VBA Error - Site change get images links

tactos

New Member
Joined
Jan 6, 2019
Messages
7
I already had one person's help to get the code and I got it working without problems.
Now I think the site has changed and now I can not get results.
Code:
[COLOR=#454545][FONT=&quot][B]Public Function getHeroImage(productUrl As String) As String[/B][/FONT][/COLOR]
[COLOR=#454545][FONT=&quot]
[/FONT][/COLOR]
[COLOR=#454545][FONT=&quot][B]    Dim dom As HTMLDocument[/B][/FONT][/COLOR]
[COLOR=#454545][FONT=&quot][B]    Set dom = New HTMLDocument[/B][/FONT][/COLOR]
[COLOR=#454545][FONT=&quot][B]    With CreateObject("winhttp.winhttprequest.5.1")[/B][/FONT][/COLOR]
[COLOR=#454545][FONT=&quot][B]        .Open "GET", productUrl, False[/B][/FONT][/COLOR]
[COLOR=#454545][FONT=&quot][B]        .send[/B][/FONT][/COLOR]
[COLOR=#454545][FONT=&quot][B]        dom.body.innerHTML = .responseText[/B][/FONT][/COLOR]
[COLOR=#454545][FONT=&quot][B]        getHeroImage = dom.querySelector("div.goodsIntro_largeImgWrap > img").getAttribute("data-zoom")[/B][/FONT][/COLOR]
[COLOR=#454545][FONT=&quot][B]    End With[/B][/FONT][/COLOR]
[COLOR=#454545][FONT=&quot]
[/FONT][/COLOR]
[COLOR=#454545][FONT=&quot][B]End Function[/B][/FONT][/COLOR]
I basically wanted to have the links of the images in a column. The code I was using was as follows:
but now it does not return results.
I've tried changing the selector to:
Code:
[COLOR=#454545][FONT=&quot][B]dom.querySelector ("div.goodsIntro_largeImgWrap> # js-goodsNormalImg> img"). getAttribute ("data-zoom")[/B][/FONT][/COLOR]
but it did not work.
Can someone help please? What have I done wrong to change in the next?
Website I want to get the pictures: https://www.gearbest.com/cell-phones...601631974.html
 

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Re: VBA Eror - Site change get images links

Welcome to the Board

Can you follow the procedure below? It assumes you are using Chrome, but IE is similar.


  • Load the page with your browser.

  • Right click one image you want.
  • Choose the inspect option.
  • At the right pane, the element HTML code will be highlighted.
  • Paste it here, either by typing or as an image.
 
Last edited:
Upvote 0
Re: VBA Eror - Site change get images links

Code:
<img src="https://gloimg.gbtcdn.com/soa/gb/pdm-product-pic/Electronic/2018/11/10/goods_img_big-v1/20181110151249_73645.jpg" data-img="https://gloimg.gbtcdn.com/soa/gb/pdm-product-pic/Electronic/2018/11/10/goods_img_big-v1/20181110151249_73645.jpg" data-gbimg="https://css.gbtcdn.com/imagecache/gbw/img/site/mainDefault.jpg" data-zoom="https://gloimg.gbtcdn.com/soa/gb/pdm-product-pic/Electronic/2018/11/10/source-img/20181110151249_73645.jpg" alt="Xiaomi Mi Note 3 4G Smartphone Versão Internacional" class="goodsIntro_largeImg initial lazy-loaded" id="js-goodsNormalImg" width="500" height="500" data-was-processed="true">
 
Upvote 0
Re: VBA Eror - Site change get images links

Please test this:

Code:
Public Sub GetInfo()
Dim res$, html As HTMLDocument, Elements As Object, i%, j%
With CreateObject("MSXML2.XMLHTTP")
    .Open "GET", "https://www.gearbest.com/cell-phones/pp_009601631974.html", False
    .setRequestHeader "If-Modified-Since", "Sat, 1 Jan 2000 00:00:00 GMT"
    .Send
    res = StrConv(.responseBody, vbUnicode)
End With
Set html = New HTMLDocument
[a:a].ClearContents
With html
    .Body.innerHTML = res
    Set Elements = .getElementsByTagName("img")
    j = 0
    For i = 0 To Elements.Length - 1
        If Not IsNull(Elements(i).getAttribute("src")) Then
            j = j + 1
            Cells(j, 1) = Elements(i).getAttribute("src")
        End If
    Next
    MsgBox j, , "#elements found"
End With
End Sub
 
Upvote 0
Re: VBA Eror - Site change get images links

How i run this?
In the other code i did like that image.
g5artPX


And here give me error like this:
GPTeZIG
 
Upvote 0
Re: VBA Eror - Site change get images links

Please test this:

Code:
Public Sub GetInfo()
Dim res$, html As HTMLDocument, Elements As Object, i%, j%
With CreateObject("MSXML2.XMLHTTP")
    .Open "GET", "https://www.gearbest.com/cell-phones/pp_009601631974.html", False
    .setRequestHeader "If-Modified-Since", "Sat, 1 Jan 2000 00:00:00 GMT"
    .Send
    res = StrConv(.responseBody, vbUnicode)
End With
Set html = New HTMLDocument
[a:a].ClearContents
With html
    .Body.innerHTML = res
    Set Elements = .getElementsByTagName("img")
    j = 0
    For i = 0 To Elements.Length - 1
        If Not IsNull(Elements(i).getAttribute("src")) Then
            j = j + 1
            Cells(j, 1) = Elements(i).getAttribute("src")
        End If
    Next
    MsgBox j, , "#elements found"
End With
End Sub

I already run the code in VBA (green arrow) and give me error.

Print1: https://ibb.co/FHK6kHg
Print2: https://ibb.co/cYYQbL4

Tks for the help
 
Upvote 0
Re: VBA Eror - Site change get images links

To run the code, press ALT + F8 while on the spreadsheet and pick the desired subroutine.
It will write all found elements at column A.
Here at work I cannot see the images, but remember noticing yesterday at home that you were using the code as a worksheet function, would you like that? Are you expecting multiple results from the web query?
 
Upvote 0
I have always used as a function I do not know another reality.
Normally I put about 100 links (all different from this website) in column A. In column B I had the function that returned the links of the images.
Even so you are giving an error:
Compile Error:
User-defined type not defined

Print error: https://ibb.co/Tb2Xpkq
 
Upvote 0
o Add a reference to the Microsoft HTML object library at VBE > tools > references

The function below will return the first element. If you need multiple results, we will need a subroutine or an array formula.

Code:
Public Function GetInfo$(w$)
Dim res$, html As HTMLDocument, Elements As Object
With CreateObject("MSXML2.XMLHTTP")
    .Open "GET", w, False
    .setRequestHeader "If-Modified-Since", "Sat, 1 Jan 2000 00:00:00 GMT"
    .Send
    res = StrConv(.responseBody, vbUnicode)
End With
Set html = New HTMLDocument
GetInfo = "Null"
With html
    .Body.innerHTML = res
    Set Elements = .getElementsByTagName("img")             ' your tag here
    ' your attribute here
    If Not IsNull(Elements(0).getattribute("src")) Then _
    GetInfo = Elements(0).getattribute("src")
End With
End Function
 
Upvote 0

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