VBA Duplicates in a group based on 2 columns

Stephen_IV

Well-known Member
Joined
Mar 17, 2003
Messages
1,177
Office Version
  1. 365
  2. 2019
Platform
  1. Windows
Good afternoon,

I have data based on 2 columns column B and E. What I would like to do is to highlight the group in yellow if the name and the DOB match. For instance AAAA and DDDD would be highlighted in this example.

Thanks in advance!!!!!


Rich (BB code):
<style type="text/css">
	table.tableizer-table {
		font-size: 12px;
		border: 1px solid #CCC ; 
		font-family: Arial, Helvetica, sans-serif;
	} 
	.tableizer-table td {
		padding: 4px;
		margin: 3px;
		border: 1px solid #CCC ;
	}
	.tableizer-table th {
		background-color: #104E8B ; 
		color: #FFF ;
		font-weight: bold;
	}
</style>
<table class="tableizer-table">
<thead><tr class="tableizer-firstrow"><th></th><th>NAME</th><th> </th><th> </th><th>DOB</th></tr></thead><tbody>
 <tr><td> </td><td> </td><td> </td><td> </td><td> </td></tr>
 <tr><td> </td><td>AAAA</td><td> </td><td> </td><td>7/6/2011</td></tr>
 <tr><td> </td><td>AAAA</td><td> </td><td> </td><td>7/6/2011</td></tr>
 <tr><td> </td><td> </td><td> </td><td> </td><td> </td></tr>
 <tr><td> </td><td>BBBB</td><td> </td><td> </td><td>10/26/1987</td></tr>
 <tr><td> </td><td>BBBB</td><td> </td><td> </td><td>10/18/1991</td></tr>
 <tr><td> </td><td>BBBB</td><td> </td><td> </td><td>10/22/2000</td></tr>
 <tr><td> </td><td> </td><td> </td><td> </td><td> </td></tr>
 <tr><td> </td><td>CCCC</td><td> </td><td> </td><td>10/3/2002</td></tr>
 <tr><td> </td><td>CCCC</td><td> </td><td> </td><td>8/15/2006</td></tr>
 <tr><td> </td><td> </td><td> </td><td> </td><td> </td></tr>
 <tr><td> </td><td>DDDD</td><td> </td><td> </td><td>8/7/2002</td></tr>
 <tr><td> </td><td>DDDD</td><td> </td><td> </td><td>8/7/2002</td></tr>
 <tr><td> </td><td> </td><td> </td><td> </td><td> </td></tr>
 <tr><td> </td><td>EEEE</td><td> </td><td> </td><td>6/27/1994</td></tr>
 <tr><td> </td><td>EEEE</td><td> </td><td> </td><td>4/15/1995</td></tr>
 <tr><td> </td><td>EEEE</td><td> </td><td> </td><td>12/31/1989</td></tr>
</tbody></table>
 

Excel Facts

Show numbers in thousands?
Use a custom number format of #,##0,K. Each comma after the final 0 will divide the displayed number by another thousand
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[TD]name[/TD]
[TD]dob[/TD]
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[TD]aaaa[/TD]
[TD="align: right"]01/08/1994[/TD]
[TD]x[/TD]
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[TD]aaaa[/TD]
[TD="align: right"]01/08/1994[/TD]
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[TD]bbbb[/TD]
[TD="align: right"]02/08/1993[/TD]
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[TD]bbbb[/TD]
[TD="align: right"]03/07/1994[/TD]
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[TD]cccc[/TD]
[TD="align: right"]05/08/1990[/TD]
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[TD="align: right"]05/08/1990[/TD]
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[TD="colspan: 4"]rows marked x have been coloured by this[/TD]
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[TD="colspan: 3"]conditional formatting formula[/TD]
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[TD="colspan: 2"]cell A4 (the first aaaa)[/TD]
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[TD="colspan: 10"]=OR(AND(A4=A5,B4=B5),AND(A5="",B5="",A4=A3,B4=B3),AND(A3="",B3="",A4=A5,B4=B5))=TRUE[/TD]
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[TD="colspan: 5"]the bbbb's have not because the date is different[/TD]
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Upvote 0
Hi oldbrewer for replying but I am looking for a VBA approach. If anyone can help. Thanks!
 
Upvote 0
This assumes your headers are in row 1 and first group name is in B3.
Code:
Sub Steohen_IV()
Dim Ar As Range
Application.ScreenUpdating = False
For Each Ar In Range("B3:E" & Cells(Rows.Count, "E").End(xlUp).Row).SpecialCells(xlCellTypeConstants).Areas
    If Application.CountIf(Ar.Columns(1), Ar.Cells(1, 1)) = Ar.Rows.Count And Application.CountIf(Ar.Columns(4), Ar.Cells(1, 4)) = Ar.Rows.Count Then
        Ar.Interior.Color = vbYellow
    End If
Next Ar
Application.ScreenUpdating = True
End Sub
 
Upvote 0
Thanks JoeMo,

That seems to do the trick. Much appreciated.
 
Upvote 0

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