appreciated.

Thanks

Dan

 

[AlphaFrog]

Try this...
=TODAY()-DATE(YEAR(TODAY()),1,0)

 

[danbates]

Perfect thank you.

Can I ask, can your code be modified so it can add the following please?

I would like a 9 before the 278 and then 1092 afterwards.

Is that possible?

Thanks again

Dan

 

[AlphaFrog]

This?

="9"&TEXT(TODAY()-DATE(YEAR(TODAY()),1,0),"000")&"1092"

 

[danbates]

Perfect, thank you.

 

[Rick Rothstein]

I would like a VBA code that can find

Try this...
=TODAY()-DATE(YEAR(TODAY()),1,0)

Perfect thank you.

I thought you wanted a VBA solution... is that no longer the case?

 

[danbates]

Hi Rick,

I did, but when AlphaFrog kindly supplied me with a formula I just started recording a macro. I entered the formula in my cell and then I pressed F2 and then enter and that gave me the formula in VBA.

Thanks

Dan

 

[AlphaFrog]

The day number is formatted as three digits; 001, 002, ...365

You could change that to suit.

Declare dn as String if you want a text result, or Long if you want a numeric value.

dn = "9" & Format(Date - DateSerial(Year(Date), 1, 0), "000") & "1092"

 

[Rick Rothstein]

dn = "9" & Format(Date - DateSerial(Year(Date), 1, 0), "000") & "1092"

You can eliminate the concatenations by moving those numbers into the format pattern taking care to put a backslash in front of any 0's that are to remain constant within the pattern...

dn = Format(Date - DateSerial(Year(Date), 1, 0), "90001\092")