VBA find first non 0 value in range then count how many rows until next non 0 value

VBAhelpplz

New Member
Joined
Mar 24, 2023
Messages
1
Office Version
  1. 365
Platform
  1. Windows
Hi I am at a loss how to do this. I have a range of numbers in the column. Some are 0s and some are not. I need to:

1) find first non 0 value in the range (SaaS column, would correspond to 1/1/24 and $25000
2) count how many rows until next non 0 value in the range (10/1/2024 and $30000)
3) if count is >12 display error
4) do until entire range is checked and there are no instances where the rows with 0s between rows with non-zeros is >12 left. Any help would be greatly appreciated. Here is the data:

1679700180437.png
 

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For example:
VBA Code:
Dim ZnZ, aRan
Dim I As Long, Min0 As Long, nwMin As Long

aRan = Range(Range("F1"), Range("F1").Offset(10000, 0).End(xlUp)).Address   '<<< YOUR Range

ZnZ = Evaluate("(IF(" & aRan & "<>0,ROW(" & aRan & "),99999))")
Min0 = Application.WorksheetFunction.Small(ZnZ, 1)
For I = 2 To UBound(ZnZ)
    nwMin = Application.WorksheetFunction.Small(ZnZ, I)
    Debug.Print nwMin, Min0                                 'Debug only
    If nwMin = 99999 Then Exit For
    If nwMin - Min0 > 12 Then
        '
        '   What to do if delta > 12 ??
        '   nwMin is the row#
        '
        MsgBox (nwMin & " after " & Min0)
        '
    Else
        'anything to do?
    End If
    Min0 = nwMin
Next I
You have to customize the line marked <<< (your range to be examined) and specify what to do when a gap >12 is found, removing the MsgBox I used to report the status
 
Upvote 0
Try
Sub MoreThanTwelve()
Dim M, T&
'Saas range is B2:B30
M = Filter(Evaluate("(transpose(if(B2:B30>0,Row(B2:B30),false))"), False, False)
For T = 1 To UBound(M)
If M(T) - M(T - 1) > 12 Then Range("C" & M(T)) = "Error"
Next T
End Sub
 
Upvote 0

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