VBA Code for split text based on variable length and replace

Jackyk1994

New Member
Joined
Jul 16, 2024
Messages
5
Office Version
  1. 365
Platform
  1. Windows
Hi everyone, I have a batch of data at column A starting at A3 and I call them “cell.value”

In short, I need to use semicolons to separate my data and replace in the same cell, but I may need to separate multiple times in the same cell.

Raw data example:

PRODUCT0105ABCDE0201L0302AD
PRODUCT0103IPC0201D0303AUS
PRODUCT0106QWERTY0201D0405ASDFG


I want the result to be replaced by:

PRODUCT;0105ABCDE;0201L;0302AD
PRODUCT;0103IPC;0201D;0303AUS
PRODUCT;0106QWERTY;0201D;0405ASDFG

Criteria:

1.“PRODUCT” is always here
2.Each phase is starting with 01-30 which is column name such as product id, no analysis at this stage but fixed 2 length and not all column is mandatory
3.After the 01-30 column name, we have a variable length here, for “0105ABCDE”, 01 is column name no analysis, 05 is the length of the column value which is “ABCDE” and fixed 2 length
4.Pattern is always the same 2 + 2 length fixed + variable length
5.Need to replace at same cell, can’t open new column

Thanks for your help.
 

Excel Facts

Which lookup functions find a value equal or greater than the lookup value?
MATCH uses -1 to find larger value (lookup table must be sorted ZA). XLOOKUP uses 1 to find values greater and does not need to be sorted.
I wonder how representative your sample data above is? If that data is what all your data is like, then another way of looking at the criteria is to put a semicolon after every letter that is followed immediately by a digit. If that is the case then you could try this code with a copy of your data.

VBA Code:
Sub InsertSemiColons()
  Dim RX As Object
  Dim a As Variant
  Dim i As Long
  
  Set RX = CreateObject("VBScript.RegExp")
  RX.Global = True
  RX.Pattern = "([A-Z])(\d)"
  With Range("A3", Range("A" & Rows.Count).End(xlUp))
    a = .Value
    For i = 1 To UBound(a)
      a(i, 1) = RX.Replace(a(i, 1), "$1;$2")
    Next i
   .Value = a
  End With
End Sub

Before:
Jackyk1994.xlsm
A
1
2
3PRODUCT0105ABCDE0201L0302AD
4PRODUCT0103IPC0201D0303AUS
5PRODUCT0106QWERTY0201D0405ASDFG
6
Sheet1


After:
Jackyk1994.xlsm
A
1
2
3PRODUCT;0105ABCDE;0201L;0302AD
4PRODUCT;0103IPC;0201D;0303AUS
5PRODUCT;0106QWERTY;0201D;0405ASDFG
6
Sheet1
 
Upvote 0
I wonder how representative your sample data above is? If that data is what all your data is like, then another way of looking at the criteria is to put a semicolon after every letter that is followed immediately by a digit. If that is the case then you could try this code with a copy of your data.

VBA Code:
Sub InsertSemiColons()
  Dim RX As Object
  Dim a As Variant
  Dim i As Long
 
  Set RX = CreateObject("VBScript.RegExp")
  RX.Global = True
  RX.Pattern = "([A-Z])(\d)"
  With Range("A3", Range("A" & Rows.Count).End(xlUp))
    a = .Value
    For i = 1 To UBound(a)
      a(i, 1) = RX.Replace(a(i, 1), "$1;$2")
    Next i
   .Value = a
  End With
End Sub

Before:
Jackyk1994.xlsm
A
1
2
3PRODUCT0105ABCDE0201L0302AD
4PRODUCT0103IPC0201D0303AUS
5PRODUCT0106QWERTY0201D0405ASDFG
6
Sheet1


After:
Jackyk1994.xlsm
A
1
2
3PRODUCT;0105ABCDE;0201L;0302AD
4PRODUCT;0103IPC;0201D;0303AUS
5PRODUCT;0106QWERTY;0201D;0405ASDFG
6
Sheet1
Thanks for your help.
But unfortunately, my cell values contain different types of format suchas number and text. Can't put a semicolon at the beginning of letter
 
Upvote 0
Hi everyone, I have a batch of data at column A starting at A3 and I call them “cell.value”

In short, I need to use semicolons to separate my data and replace in the same cell, but I may need to separate multiple times in the same cell.

Raw data example:

PRODUCT0105ABCDE0201L0302AD
PRODUCT0103IPC0201D0303AUS
PRODUCT0106QWERTY0201D0405ASDFG


I want the result to be replaced by:

PRODUCT;0105ABCDE;0201L;0302AD
PRODUCT;0103IPC;0201D;0303AUS
PRODUCT;0106QWERTY;0201D;0405ASDFG

Criteria:

1.“PRODUCT” is always here
2.Each phase is starting with 01-30 which is column name such as product id, no analysis at this stage but fixed 2 length and not all column is mandatory
3.After the 01-30 column name, we have a variable length here, for “0105ABCDE”, 01 is column name no analysis, 05 is the length of the column value which is “ABCDE” and fixed 2 length
4.Pattern is always the same 2 + 2 length fixed + variable length
5.Need to replace at same cell, can’t open new column

Thanks for your help.
Add Raw data example:

PRODUCT0105ABCDE0201L0302AD
PRODUCT0103IPC0201D0303AUS
PRODUCT0106QWERTY0201D0405ASDFG
PRODUCT0104ABCD0201E090827072024


I want the result to be replaced by:

PRODUCT;0105ABCDE;0201L;0302AD
PRODUCT;0103IPC;0201D;0303AUS
PRODUCT;0106QWERTY;0201D;0405ASDFG
PRODUCT;0104ABCD;0201E;090827072024
 
Upvote 0
2.Each phase is starting with 01-30 which is column name such as product id, no analysis at this stage but fixed 2 length and not all column is mandatory
Perhaps,
Code:
Sub test()
    Dim a, i&
    With Range("a1", Range("a" & Rows.Count).End(xlUp))
        a = .Resize(, 2).Value
        With CreateObject("VBScript.RegExp")
            .Global = True
            .Pattern = "([A-Z])((0[1-9]|[1-2][0-9]|30)\d{2})"
            For i = 1 To UBound(a, 1)
                a(i, 1) = .Replace(a(i, 1), "$1;$2")
            Next
        End With
        .Value = a
    End With
End Sub
 
Upvote 0
unfortunately, my cell values contain different types of format suchas number and text. Can't put a semicolon at the beginning of letter
My suggestion does not put a semicolon at the beginning of letter, it puts it between letter and following digit which is what all your examples in post #1 and all your examples in post #4 have.
  1. Did you try the code?
  2. If my code does not do what you want then please give some sample data and expected results where my code does not work.
 
Upvote 0

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