jamescooper
Well-known Member
- Joined
- Sep 8, 2014
- Messages
- 840
This is pretty fast, is there any quicker?
Thanks.
Thanks.
Code:
LR = [match(2,1/(l21:l<>""))]
LR = [match(2,1/(l21:l<>""))]
LR = Cells(Rows.Count, "L").End(xlUp).Row
Note that my code and Alan's are doing the same thing. The only difference is I am using Cells(row,column) to refer to the range and he is using Range(...), but that really shouldn't make any difference.Thanks, doesn't appear too much difference in the speed between the 3.