VBA Help - See anything wrong with my Copy/Paste Statement? Getting an Error 450

Johnny Thunder

Well-known Member
Joined
Apr 9, 2010
Messages
693
Office Version
  1. 2016
Platform
  1. MacOS
Hi group,

I am working on a piece of code that seemed to work in the past and now I am getting a weird error? "Error 450: Wrong number of arguments or invalid property assignment".


I have marked the line with the error below.

I have tried several variations of the line to see if I could troubleshoot but no luck.

With Sheets("DPL YR2")
.Visible = True
.Unprotect
.Select
.Range("BS58").ClearContents
.Range("A58:BN58").ClearContents
.Range("BS134").ClearContents
.Range("A134:BN134").ClearContents

.Range("P2").FormulaR1C1 = _
"=IF(OR(R1C<=PDACTUALS),0,IF(ABS(SUM(R15C:R165C)-ROUND(SUMIF('CF-LOC'!R11,R1C,'CF-LOC'!R115)*LOADSCALE,2)+ROUND(SUMIF('CF-LOC'!R11,R1C,'CF-LOC'!R128)*LOADSCALE,2))<loadchk1,0,(sum(r15c:r165c)-round(sumif('cf-loc'!r11,r1c,'cf-loc'!r115)*loadscale,2)+round(sumif('cf-loc'!r11,r1c,'cf-loc'!r128)*loadscale,2))))"


.Range("P2").Copy
.Range("T2", "X2", "AB2", "AF2", "AJ2", "AN2", "AR2", "AV2", "AZ2", "BD2", "BH2").Paste <------------------- Getting the error here-----------------------
Application.CutCopyMode = False
.Calculate
End With

Other Variations -

Variation1
Code:
.Range("P2").Copy .Range("T2", "X2", "AB2", "AF2", "AJ2", "AN2", "AR2", "AV2", "AZ2", "BD2", "BH2") '-----Errors out as well

Variation2
Code:
.Range("T2", "X2", "AB2", "AF2", "AJ2", "AN2", "AR2", "AV2", "AZ2", "BD2", "BH2").value = .Range("P2").Value '-----Errors out as well
</loadchk1,0,(sum(r15c:r165c)-round(sumif('cf-loc'!r11,r1c,'cf-loc'!r115)*loadscale,2)+round(sumif('cf-loc'!r11,r1c,'cf-loc'!r128)*loadscale,2))))"
 
Last edited:

Excel Facts

Return population for a City
If you have a list of cities in A2:A100, use Data, Geography. Then =A2.Population and copy down.
i believe in your range, the quotation marks go around the entire contents of the range so for example

instead of
Range("A1","A2","A3")

i think it should be
Range("A1, A2, A3")
 
Upvote 0
With your proposed changes I now get an error, "Run-Time Error 438: Object doesn't support this property or method"

i believe in your range, the quotation marks go around the entire contents of the range so for example

instead of
Range("A1","A2","A3")

i think it should be
Range("A1, A2, A3")
 
Upvote 0
How about
Code:
.Range("P2").Copy .Range("T2, X2, AB2, AF2, AJ2, AN2, Ar2, AV2, AZ2, BD2, BH2")
 
Upvote 0
That did it!

To Nine Zero's defense his comments worked, he just needed to clarify on how to rewrite.

Thanks for the help Fluff!

How about
Code:
.Range("P2").Copy .Range("T2, X2, AB2, AF2, AJ2, AN2, Ar2, AV2, AZ2, BD2, BH2")
 
Upvote 0
Glad we could help & thanks for the feedback
 
Upvote 0
another solution could be to maybe just set the values of those cells to the value of P2

Code:
.Range("T2").Value = .Range("P2").Value
.Range("X2").Value = .Range("P2").Value
.Range("AB2").Value = .Range("P2").Value
.Range("AF2").Value = .Range("P2").Value
.Range("AJ2").Value = .Range("P2").Value
.Range("AN2").Value = .Range("P2").Value
.Range("AR2").Value = .Range("P2").Value
.Range("AV2").Value = .Range("P2").Value
.Range("AZ2").Value = .Range("P2").Value
.Range("BD2").Value = .Range("P2").Value
.Range("BH2").Value = .Range("P2").Value

EDIT: I see you got it working and yeah you are correct, i should have given the whole explanation thanks for the feedback
 
Last edited:
Upvote 0
You can replace this:
Code:
    [COLOR=#333333].Range("P2").Copy[/COLOR]
[COLOR=#333333]    .Range("T2", "X2", "AB2", "AF2", "AJ2", "AN2", "AR2", "AV2", "AZ2", "BD2", "BH2").Paste <------------------- Getting the error here-----------------------[/COLOR]
[COLOR=#333333]    Application.CutCopyMode = False[/COLOR]
with this:
Code:
        For Each cell In .Range("T2, X2, AB2, AF2, AJ2, AN2, AR2, AV2, AZ2, BD2, BH2")
            cell = .Range("P2")
        Next cell
 
Last edited:
Upvote 0
When Nine Zero posted his/her solution you had not modified your op, & so we could only have seen your 2 variations & not the original code.
 
Upvote 0

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