VBA - Google search string in default browser

[spidaman]

Can anyone help with this please?

This VBA project is meant to create a Google search string which opens directly in Google search engine in the users default browser. At the moment the search string is not producing the double speech marks around EACH value (which i want to keep). So if the value entered in the input box is 123456 the search string is: "123456 | 12". I am looking for this: "123456" | "12"

Sub Google_Search_v1()


Dim Target As Variant
Dim LValue1 As String
Dim MyURL As String


MyURL = "https:/google.com/#q="


    Target = Application.InputBox("Enter Number: ")
    
    If Target = 0 Then Exit Sub
    
    LValue1 = """""" & Target & """" & " | " & """" & Left(Target, 2) & """"""
        
    ActiveWorkbook.FollowHyperlink Address:=MyURL & LValue1


End Sub

Any help is much appreciated.
Thanks

 

[BiocideJ]

I believe the corrected line of code is this:

LValue1 = """" & Target & """ | """ & Left(Target, 2) & """"

 

[spidaman]

I believe the corrected line of code is this:

LValue1 = """" & Target & """ | """ & Left(Target, 2) & """"

Thanks for your help, but I'm afraid that hasn't produced the desired result. The string produced in Google search engine was: 123456 | 12

So missing the "......"

 

[BiocideJ]

Thanks for your help, but I'm afraid that hasn't produced the desired result. The string produced in Google search engine was: 123456 | 12

So missing the "......"

So it does. I didn't take into account that the web address has an additional level of text parsing so you basically need to double up all of your quotes.
Also, I noticed that if your Target value has a space that it causes this to also not work. This is the reason I added the Replace(...," ", %20). You may need to add additional replaces if other text characters are truncating the search text.

Here is the TESTED correct line of code:

LValue1 = Replace("""""" & Target & """"""" | """"""" & Left(Target, 2) & """""", " ", "%20")

 

[spidaman]

So it does. I didn't take into account that the web address has an additional level of text parsing so you basically need to double up all of your quotes.
Also, I noticed that if your Target value has a space that it causes this to also not work. This is the reason I added the Replace(...," ", %20). You may need to add additional replaces if other text characters are truncating the search text.

Here is the TESTED correct line of code:

LValue1 = Replace("""""" & Target & """"""" | """"""" & Left(Target, 2) & """""", " ", "%20")

BiocideJ thanks very much for posting this solution; it now works perfectly. Your help is much appreciated.

 

[BiocideJ]

Not a problem. Thanks for confirming it is working.