VBA FormulaARrray (Index w/ Multiple criteria)

acerlaptop

New Member
Joined
Feb 17, 2020
Messages
44
Office Version
  1. 2013
Platform
  1. Windows
Hi,

I have a part here of my VBA code. I don't know what the problem is but the code returns a single result to all the covered ranges. It only returns the result for the first item.

For example:
In column F2 up to F10
All the results returned by the code from F2 to F10 is the result for F2.

VBA Code:
Sheets(strN3).Range("F2:F" & LastRow2).FormulaArray = _
    "=INDEX(HELPER!C[-3],MATCH(1,(HELPER!C[-2]=RC[-3])*(HELPER!C[-1]=RC[-2]),0))"

Any thoughts?

Thanks
 

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How about
VBA Code:
Sheets(strN3).Range("F2").FormulaArray = _
    "=INDEX(HELPER!C[-3],MATCH(1,(HELPER!C[-2]=RC[-3])*(HELPER!C[-1]=RC[-2]),0))"
Sheets(strN3).Range("F2:F" & lastrow2).FillDown
 
Upvote 0
A
How about
VBA Code:
Sheets(strN3).Range("F2").FormulaArray = _
    "=INDEX(HELPER!C[-3],MATCH(1,(HELPER!C[-2]=RC[-3])*(HELPER!C[-1]=RC[-2]),0))"
Sheets(strN3).Range("F2:F" & lastrow2).FillDown
And it's a miracle :) :) :)

Thanks a lot. I've been having problem with that part. Anyway, why does my approach works with FormulaR1C1 but not with FormulaArray?
 
Upvote 0
No idea, I just know that you can't directly populate a range with an array formula, but have to put it in one cell & than fill down.
The same way as you if doing it manually.
 
Upvote 0
No idea, I just know that you can't directly populate a range with an array formula, but have to put it in one cell & than fill down.
The same way as you if doing it manually.
Okay. Thanks a LOT!!! :)
 
Upvote 0
You're welcome & thanks for the feedback
 
Upvote 0
How about
VBA Code:
Sheets(strN3).Range("F2").FormulaArray = _
    "=INDEX(HELPER!C[-3],MATCH(1,(HELPER!C[-2]=RC[-3])*(HELPER!C[-1]=RC[-2]),0))"
Sheets(strN3).Range("F2:F" & lastrow2).FillDown
hI,

Why does this not function when the number of rows is 1?
 
Upvote 0
Because there is nothing to filldown ;)
You can test for it like
VBA Code:
Sheets(strN3).Range("F2").FormulaArray = _
    "=INDEX(HELPER!C[-3],MATCH(1,(HELPER!C[-2]=RC[-3])*(HELPER!C[-1]=RC[-2]),0))"
If lastrow2 > 2 Then Sheets(strN3).Range("F2:F" & lastrow2).FillDown
 
Upvote 0
Because there is nothing to filldown ;)
You can test for it like
VBA Code:
Sheets(strN3).Range("F2").FormulaArray = _
    "=INDEX(HELPER!C[-3],MATCH(1,(HELPER!C[-2]=RC[-3])*(HELPER!C[-1]=RC[-2]),0))"
If lastrow2 > 2 Then Sheets(strN3).Range("F2:F" & lastrow2).FillDown
So that's why. But can I put IF without End If?
 
Upvote 0

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