VBA Collection - Changing Value of a Collection Item

HedgePig

Board Regular
Joined
Jun 27, 2002
Messages
146
Hello

I want to count the number of occurences of each unique value of a certain field I'm reading in. I don't know in advance what those unique values will be, so I thought I'd use collections rather than an array. I've set up two collection objects. The first simply has the field's value (of type string) added each time a new value is detected. The second stores a count of the number of occurences of that value. But I don't seem to be able to be able to change the value of this object within the collection. I guess I could delete it from the collection and then add it back in with value increased by one but that seems very clunky.

Do I just have the syntax wrong or am I trying to do something impossible. The last line of the code below generates a "Run-time error 424 - Object required"

Any suggestions?

Thanks
HedgePig

Code:
Dim SummaryCount as New Collection
Dim i as Long
Dim idxstr as String
.....

i =0
SummaryCount.Add i, key:=idxstr

.......
SummaryCount(idxstr) = SummaryCount(idxstr) + 1
'Produces an Error
 

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Hi

Here's an approach similar to yours that uses collections.

Create a new class module (insert Class Module) and insert the following

Public counta As Integer
Public item As String

Leave it as the default name of Class1.

You will have to adapt the following to cover your field readin process but hopefully you should get the idea.

Code:
Sub ccc()
 Dim nodupes As New Collection
 
 For Each ce In Range("a1:a9")
  Dim nodup As New Class1
  tester = ""
  On Error Resume Next
  tester = nodupes(ce.Value).item
  On Error GoTo 0
  If tester = "" Then
    nodup.counta = 1
    nodup.item = ce.Value
    nodupes.Add item:=nodup, key:=ce.Value
  Else
    nodup.counta = nodupes(ce.Value).counta + 1
    nodup.item = ce.Value
    nodupes.Remove (ce.Value)
    nodupes.Add item:=nodup, key:=ce.Value
 End If
  Set nodup = Nothing

 Next ce
 
 For Each ce In nodupes
   MsgBox ce.item & ", " & ce.counta
 Next ce
End Sub

I had the following data in the range A1:A9 (a,a,a,a,b,b,b,c,d). The results output were

a, 4
b, 3
c, 1
d, 1

HTH

Tony
 
Upvote 0
Thanks for your post, Tony!

I like your idea of keeping everything (description and value) in one class, rather than maintaining two collections. However, you still have to remove the item from a collection to update and then add it back in again. I'd much prefer being able to directly update the object in the collection as I suspect this would be much quicker (although I may be wrong). So, do you know if there is anyway to directly access and alter an object while it's still part of a collection?

HedgePig
 
Upvote 0
"Run-time error 424 - Object required" Your are saving a value type, not an object type. VB collections are read only. They only "collect" and do not expose their own "value" property. However, for a reference type that contains write-access properties, you can overcome this limitation. In essence, the reference to your object is read-only but not the properties of the object being referenced. This may seem like a lot of overhead creating custom objects but it is not and will produce code that is much easier to read and maintain. The first example is for explanation only. See the code comments. See the second example for a better way to solve your problem using a custom made object. The following examples are for illustration only.

CustomTypeInCollection.zip

Both of the following examples use a custom class created by adding a class module and adding this line of code. Name this class "MyCustomType".

<table border="1" bgcolor="White"><caption ALIGN=left><font size="2" face=Courier New>Example VBA Code:</FONT></caption><tr><td><font size="2" face=Courier New>  <font color="#0000A0">Public</font> FieldCount <font color="#0000A0">As</font> <font color="#0000A0">Long</font>
</FONT></td></tr></table>

<table border="1" bgcolor="White"><caption ALIGN=left><font size="2" face=Courier New>Example VBA Code:</FONT></caption><tr><td><font size="2" face=Courier New>  <font color="#0000A0">Sub</font> Example()
       <font color="#0000A0">Dim</font> SummaryCount <font color="#0000A0">As</font> <font color="#0000A0">New</font> Collection
       <font color="#0000A0">Dim</font> idxstr <font color="#0000A0">As</font> <font color="#0000A0">String</font>
      
      <font color="#008000"> 'add three custom object that contain a single</font>
      <font color="#008000"> 'public property, 1 as Long</font>
      <font color="#008000"> 'assign 1, 2, and 3</font>
       idxstr = "Key1"
       SummaryCount.Add GetInstance(1), key:=idxstr
       idxstr = "Key2"
       SummaryCount.Add GetInstance(2), key:=idxstr
       idxstr = "Key3"
       SummaryCount.Add GetInstance(3), key:=idxstr
      
      <font color="#008000"> 'output 1, 2, 3</font>
       <font color="#0000A0">Debug.Print</font> SummaryCount("Key1").FieldCount
       <font color="#0000A0">Debug.Print</font> SummaryCount("Key2").FieldCount
       <font color="#0000A0">Debug.Print</font> SummaryCount("Key3").FieldCount
      
      <font color="#008000"> 'add the custom objects value to it'self</font>
       SummaryCount("Key1").FieldCount = SummaryCount("Key1").FieldCount + 1
      <font color="#008000"> 'assign a value straight-away</font>
       SummaryCount("Key2").FieldCount = 3
      <font color="#008000"> 'assign a value straight-away</font>
       SummaryCount("Key3").FieldCount = 4
      
      <font color="#008000"> 'output 2, 3, 4</font>
       <font color="#0000A0">Debug.Print</font> SummaryCount("Key1").FieldCount
       <font color="#0000A0">Debug.Print</font> SummaryCount("Key2").FieldCount
       <font color="#0000A0">Debug.Print</font> SummaryCount("Key3").FieldCount
  
  <font color="#0000A0">End</font> <font color="#0000A0">Sub</font>
  
  <font color="#0000A0">Private</font> <font color="#0000A0">Function</font> GetInstance(Value <font color="#0000A0">As</font> Long) <font color="#0000A0">As</font> MyCustomType
       <font color="#0000A0">Set</font> GetInstance = <font color="#0000A0">New</font> MyCustomType
       GetInstance.FieldCount = Value
  <font color="#0000A0">End</font> <font color="#0000A0">Function</font>
  
</FONT></td></tr></table>

<table border="1" bgcolor="White"><caption ALIGN=left><font size="2" face=Courier New>Example VBA Code:</FONT></caption><tr><td><font size="2" face=Courier New>  <font color="#0000A0">Sub</font> Example2()
  
       <font color="#0000A0">Dim</font> SummaryCount <font color="#0000A0">As</font> <font color="#0000A0">New</font> Collection
  
       AddField "Field_Item_1", SummaryCount
       AddField "Field_Item_1", SummaryCount
       AddField "Field_Item_1", SummaryCount
      
       AddField "Field_Item_2", SummaryCount
       AddField "Field_Item_2", SummaryCount
      
       AddField "Field_Item_3", SummaryCount
      
      <font color="#008000"> '3 occurrences</font>
       <font color="#0000A0">Debug.Print</font> SummaryCount("Field_Item_1").FieldCount
      <font color="#008000"> '2 occurrences</font>
       <font color="#0000A0">Debug.Print</font> SummaryCount("Field_Item_2").FieldCount
      <font color="#008000"> '1 occurrences</font>
       <font color="#0000A0">Debug.Print</font> SummaryCount("Field_Item_3").FieldCount
  
  <font color="#0000A0">End</font> <font color="#0000A0">Sub</font>
  
  <font color="#0000A0">Private</font> <font color="#0000A0">Function</font> AddField(Field <font color="#0000A0">As</font> String, c <font color="#0000A0">As</font> Collection) <font color="#0000A0">As</font> MyCustomType
       <font color="#0000A0">On</font> <font color="#0000A0">Error</font> <font color="#0000A0">Resume</font> <font color="#0000A0">Next</font>
       <font color="#0000A0">Set</font> AddField = c(Field)
       <font color="#0000A0">If</font> AddField <font color="#0000A0">Is</font> <font color="#0000A0">Nothing</font> <font color="#0000A0">Then</font>
           <font color="#0000A0">Set</font> AddField = <font color="#0000A0">New</font> MyCustomType
           AddField.FieldCount = 1
           c.Add AddField, Field
       <font color="#0000A0">Else</font>
           AddField.FieldCount = AddField.FieldCount + 1
       <font color="#0000A0">End</font> <font color="#0000A0">If</font>
  <font color="#0000A0">End</font> <font color="#0000A0">Function</font>
</FONT></td></tr></table>
 
Upvote 0
Thanks Right_Click! Your explanation "In essence, the reference to your object is read-only but not the properties of the object being referenced." is very helpful and your solution is exactly what I was looking for.

Interesting that this can be done with custom objects but not native types (integer, string, etc)

Many thanks again for the solution. It's precisely what I needed to know.

HedgePig
 
Upvote 0
HedgePig

The code from Right_Click prompted me. You can use my approach without the adding and removing entries in the collection. I did a quick test on approx 20000 records and the difference was about 1 second between the 2 methods.

Code:
Sub ccc()
 starttime = Now()
 
 Dim nodupes As New Collection
  
 For Each ce In Range("a1:a20000")
  Dim nodup As New Class1
  tester = ""
  On Error Resume Next
  tester = nodupes(ce.Value).item
  On Error GoTo 0
  If tester = "" Then
    nodup.counta = 1
    nodup.item = ce.Value
    nodupes.Add item:=nodup, key:=ce.Value
  Else
    'nodup.counta = nodupes(ce.Value).counta + 1
    'nodup.item = ce.Value
    'nodupes.Remove (ce.Value)
    'nodupes.Add item:=nodup, key:=ce.Value
    nodupes(ce.Value).counta = nodupes(ce.Value).counta + 1
 End If
  Set nodup = Nothing

 Next ce
  
 For Each ce In nodupes
   MsgBox ce.item & ", " & ce.counta
 Next ce
  
End Sub


Tony
 
Upvote 0
Hello Tony

Thanks for that post. Actually it's pretty much exactly what I did after reading Right_Click's reply! Using this approach, it's easy to slot in any new "item" in alphabetic order which is nice.

I didn't time the differences between the two approaches though - interesting that there's not much time difference. I'm running through about 350,000 records in just over 30 seconds and it's not the newest of PC's, so it's pretty quick.

Thanks again
HedgePig
 
Upvote 0

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