VBA Find first instance of word

decadence

Well-known Member
Joined
Oct 9, 2015
Messages
525
Office Version
  1. 365
  2. 2016
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Platform
  1. Windows
Hi, I have a column of data and every cell may or may not contain specific words, what I am trying to do is once the first instance of a word (from an array) is found then insert a column before the data column then exit completely out of the loop without looking in any other cells in the data column, Can someone help with this please. This is what I am using

Code:
Sub InsertByWord()
    '
    Dim RRng as range, oCell as Range, Arr as Variant, k As Integer

    Arr = Array("*Apple*", "*Banana*", "*Orange*")
    Set RRng = ActiveSheet.range("C:C")
    For k = 0 To 2
        For Each oCell In RRng
            If oCell.Value Like Arr(k) Then
                LR = oCell.Row
                    RRng.Offset(0, -1).EntireColumn.Insert
                Exit For
            End If
        Next oCell
    Next k
End Sub
 
Last edited:

Excel Facts

How to fill five years of quarters?
Type 1Q-2023 in a cell. Grab the fill handle and drag down or right. After 4Q-2023, Excel will jump to 1Q-2024. Dash can be any character.
Try this:
Exit Sub
Not Exit Loop

Code:
Sub InsertByWord()
'Modified  7/19/2018  4:16:42 AM  EDT
    Dim RRng As Range, oCell As Range, Arr As Variant, k As Integer
    Arr = Array("*Apple*", "*Banana*", "*Orange*")
    Set RRng = ActiveSheet.Range("C:C")
    For k = 0 To 2
        For Each oCell In RRng
            If oCell.Value Like Arr(k) Then
                LR = oCell.Row
                    RRng.Offset(0, -1).EntireColumn.Insert
                Exit Sub
            End If
        Next oCell
    Next k
End Sub
 
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