Dear Excel Wizards,
Currently I have a workbook that I use for record keeping everyday.
There are many columns of data in this workbook, one of which is a date column.
As I find it incredibly cumbersome to individually populate every single cell in each column as I move down the rows, I have some in-cell formulas in several cells that returns certain values based on information that I have to manually insert in cells of certain columns.
For the date column, I am using the =Today() function. However, how do I create a macro that dynamically copies all the latest dates (which is today) and then paste as values to the last cell using an adjacent cell as a marker for the last row, so that when it comes to the next day, the dates are archived in order, and the latest date is reflected in the new row?
Below is an example of some column headers that I have. Thank you!
[TABLE="width: 344"]
<tbody>[TR]
[TD]Auto-Region[/TD]
[TD]Source[/TD]
[TD]Week[/TD]
[TD]Date[/TD]
[/TR]
</tbody>[/TABLE]
Currently I have a workbook that I use for record keeping everyday.
There are many columns of data in this workbook, one of which is a date column.
As I find it incredibly cumbersome to individually populate every single cell in each column as I move down the rows, I have some in-cell formulas in several cells that returns certain values based on information that I have to manually insert in cells of certain columns.
For the date column, I am using the =Today() function. However, how do I create a macro that dynamically copies all the latest dates (which is today) and then paste as values to the last cell using an adjacent cell as a marker for the last row, so that when it comes to the next day, the dates are archived in order, and the latest date is reflected in the new row?
Below is an example of some column headers that I have. Thank you!
[TABLE="width: 344"]
<tbody>[TR]
[TD]Auto-Region[/TD]
[TD]Source[/TD]
[TD]Week[/TD]
[TD]Date[/TD]
[/TR]
</tbody>[/TABLE]